You will need to use differentiation to do so. So differentiate y, then set this function = 0 then solve for x, this will give you the x value for the minimum/maximum
Not quite, 14x - 3 as you must treat both terms separately, so by multiplying by the power and reducing it by one would make 7x^2 into 14x And -3x or -3x^1 would differentiate into -3
this is great but im still a bit lost, im trying to look at y = 7x^2 - 3x how do i find the co ordinates and maxlimu / min
You will need to use differentiation to do so. So differentiate y, then set this function = 0 then solve for x, this will give you the x value for the minimum/maximum
@@ImStuckRevision ok so would that be 2(7x^1 - 3x)
Not quite, 14x - 3 as you must treat both terms separately, so by multiplying by the power and reducing it by one would make 7x^2 into 14x
And -3x or -3x^1 would differentiate into -3
@@ImStuckRevision ok i think i see what you mean, so does this answer give you the turning point? then i have to go on to find max and minima
Yes the turning points are also minimum and maximum. To find out if they are either minimum or maximum you must differentiate again.