Predicting the Products of Chemical Reactions
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- Опубліковано 7 лис 2023
- Predicting the products of chemical reactions involves understanding the type of reaction occurring and as well as being able to determine ionic charge. Here, I'll focus on single replacement, double replacement, and combustion reactions. These are the main types you'll need to be able to predict the products for. In another video I'll cover combination and decomposition reactions.
Note that the equations in this video are not necessarily balanced!
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***(Single Replacement Reactions****
Metal Replacing Metal:
Use the activity series to determine if a metal can replace another metal in a compound. Metals higher in the activity series can displace metals lower in the series.
For example, if you have zinc (Zn) and copper sulfate (CuSO4), you can consult the activity series to see if Zn can replace Cu. If it can, the reaction might proceed as follows:
Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s)
b. Metal Reacting with an Acid:
Similarly, use the activity series to see if a metal can replace hydrogen in an acid. If the metal is higher in the activity series than hydrogen, a reaction will occur.
For example, with hydrochloric acid (HCl) and zinc (Zn), the reaction would be:
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
****Double Replacement Reactions****
Precipitation Reaction:
Consult a solubility table to determine if the products will form a solid (precipitate). If the combination of ions results in an insoluble compound, a precipitation reaction occurs.
For example, if you mix silver nitrate (AgNO3) and sodium chloride (NaCl), the reaction would be:
AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
Neutralization Reaction:
When an acid reacts with a base, a neutralization reaction occurs, forming water and a salt.
For example, in the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH):
HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq)
****Combustion Reactions****
Combustion reactions involve a substance reacting with oxygen to produce carbon dioxide and water. For hydrocarbons, like in the combustion of methane (CH4):
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
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I have a chem test tmrw and this helped me stop pissing my pants uncontrollably. Thank you Wayne.
All the best on your chem test!
The background vid for the intro was so cool!! The man, the myth, the legend continues to strike again & again!
Thanks, Nick. Here's the full video for the reaction. It's one of my favorites!
the only thing thats getting me through chem right now. THANK YOU!!!
This is the best video Ive seen explaining this. thank you so much
You are helping so much!
Oxidation was so hard for me to learn once I watched your videos its my faviroute chapter now
That is great to hear!
You have no idea how much this helped me… so thank you :)
Happy to help!
This is super helpful
Sir Please make a video on basics of chemistry
I'll put it on my list!
Thank you very much 👍🏼👍🏼
Welcome 😊
Thanks sir
Welcome!
Bro has Fr saved me
🎉😊 first
Nice!
Hello sir
Can you teach us Organic chemistry, i am.facing difficulties in it .
It will very helpfull for me as well as for my fellow classmates belonging to class 10th
I've done some naming for alkanes and such but really haven't done much organic chem. it's on my list!
Good morning sir
Good afternoon. I think I saw you on the livestream last night, yes?
@@wbreslyn yes sir and now it's 12:45 AM here in India
What aq mean?
aqueous
@@it.s_Raine yes I knw the word in full but what does it mean? Like pls define it for me🤗
@@undjizuvakaijere4519 Aqueous is a term used to define a system that involves water. The word aqueous is also applicable to describe a solution or mixture in which water is the solvent. A substance will form an aqueous solution or not, it depends on the nature of its chemical bonds.
For example, a solution of table salt, also known as sodium chloride (NaCl), in water would be represented as Na+(aq) + Cl−(aq). The word aqueous (which comes from aqua) means pertaining to, related to, similar to, or dissolved in, water.
I learnt nothing because at no point was there any discussion of WHY.
thxxxxxxxx
No problem!