How to Find Argument of Complex Number (Hindi) - Part 1 | NCERT 11 Class Maths
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- Опубліковано 19 сер 2024
- In this video tutorial you will learn how to find argument of complex number of NCERT 11 th class maths in Hindi.
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Legends watching this video just before term 1 exam because they are offline 😂😂😂😂😂😂
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Thanku so much sir.....yu have clear my doubt🥰🥰
Thankyou sir because of you I learnt the concept very easily and now I can solve the problems.you are best teacher.😃
Tomorrow is my exam and i am watching video today 😂😂
It's very helpful.
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Thank you sir🙏🙏😃
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I dont understand a single hindi, but such a clear explaination
Really?
I don't understand your single English
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1 day before exam .
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It is very usefull basic for me thanks sir
Thanks alot sir I was having problem related to this topic now my all doubts are clear
Sir, everything is good, but you should not say that 'tan' & 'tan' are cancelled then we can get alpha=theta. Though you say the inverse method, I think that you shouldn't say that those are cancelled. OVERALL! THANK YOU FOR SUCH A GOOD VIDEO 😊
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Thank you very much for understanding a complex
Thing in a very simple way
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Sapna number do
Bahut hi accha bataya ek baar me samajh aagaya thanku sir🙏
Sir aapke Video bohot he important hota hai sir 👍
Sir how u converted alpha √3 into π/3?? Plzz explain me this???
I also want to know this
@@neelamvarshney5793 mreko pta lg gya bhai... Bta du aapko?
Pie/3=60degree and tan 60=root3
Hope u understand😊😊
Also watch my vedios on Complex numbers ( Full explain with easy concept)
Please Subscribe My channel
#UA-camrStudy
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It was very helpful.thank u sir
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Sir very good explanation for beginners.Thank you sir.
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bahut Help mila Thanks sir
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Good explanation
I'm seeing this video 1 hour before exam
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Sir kya IV quadrant me minus alpha ki jagah 2π minus alpha li jasakti hai
Yes
No coz argument π se jyada ho jayega phir
yes
Outstanding explanation by sir
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Waiting 2 hr before exam 😅
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Now it is clear to me
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Sir argZ1 is 2+root3 then thita=?
Thank u... Nicely explained! 🙂🙂
my all doubts are cleared..!
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In 3 quad it's pi plus alpha , if I takeur choice as u take in video it will uh argument bt we find principal argument only ....Nd relation is argument =principal argument + 2nπ...
Sir your this video is very useful for me
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Legend people watching before 1 hour of examination
Me
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Aapki teaching bahut aachi hain
sir value of π greater than 180• what to do
I have to find polar form of -1-i
Let
tanα = |y/x|
tanα=|(-1)/(-1)| = 1 = tan(pi/4)
α = pi/4
since (-1,-1) lies in 3 quad so
θ = α-pi
= pi/4 - pi ( since α = pi/4)
= -3pi/4 (after simplifying)
Very good explanation sir
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Sir aapne ab video daalni band kyu kr di aap bahut acha padhate hn
Hey brother tan π/6 lies in which quadrant
Tan pi/6 is 1/root 3 its a value
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Thank you so much sir. You explained very well..
How can we convert tan 60 into π/3
Pls explain
Go and search degrees into radians..
Multiply the angle given in degrees by π/180
@@tanu167 shi bola ye to bataya he nhi
very very nice video.thanks sir......
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