I love how you explain this whole thing, and at the end give us a good conclusion so we don't have to do the calculating every time. We can just know the result while knowing how it works. Thanks a lot !!!
I am studying solid-state physics which requires me to understand the convolution with a delta function. Your short but pithy exposition helped me get around it. Thanks very much.
When h(alpha) is shifted in alpha axis by say Alpha0 amount, where will the final waveform shifted to after convultion with delta function delta (tau-4)?
Wonderful explanations on your channel...easy to understand...thank u very much sir, for your effort to help students all around the world. I am from Sri Lanka. One love.
The function needs to be evaluated for all values of t. So you could start with a positive value if you like, but you will also need to consider the negative values at some point. Most people prefer to start with the most negative values and then consider increasingly positive (less negative) values of t.
i have a question. What if we were to take the convolution of a sin function for example and a delta function with no shift. Would the convolution just be the original sin function?
It's not flipped at the end. That is the output of the convolution. If anything, the earlier functions can be viewed as having been "flipped" - but I prefer not to think about "flipping" any functions. I prefer to consider the exact functions, as the maths specifies. This video might help: "Convolution in 5 Easy Steps" ua-cam.com/video/aMaw4EumwyE/v-deo.html
Thank you.. I've looked every where to find answer for my question but couldn't find it.. I'm trying to understand when laplace transfor of delta function is F(s)=1 ..how I can plot this 1 on the s domain graph ? Is that number on the real part alpha (decays) or on the imaginary part (jw) ?
For a delta function, F(s)=1 for all s. That means the function equals 1 everywhere over "the s-plane". Perhaps this video will help with the visualisation: "How do Poles and Zeros affect the Laplace Transform and the Fourier Transform?" ua-cam.com/video/iP4fckfDNK8/v-deo.html
Not sure what point you're making, sorry. Why do you use a capital letter for the first "X"? Normally we use the capital letter for representing the signal in the frequency domain. If your first letter was a lower case, then yes, your equation would be correct.
Have you tried watching my video that explains what convolution is? It might help: "What is Convolution? And Two Examples where it arises." ua-cam.com/video/X2cJ8vAc0MU/v-deo.html
I love how you explain this whole thing, and at the end give us a good conclusion so we don't have to do the calculating every time. We can just know the result while knowing how it works. Thanks a lot !!!
Glad it was helpful!
I am studying solid-state physics which requires me to understand the convolution with a delta function. Your short but pithy exposition helped me get around it. Thanks very much.
Glad it was helpful!
absolute banger of a video, thank you!
Glad you liked it!
When h(alpha) is shifted in alpha axis by say Alpha0 amount, where will the final waveform shifted to after convultion with delta function delta (tau-4)?
I was really struggling to understand h(t-tau) part ,your explanation was very helpful. Thank you
Glad it was helpful!
Wonderful explanations on your channel...easy to understand...thank u very much sir, for your effort to help students all around the world. I am from Sri Lanka. One love.
Thanks for your nice comment. I'm so glad you like the channel.
Thanks a lot for learning to us in a simple language. I really like it.
It's my pleasure. I'm glad you find the videos helpful.
At 3:10 why does t start at the negative side not at the positive side
The function needs to be evaluated for all values of t. So you could start with a positive value if you like, but you will also need to consider the negative values at some point. Most people prefer to start with the most negative values and then consider increasingly positive (less negative) values of t.
@@iain_explains I see, thank you
Thank you so much, greetings from Spain!
You are welcome!
i have a question. What if we were to take the convolution of a sin function for example and a delta function with no shift. Would the convolution just be the original sin function?
Yes.
Thanks. Why h(t) flipped to the original shape at the end?
It's not flipped at the end. That is the output of the convolution. If anything, the earlier functions can be viewed as having been "flipped" - but I prefer not to think about "flipping" any functions. I prefer to consider the exact functions, as the maths specifies. This video might help: "Convolution in 5 Easy Steps" ua-cam.com/video/aMaw4EumwyE/v-deo.html
Thank you.. I've looked every where to find answer for my question but couldn't find it.. I'm trying to understand when laplace transfor of delta function is F(s)=1 ..how I can plot this 1 on the s domain graph ? Is that number on the real part alpha (decays) or on the imaginary part (jw) ?
For a delta function, F(s)=1 for all s. That means the function equals 1 everywhere over "the s-plane". Perhaps this video will help with the visualisation: "How do Poles and Zeros affect the Laplace Transform and the Fourier Transform?" ua-cam.com/video/iP4fckfDNK8/v-deo.html
@@iain_explains Thank you 🙏
Thanks for these videos, they are really intuitive and help you understand what the math actually means. Thanks!! :)
That's great. Glad you like them!
Thank you soo much, that was very helpful!!!
Glad it was helpful!
Very helpful, thank you!
Glad it was helpful!
What if we have x(t) = Aδ(t-to)?
Here's a video that explains that: "What is an Impulse Response?" ua-cam.com/video/WTmelRV_Yyo/v-deo.html
thank you so much!
You're welcome!
what will happen if X(t) = delta(t+3) ?
The same as it shows in the video (which is for x(t) = delta(t-4) ), but with the "response" starting at t=-3
What will happen if X(t)=delta(t-1)+delta(t-2)
Convolution is linear and additive, so you can take the convolution with each delta separately, and then add the result.
@@iain_explains thanks a lot. great teacher
Very intuitive and clear
I'm glad it helped.
Perfect
Thanks. Glad you liked it.
X(t)*delt(t)=x(t)
Not sure what point you're making, sorry. Why do you use a capital letter for the first "X"? Normally we use the capital letter for representing the signal in the frequency domain. If your first letter was a lower case, then yes, your equation would be correct.
I don't understand jack
Have you tried watching my video that explains what convolution is? It might help: "What is Convolution? And Two Examples where it arises." ua-cam.com/video/X2cJ8vAc0MU/v-deo.html