WMA14/01, IAL, (Edexcel), P4, October 2022, Q11, Implicit Differentiation, Stationary Points

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  • Опубліковано 16 лис 2024

КОМЕНТАРІ • 7

  • @--katkat
    @--katkat 19 днів тому +1

    Hi Mr hassaan ! Just wanted thank you from the bottom of my heart for these videos , since this is most probably the last time I'll visit your channel cause I had my final maths exam today . I've learned a lot from your video's. Thank u 💛💛

    • @MrHassaansMathsChannel
      @MrHassaansMathsChannel  19 днів тому +1

      You're welcome... im happy that you benefited from them and I wish you the best in life

    • @--katkat
      @--katkat 18 днів тому

      @MrHassaansMathsChannel thank you

  • @fami5123
    @fami5123 Рік тому +5

    Sir, how about "x+y=-6" this equation ?

    • @neptune-r3i
      @neptune-r3i 8 місяців тому

      did you figure that out? if so can you tell me as well?

    • @Cataclysmic_11
      @Cataclysmic_11 5 місяців тому +9

      ​@user-xo1sf8qi1b basically u have to use both equations separately. Use x+y=-6 and substitute into the equation of the graph to get a value for y. However what you will notice is that when you form a quadratic equation for the -6 equation, and try to sole it you will get error cuz inside the square root u will get negative number. So you will dispose off the -6 equation and use the +6 equation as sir did to find two values of y. A bit late but hope this helps.

    • @neptune-r3i
      @neptune-r3i 5 місяців тому

      @@Cataclysmic_11 thank you so muchh