An Interesting Non-standard Equation

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  • Опубліковано 7 лют 2025
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КОМЕНТАРІ • 16

  • @jan-willemkrans7074
    @jan-willemkrans7074 Місяць тому +2

    Thanks for a all the effort, as per usual.
    This certainly looked like fun, so I gave it a shot before watching the video. (As I usually do, I just don't comment that often.) I used a syntax that can be input into Wolfram Alpha easily here, just chop off the part with the ";" at the end if anyone cares to check parts.
    x^45 = 243^(x^2); prime decomposition
    x^(3^2*5) = (3^5)^(x^2); redistribute power
    x^(3^2*5) = 3^(x^2*5); ()^(1/5)
    Note: taking the quintic root does get rid of 4 complex intermediate branches for this step of solving the eqation in this kind of domain. The root is of an odd value though, so there isn't a second real root (that would be the unary negated version of the first output).
    x^(3^2) = 3^(x^2)
    By direct inspection, x = 3 .
    Is there a second real solution? Try to arrange the equation for the Lambert W function.
    x^(3^2) = 3^(x^2); ln()
    3^2*ln(x) = x^2*ln(3); ()*x^-2*3^-2
    x^-2*ln(x) = 3^-2*ln(3); use e^ln(x^-2) = x^-2
    e^(-2*ln(x))*ln(x) = 3^-2*ln(3); -2*()
    -2*ln(x)*e^(-2*ln(x)) = -2*3^-2*ln(3); use e^ln(3^-2) = 3^-2
    -2*ln(x)*e^(-2*ln(x)) = -2*ln(3)*e^(-2*ln(3)); apply Lambert W function
    -2*ln(x) = ProductLog(-2*ln(3)*e^(-2*ln(3))); -1/2*()
    ln(x) = -1/2*ProductLog(-2*ln(3)*e^(-2*ln(3))); e^()
    x = e^(-1/2*ProductLog(-2*ln(3)*e^(-2*ln(3))))
    Again, by direct inspection, x = 3 for one possible answer.
    Wolfram Alpha tells that "e^(-1/2*ProductLog(0, -2*ln(3)*e^(-2*ln(3))))" with an output value of near 1.188 is the the primary solution.
    The expression "e^(-1/2*ProductLog(-1, -2*ln(3)*e^(-2*ln(3))))" for the next branch equals 3, as expected.
    All other expressions for the Lambert W function will yield (countable) infinitely many complex solutions. From the earlier discarded 4 branches (by taking the quintic root) all results will yield sets of just complex solutions, too.

  • @SweetSorrow777
    @SweetSorrow777 Місяць тому +5

    How are numerical values calculated from the Lambert W function?

    • @jan-willemkrans7074
      @jan-willemkrans7074 Місяць тому +3

      See the Wikipedia page, it has an infinitely large series expansion. There are easier to approximate functions used in calculators for numerical outputs though.

  • @davidramos4707
    @davidramos4707 Місяць тому +2

    You should make a UA-cam channel called LambertWFunction.

  • @rakenzarnsworld2
    @rakenzarnsworld2 Місяць тому +1

    x = 3

  • @giuseppemalaguti435
    @giuseppemalaguti435 Місяць тому

    x=e^(-0,5W(-ln9/9))=1,188...oltre al banale 3

  • @scottleung9587
    @scottleung9587 Місяць тому

    Nice!

  • @RealQinnMalloryu4
    @RealQinnMalloryu4 Місяць тому

    x^3^15 x^3^3^5 x1^3^1 x^3^1 (x ➖ 3x+1) 3^5x^2 3^2^3x^2 1^1^3x^2 3x^2 (x ➖ 3x+2).

  • @mtaur4113
    @mtaur4113 Місяць тому +1

    Pretty gross, answer better be 3 or we might be in trouble.

    • @nightstar8444
      @nightstar8444 Місяць тому

      O_o

    • @mtaur4113
      @mtaur4113 Місяць тому

      @nightstar8444 j/k, there a W function for that