The Complex Logarithm

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  • Опубліковано 8 січ 2025

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  • @Christian-qh5zu
    @Christian-qh5zu 5 років тому +63

    Am I the only one who thinks the animation style resembles 3blue1brown? Keep up the good work man!

    • @XanderGouws
      @XanderGouws  5 років тому +9

      Thank you so much

    • @pinklady7184
      @pinklady7184 4 роки тому +3

      Xander Gouws, are you alive and kicking? If not, rest in peace and thank you for your contributions.

    • @anjamoro8384
      @anjamoro8384 2 роки тому +3

      @@pinklady7184 what

  • @MathManMcGreal
    @MathManMcGreal 5 років тому +14

    Love it! Short, crisp, clean, and clear!

  • @salmanshahriar5974
    @salmanshahriar5974 5 років тому +19

    You deserve more recognition, man ♥️

  • @mathematicalmuscleman
    @mathematicalmuscleman 2 роки тому +3

    So this is how Pure Mathematicians developed the construct of a Complex Logarithm Mapping. Maybe this is the process that Euler used.

  • @るるん-n6n
    @るるん-n6n 2 роки тому +1

    Awesome video!
    Note: The domain shown at the end isn't really standard, because you can't define a continuous version of Log on all of C. If you make both inequalities at 3:26 sharp, it will become holomorphic, which is much nicer in proofs and calculations.

  • @armandoski-g
    @armandoski-g 2 роки тому

    This channel's gonna blow in 3,2,1...

  • @shreerampetkar5221
    @shreerampetkar5221 3 роки тому +1

    Wonderful video! Great amimations and a calm voice! Thanks a lot!

  • @mathsfamily6766
    @mathsfamily6766 3 роки тому +2

    Perfect explanation!

  • @pinklady7184
    @pinklady7184 4 роки тому +1

    Brilliant solution. Thanks for tutorial.

  • @PIPuniverse
    @PIPuniverse 4 роки тому +2

    Hey man! Can you tell me what is the name of the font that you are writing with, it looks really scientific and awesome?

    • @XanderGouws
      @XanderGouws  4 роки тому +1

      Hey! I believe the font I'm using here is just the default LaTeX font, which is Computer Modern. If you're not familiar with LaTeX, it's a markup language that lets you write math equations pretty easily. A great way to learn it is to play around with it using www.codecogs.com/latex/eqneditor.php but there are also some great tutorials on UA-cam for a more structured approach.
      Hope this helps :)

    • @PIPuniverse
      @PIPuniverse 4 роки тому

      @@XanderGouws Thank you for your help :)

  • @engelsteinberg593
    @engelsteinberg593 3 роки тому

    The complex definition of sine and cosibe is no the same McClaurin Series as always?

  • @josemartinho424
    @josemartinho424 Рік тому

    😊very clear! Brilliant!

  • @antman7673
    @antman7673 5 років тому

    Very good video.
    Understood the complex log in less than 2 minutes. Skipped a bit a head :P
    Very much appreciated.

  • @Labroidas
    @Labroidas 5 років тому +5

    Very nice video, well prepared, everything brought to the point in a simple way, and the visualizations are very clean and easy to follow. This video must have taken a long time to make in relation to how short it is! This makes it a lot easier to digest the tons of information in my textbook, thank you very much.

    • @XanderGouws
      @XanderGouws  5 років тому +2

      Thank you so much! I'm glad I could help :)

  • @elreturner1227
    @elreturner1227 4 місяці тому

    This always seemed obvious logarithms are just roots for when x is the exponent instead of the base just like square root of -1 except a bit fancier

  • @prediccionescountryballs893
    @prediccionescountryballs893 2 роки тому

    6:43

  • @TheOriginalDeaf
    @TheOriginalDeaf 10 місяців тому

    e^(I*pi) = -1
    Ln both sides
    Pi*i = ln(-1)
    Pi = ln(-1)/i
    I proved that pi is rational in the complex plain, is this true or did I do a wrong step?

    • @Cyrenalux
      @Cyrenalux 3 місяці тому +1

      π = ln(-1)/i
      π = iπ/i
      π = π
      🤷

  • @redpepper74
    @redpepper74 3 місяці тому +2

    0:27 “This isn’t because the values don’t exist, but because they’re not real.” Hmmm okay mister

  • @duckymomo7935
    @duckymomo7935 5 років тому +1

    Why didn’t you mention arg (z)?

    • @XanderGouws
      @XanderGouws  5 років тому +1

      It was easier to write θ than to use arg(z) every time - but maybe I could've made a note of it or something.

  • @lamaiyad9596
    @lamaiyad9596 2 роки тому

    شكراً جزيلاً 🤍

  • @JDC2890
    @JDC2890 2 роки тому

    (1 + 2n)Pi*i, where n is an integer?

  • @REEMAN_
    @REEMAN_ 2 роки тому

    U R amazing!

  • @bobsno1fan783
    @bobsno1fan783 6 років тому +1

    What is 2+2?

    • @rot6015
      @rot6015 5 років тому

      7

    • @n019n
      @n019n 8 місяців тому +1

      first you divide by zero on each side

  • @ycombinator765
    @ycombinator765 2 роки тому

    Loved it

  • @РайанКупер-э4о
    @РайанКупер-э4о 4 місяці тому

    Letting the log have multiple values doesn't break the math.

  • @bebarshossny5148
    @bebarshossny5148 4 роки тому

    why did this channel stop its another one of those gold math channels like 3b1b

    • @XanderGouws
      @XanderGouws  3 роки тому +2

      My bad! I've been busy with uni recently and haven't had much time to put towards making videos :( I do plan to get back to it as soon as I can though!

  • @高木清治
    @高木清治 4 роки тому

    θ=π/4 , r^2=1^2+1^2 , k=0 , i*π=4*ln(1+i)-2*ln(2)?

  • @Effect_channel
    @Effect_channel 4 місяці тому

    0:38 this identity isnt actually eulers but still but the TRUE eulers identity is (sigma n=1 to ∞) (1/n²)=π²/6

  • @theophonchana5025
    @theophonchana5025 3 роки тому

    ln (-1) = error

  • @abhishekdixit638
    @abhishekdixit638 4 роки тому

    For z=a+ib
    cos(z)=[cos(a)cosh(b)]-i[sin(a)sinh(b)]
    And
    sin(z)=[sin(a)cosh(b)]+i[sinh(b)cos(a)]
    (If i'm right...)

  • @ZombieLoverPlays
    @ZombieLoverPlays 6 років тому +1

    Love it

  • @pucek365
    @pucek365 3 роки тому

    314 likes :D Love it

  • @theophonchana5025
    @theophonchana5025 3 роки тому

    ln (-1) = undefined

    • @soccerbels7947
      @soccerbels7947 3 роки тому

      Dude if you tried on an calculator ofc it will not work

  • @theophonchana5025
    @theophonchana5025 3 роки тому

    #ln #naturallogarithm #logarithm

  • @yondabigman4668
    @yondabigman4668 3 роки тому

    Oh boy

  • @anwarh.joarder8644
    @anwarh.joarder8644 2 роки тому

    Kindly speak allowed and in a slow paced way for non- natives.

  • @sarkarsubhadipofficial
    @sarkarsubhadipofficial Рік тому

    😮

  • @otonanoC
    @otonanoC Рік тому

    I waited and waited for the narrator to say that f(z)=ln(z) is literally the inverse function of f(z)= e^z . But he never got there.

  • @ЕвгенийСимонов-к5о
    @ЕвгенийСимонов-к5о 5 років тому

    Плиз нот туркиш
    Го руссиш

  • @pratyaksh1729
    @pratyaksh1729 2 роки тому

    Actually your result is wrong. Logarithm of a negative value is a multivalued function. That means it can have multiple values. For example: 3i*pi is also a solution.

    • @1495978707
      @1495978707 4 місяці тому +1

      He specifically addresses this if you keep watching...

  • @theophonchana5025
    @theophonchana5025 3 роки тому

    #error #undefined