Just find it by your own. we know input cap of NAND is 4C. we got x2= 6 , so input cap for NAND will be 6×3C. So , if upscaling factor of NAND is k2 ,then 4C×k2= 6×3C so k2= 4.5
@@pawansharma6226 we are equating the product of size we want upsize the unit DUT gate i/p cap (here NAND : K2*4C) with the{=} product of unit inverter cap and Stage effort(3c*fk)... am I right..? If I am wrong please let me know...
This prof is a genius
He's gonna save me from failing this course legit
🙏Wow...
We should only add even number of inverters . so that my actual boolean logic doesnt change right ?
Yes.
What will be k2?
Just find it by your own.
we know input cap of NAND is 4C.
we got x2= 6 , so input cap for NAND will be 6×3C.
So , if upscaling factor of NAND is k2 ,then 4C×k2= 6×3C so k2= 4.5
@@pawansharma6226 we are equating the product of size we want upsize the unit DUT gate i/p cap (here NAND : K2*4C) with the{=} product of unit inverter cap and Stage effort(3c*fk)...
am I right..? If I am wrong please let me know...
how did we jump to the conclusion of 400 lambda width?
Listen carefully bro you'll find all the answers