Review Exercise | Equations | Rational Expressions l Part 4 l Grade 11 l Unit 2 | New

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  • Опубліковано 2 жов 2024
  • Part 1 Link: • Review Exercise | Simp...
    Part 2 Link : • Review Exercise | Oper...
    Part 3 Link: • Review Exercise | Deco...
    Part 4 Link (this video): • Review Exercise | Equa...
    Part 5 Link: • Review Exercise | Ineq...
    Old Curriculum Questions: • Exercise 2.6 | Rationa...
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КОМЕНТАРІ • 18

  • @moking5347
    @moking5347 8 місяців тому +1

    THANKS SO MUCH 🎉🎉❤

  • @ADEY524
    @ADEY524 8 місяців тому

    tnks tich continue

  • @Ahmed-ly5pm
    @Ahmed-ly5pm 9 місяців тому

    Thank you tich

  • @BlenGhiwot
    @BlenGhiwot 8 місяців тому

    At question B you have multipled the equation by x square if the product wasn't zero would we multiple that to

    • @MathMadeEasyBetty
      @MathMadeEasyBetty  8 місяців тому

      Yes you can multiply by any number or x as long as you do it on both sides (before equal sign and after equal sign). If two numbers are equal you can multiply or divide both sides by the same number to simplify your equation. Whenever I multiply by x or any number it’s mostly it is to avoid fraction. So yes for equations you can multiply. You can try the same question by multiplying both sides by x^3 instead of x square and you will see that the result is all the same. Please let me know if there is any confusion I will make a short video for you but let me know

  • @EsetK
    @EsetK 8 місяців тому

    betam betam enamesgnalen batya

  • @C......590
    @C......590 9 місяців тому

    Enamesegnal❤❤

  • @HannahT-qo3zj
    @HannahT-qo3zj 8 місяців тому

    for q b, if we use -2 and -3 our s.s becoms{3,-2}
    is my answer possible n if i is does that mean we can have many different answers

    • @MathMadeEasyBetty
      @MathMadeEasyBetty  8 місяців тому

      Q b is 1-5/x -6/x^2 = 0
      If you put -2 you get 1+ 5/2-6/4 = 1+ 5/2 -3/2 = 1+ 1= 2 and not zero. Can you double check your work? We both should get the same answer

    • @HannahT-qo3zj
      @HannahT-qo3zj 8 місяців тому

      x^2-5x-6=0
      x(x-2)-3(x+2)=0
      (x-3)(x+2)=0
      s.s{3,-2} this is what i got ,,,,,,,,,,am i missing something@@MathMadeEasyBetty

    • @MathMadeEasyBetty
      @MathMadeEasyBetty  8 місяців тому +1

      Two numbers that adds up to -5 and multiplied -6 are not -2 and -3; -2 +-3 is -5 but when you multiply -2 and -3 it’s not -6 that’s why we use number 1 and -6. That means you can write the equation
      x^2 -5x -6 as
      x^2 +x -6x -6 = 0
      X(x+1) + -6(x+1) = 0
      (X-6)(x+1) = 0
      X=6 or x = -1
      You can replace the solution and check that way you know the answer is correct. If you see your calculation one of them is (x-2) one is (x+2) you can’t Group different items. Please let me know if it’s not clear I will make a short video for you no worries just let me know

    • @HannahT-qo3zj
      @HannahT-qo3zj 8 місяців тому

      owwww ya ya i made a sign mistake 😅🤦‍♀ now i get it its clear thank you so much miss for real u r the best @@MathMadeEasyBetty

    • @MathMadeEasyBetty
      @MathMadeEasyBetty  8 місяців тому +1

      You are welcome dear; I appreciate you for working the problems with me. That’s the way to practice math; Good job. Let me know when you have any question in any other problems

  • @MatiLijalem
    @MatiLijalem 10 місяців тому +1

    Ere le 12 seriln pls pls pls

  • @leroykabanuck62
    @leroykabanuck62 9 місяців тому

    "PromoSM" 😃

  • @Tiktok-cy8ic
    @Tiktok-cy8ic 10 місяців тому

    ufeyy tebarekiln enamesegnalen❤🤎🤎