It is done by consulting t distribution table using degree of freedom and desired probability level. Here is an example ua-cam.com/video/5QuSa3odhPE/v-deo.html&si=CylvZygWtuaFmh1Y
@@benishali Thnku mam for reply. yeah the information given about the question are treatment means, treatment, row, colum & total sum of squares and the task is to draw the observations of 5*5 LSD on the basis of these given info's.
@@benishali For reference, the information given about 5*5 LSD are-- SS due to treatment - 65.42 SS due to rows - 1.36 SS due to colum - 80.73 Total SS - 153.94 Mean of five treatments are - A(3.684), B(3.396), C(3.368), D(3.036), E(3.996) and F (0.025)=4.12 with 4 & 12 degree of freedom, t(0.005)=3.055 with 12 degree of freedom. And now we have to draw all observations of 5*5 LSD.
thank you, you are explaining super well.
Thanks a lot!
Wow very clear explainations. Thank you !
You are welcome!
You are welcome!
Thanks Ma'am, You are a Good Teacher of Stat
Thanks and welcome!
Excellent thanks very much
You're welcome.
Great video, as per ususal!
Glad it was useful!
Thank you for the detailed explanation, sister 😇🥰🥰
Thank you so much!
👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏
Thanks
good job, dear Mam
Thanks
Am I the only one that can't see clearly on the screen? Great video tho. Very helpful. Thank you so much
Please try again. And thanks for the feedback!
How do you read the t-table?? for the fishers formula.
It is done by consulting t distribution table using degree of freedom and desired probability level. Here is an example ua-cam.com/video/5QuSa3odhPE/v-deo.html&si=CylvZygWtuaFmh1Y
Hello mam, is it possible to estimate all LSD observations with help of just anova table info's (sum of squares, f statistic and treatment totals)??
You need to know the mean value as well as no. of observations for each pair of samples / groups / treatments.
@@benishali Thnku mam for reply. yeah the information given about the question are treatment means, treatment, row, colum & total sum of squares and the task is to draw the observations of 5*5 LSD on the basis of these given info's.
@@benishali For reference, the information given about 5*5 LSD are--
SS due to treatment - 65.42
SS due to rows - 1.36
SS due to colum - 80.73
Total SS - 153.94
Mean of five treatments are - A(3.684), B(3.396), C(3.368), D(3.036), E(3.996) and F (0.025)=4.12 with 4 & 12 degree of freedom, t(0.005)=3.055 with 12 degree of freedom. And now we have to draw all observations of 5*5 LSD.
how we calculate LSD value for two way anova and how we write significant letters? Kindly help
I am sorry. I don't have a clear idea of that.
I also want to know that😢