thanks, but i have a question: if the cart were to be upwards on the track (as in outside the track, not inside like it is in the diagram) would the normal reaction be acting upwards since it will be in contact on the other side?
Hi I’ve been wondering when a roller coaster completes a loop would the speed at the bottom of the loop after doing the loop be the same as the minimum speed?
That is the normal reaction force acting on the cart. Imagine a book resting on your desk. The normal reaction force from the desk acts upward (pushing) on the book. In the case of the roller coaster cart at the top of the loop, the track pushes on the cart (downward).
if normal force and gravitational force both points down at the top of the circle, then what is preventing the car from falling at the top. What is the force that is countering gravity that allows the car to not fall
The car is falling, but because it has tangential velocity, the car moves in a curved path. That's literally the whole premise of circular motion. If you stopped the car at the top, it would then fall to the ground. This is why the space station doesn't come crashing down to the earth, its falling but also moving really fast at a right angle to the force of gravity.
What happens when the cart is not exactly at the top or bottom? What is the equation for centripetal force when the cart is halfway between them, for example?
It gets a bit more complicated at that point, I haven’t done this in Physics yet, but in Further Maths we have to resolve the forces relative to an angle to the centre
Thank you, The video is awesome But a small doubt ❓ Why do we substitute the formula of *critical velocity at any point* in the equation to find *minimum tension in string to just complete vertical circle*
the critical velocity is the minimum velocity required to keep the mass moving in a circular path without the tension in the string becoming zero. This ensures that the tension in the string is sufficient to keep the mass moving in a circular path and prevent it from falling straight down due to gravity.
Most underrated physics video... Thanks!
Thank you so much! Saved me from confusion.
Exceptional explanation, thanks
very informative . thanks
I’ve been expecting you
who came here in hopes of deriving root 5 gl?
Nope.. Ik tht already
@@PCM1112 "so why are you here? just to suffer?"
@@Anonymous_baka634 nah actually I had to revise this particular topic...
Critical?
@@SajithaKR-e1b ????
Thankyou so much❤
Your voice is so beautiful
Great explanation
thanks, but i have a question:
if the cart were to be upwards on the track (as in outside the track, not inside like it is in the diagram) would the normal reaction be acting upwards since it will be in contact on the other side?
You're correct, the normal reaction force will be acting upwards and the weight will be downwards.
@@vt.physics got it thanks!
@@vt.physics would that mean you do F = N - mg?
@@Adamclws that looks right to me, as the normal reaction force is acting in the direction of the centripetal force
@@vt.physics what about if it was on the right side (inside of loop)]
Hi I’ve been wondering when a roller coaster completes a loop would the speed at the bottom of the loop after doing the loop be the same as the minimum speed?
Thank you soooooooo much ❤❤❤
Aewsomeee!!!
But why is N downwards at the top?
That is the normal reaction force acting on the cart.
Imagine a book resting on your desk. The normal reaction force from the desk acts upward (pushing) on the book.
In the case of the roller coaster cart at the top of the loop, the track pushes on the cart (downward).
@@vt.physics oh OK thanks
because you are upside down it will go down
Thanks sis😘
Welcome 😊
if normal force and gravitational force both points down at the top of the circle, then what is preventing the car from falling at the top. What is the force that is countering gravity that allows the car to not fall
Centrifugal force
@@aji3576 No, there's no such thing as "centrifugal force"
The car is falling, but because it has tangential velocity, the car moves in a curved path. That's literally the whole premise of circular motion. If you stopped the car at the top, it would then fall to the ground. This is why the space station doesn't come crashing down to the earth, its falling but also moving really fast at a right angle to the force of gravity.
What case that involve normal force equal to zero?
What happens when the cart is not exactly at the top or bottom? What is the equation for centripetal force when the cart is halfway between them, for example?
It gets a bit more complicated at that point, I haven’t done this in Physics yet, but in Further Maths we have to resolve the forces relative to an angle to the centre
then you can use trig to find the forces
My teacher said the Force of tension at the top is 0, is he correct?
No
Thank you, The video is awesome
But a small doubt ❓
Why do we substitute the formula of *critical velocity at any point* in the equation to find *minimum tension in string to just complete vertical circle*
the critical velocity is the minimum velocity required to keep the mass moving in a circular path without the tension in the string becoming zero. This ensures that the tension in the string is sufficient to keep the mass moving in a circular path and prevent it from falling straight down due to gravity.
Wow
hey