Sir I am following you from 2 monthes you teach awesome. I am a foundation class 10th student currently I am studying from aakash digital but to complete class 11 syllabus I watch your videos . Always I forgot to comment but sir never stop teaching. First time in the life I realised that I had understood the concepts currently I am watching your chemical bonding lecture. I suggest my freinds to watch your videos and they also like your teaching.❤
Mera reasoning before seeing solution:- Maalik mai iss question ko iss tarah se interpret kr rha hu ki π bond aise toh rotate nhi kr skta, iska mtlb wo + - mein break ho kr sigma bond banega aur wo rotate karega. Negative barrier wala molecule most probably C hoga kyuki waha sbse jyada steric hinderance hai. Isliye wo jldi se jldi alag plane mein jana chahega. Isliye C ka S hoga. Ab options ke hisab se B ka R confirm hogya. Baar bachi A aur D ki. Yha stability dekh lete hai toh D ek acha khasa stable sa compound hai. Agr usmein bond break hua toh dono + - kaafi stable rahenge aur as such koi steric crowding bhi nhi hai. Upar se D waise bhi ek jyada symmetrical aur stable compound aur A mein bade bade groups bhi lage hai isliye A ko rotate krna padega apne aap ko stable banane ke liye. Thus A ka q aur D ka p answer ho jayega jisse option A answer mil jayega. Ik mera reasoning jyada chemistry related nhi but agr ye question exam mein aata toh mai yhi sochta. Ab video dekh kr kuch naya seekhta hu.
Agr B ke reasoning ki baat ho toh jb double bond + - mein tutega toh - ring ke taraf rakhenge jisse ring aromatic ho jayega aur + bahar ke taraf rakhenge jisko stable krne ke liye 2 phenyl group already present hai. Yha se B kaafi acha khasa stable compound ban jayega after breaking of π bond isliye uska barrier kam hoga baaki ki comparison mein. Agr B aur D ka comparison krna ho toh better ye hoga dekhna ki kisko jyada stability milegi after bond breaking. Agr D ki baat kare toh wo pehle bhi kaafi stable tha, baad mein bhi stable hogya. But B pehle utna stable nhi tha but baad mein kaafi jyada stable hogya. Thus B ki rotation free energy D se kam hogi.
Sir in b) ring will become aromatic after giving it negative and the carbocation is stabilized by (2 +M) due to benzene rings so rotational barrier decreases.
Op question maalik ❣️🔥 Kuch options ban gaye the lekin you made a very much clearity regarding all the options ❣️🫶 Aise hi aur question laate rahiye eagerly waiting...👍🔥
Sir but when we rotate bond in (a) and also give -ve on both oxygen then one ring become anti aromatic and other become aromatic . While in case of (d) , both +ve and -ve charges are quite stable after rotation of bond because of adjacent double bond then it have lower Potential barrier than(a) hence ans must be B. Can you pls being a detailed lecture about its thinking algorithm.
Dost kab se organic or inorganic start ho gi is Channel pe bahut dino se intzaar kar rha hu dost first attempt aane hi waala hai darr alag se lag rha hai kiya hoga dropper hu dost ab aap to samajhte honge droppers ke paas time nhi rehta dost. Bus jaldi inorganic ka session lijiye ❤
Sir I am following you from 2 monthes you teach awesome. I am a foundation class 10th student currently I am studying from aakash digital but to complete class 11 syllabus I watch your videos . Always I forgot to comment but sir never stop teaching. First time in the life I realised that I had understood the concepts currently I am watching your chemical bonding lecture. I suggest my freinds to watch your videos and they also like your teaching.❤
Mera reasoning before seeing solution:-
Maalik mai iss question ko iss tarah se interpret kr rha hu ki π bond aise toh rotate nhi kr skta, iska mtlb wo + - mein break ho kr sigma bond banega aur wo rotate karega. Negative barrier wala molecule most probably C hoga kyuki waha sbse jyada steric hinderance hai. Isliye wo jldi se jldi alag plane mein jana chahega. Isliye C ka S hoga. Ab options ke hisab se B ka R confirm hogya. Baar bachi A aur D ki. Yha stability dekh lete hai toh D ek acha khasa stable sa compound hai. Agr usmein bond break hua toh dono + - kaafi stable rahenge aur as such koi steric crowding bhi nhi hai. Upar se D waise bhi ek jyada symmetrical aur stable compound aur A mein bade bade groups bhi lage hai isliye A ko rotate krna padega apne aap ko stable banane ke liye. Thus A ka q aur D ka p answer ho jayega jisse option A answer mil jayega.
Ik mera reasoning jyada chemistry related nhi but agr ye question exam mein aata toh mai yhi sochta. Ab video dekh kr kuch naya seekhta hu.
Agr B ke reasoning ki baat ho toh jb double bond + - mein tutega toh - ring ke taraf rakhenge jisse ring aromatic ho jayega aur + bahar ke taraf rakhenge jisko stable krne ke liye 2 phenyl group already present hai. Yha se B kaafi acha khasa stable compound ban jayega after breaking of π bond isliye uska barrier kam hoga baaki ki comparison mein. Agr B aur D ka comparison krna ho toh better ye hoga dekhna ki kisko jyada stability milegi after bond breaking. Agr D ki baat kare toh wo pehle bhi kaafi stable tha, baad mein bhi stable hogya. But B pehle utna stable nhi tha but baad mein kaafi jyada stable hogya. Thus B ki rotation free energy D se kam hogi.
Aapke Karan Mera organic me soch ne ka tarika develop hua hai
Thank you malik❤
I did this question earlier to
Keep giving these kind of doses daily. ❤
Was doable thanku sir for your efforts salute to you sir
dost ye chote but crucial concepts ko dicuss karna kabhi band mat karna bohut madad hoti he❤❤
Noted in my copy 🔥🔥 we need more question solving like this
Yha par hum aromaticity se bhi soch skte hai n
Sir in b) ring will become aromatic after giving it negative and the carbocation is stabilized by (2 +M) due to benzene rings so rotational barrier decreases.
Op question maalik ❣️🔥
Kuch options ban gaye the lekin you made a very much clearity regarding all the options ❣️🫶
Aise hi aur question laate rahiye eagerly waiting...👍🔥
Op question dost❤
Sir aap bahot ache ache question deeply karwa rahe hoo Thora aur frequency inh sab ki bhada dijiye please
sir equilibrium ke questions kab disscuss honge
LY3M MAALIK ❤️🔥❤️🔥❤️🔥
Sir mera hydrogen spectrum ke baad ka lecture nh aa rah hai ,so sir abhi mai keya karu ?
Sir but when we rotate bond in (a) and also give -ve on both oxygen then one ring become anti aromatic and other become aromatic . While in case of (d) , both +ve and -ve charges are quite stable after rotation of bond because of adjacent double bond then it have lower Potential barrier than(a) hence ans must be B. Can you pls being a detailed lecture about its thinking algorithm.
Kl phy ka half yearly h...exam se aake attempt krungi promise 🔥💪
Dost kab se organic or inorganic start ho gi is Channel pe bahut dino se intzaar kar rha hu dost first attempt aane hi waala hai darr alag se lag rha hai kiya hoga dropper hu dost ab aap to samajhte honge droppers ke paas time nhi rehta dost. Bus jaldi inorganic ka session lijiye ❤
sir under 1 minute solved b option