NMR spectroscopy in easy way - Part 1

Learn Nuclear magnetic resonance (NMR) spectroscopy in easy way. NMR is a special tool that plays a key role in structural elucidation of many organic and pharmaceutical compounds.
In organic chemistry, NMR spectra can be used to identify a structure for which spectral interpretation is essential. By observing the number of NMR signals, one can approximately estimate the types of nuclei present in the structure. In case of 1H-NMR, the number of different types of protons attached in different way to parent chain can be detected by studying NMR signals.
All nuclei can not give NMR signal but nuclei with spin quantum number I = 1/2 can only win this game. Nuclei like proton (1H), 13-carbon (13C), fluorine (19F) and few other nuclei can give NMR signals.
Electrons surrounding a nuclei can oppose the magnetic field applied externally thereby they reduce NMR signal. This effect is knows as shielding effect. But the effect of these electrons highly depends on the connectivity and orientation of the groups in the molecule.
In this spectroscopy, the effect of neighboring groups on the nuclei is also studied. Few of the groups increase the electron density surrounding the nuclei under study thereby they produce an upfield effect. These groups shift the NMR signals to right side leading to decrease in the chemical shift.
This is the part-I of video series in which how easily we can understand NMR spectroscopy was discussed.
Find part -2 of this video here : • NMR spectroscopy in ea...
Part-3 : NMR spectral interpretation and rules: • NMR spectroscopy in ea...
Part-4 : NMR spectral table: • NMR spectroscopy in ea...
Part-5 : Magnetic anisotropy: • NMR spectroscopy in ea...
Part-6: Solvents in NMR : • NMR spectroscopy in ea...
Part-7: 1H vs 13C NMR : • NMR spectroscopy in ea...
Part-8: Number of NMR signals: • NMR spectroscopy in ea...
Part-9: Magnetic equivalence: • NMR spectroscopy in ea...
Part-10: NMR signals in cyclic compounds: • NMR spectroscopy in ea...
#NMRspectroscopy
#NMRprinciple
#protonNMR

[@prathyushad6665]

The best video on NMR. Clear with appropriate examples and concise. Thankyou Sir

[@egpat]

Glad it was helpful! Thanks for watching.

[@bhavishapatel8510]

Hello.... I am not from the physics background so was struggling to understand this; you explained it so well that all my basics about NMR is now clear.... Thankyou so much!!!

[@egpat]

Glad it was helpful! Thanks for watching.

[@jikkimroy7958]

It is for the first time I could understand The NMR spectroscopy
Thank you sir and expecting more and more videos

[@egpat]

Glad it is useful. Thank you. Definitely I will upload more videos, let me know any specific topic you are more interested. Thanks for your interest.

[@sangamthakre8799]

Can u give me ppt of NMR spectroscopy

[@jubairiyajubi3972]

Well explained . Concepts are clear sir . Thank you so much

[@prashantkumarparmanu]

he is the best teacher . A true spirit of a mentor . The Real Man .

[@egpat]

Thanks for liking.

[@SurajSingh-xv6rv]

Thank u you sir it is really helpful and easy to understand 👍

[@FeelEveryShorts]

You are the best teacher.

[@vps1705]

Clear understanding to any chemistry students

[@sireesha_2024]

Explained in simple way..tq sir

[@karthigajagadeesan5177]

Super sir.good explanation

[@hrucha98]

Excellent explained wow👍

[@brijeshprajapati6613]

Waoooo sir tq so much 👍🙏🙏🙏🙏🙏💐💐 unbelievable sir

[@KalaiSelvi-ss1lz]

Very nice explanation sir.upload more videos sir

[@maddumounika2977]

Thank you sir. This video helped me a lot👌

[@egpat]

Glad to hear that. Thanks for watching.

[@helionyanna4655]

Well explained 👌🏻 ..... Thank u sir 🙂

[@egpat]

Glad you liked it. Thanks for watching.

[@vps1705]

Excellent teaching

[@Deevena970]

You are a good teacher. Thank you

[@egpat]

Thank you! Keep watching.

[@manikantapavan6427]

Hi, Nice explanation.. It would be better to describe why Resonance term is used in the technique.. and please check once regarding "No spin " in "No external magnetic field". The concept is, in no external magnetic field nuclei with 1/2 spin will be arranged in random, when an external magnetic field is applied, the nuclei with 1/2 spin will allign to the field. And further is as described. Ignore it, if it is irrelevant.

[@egpat]

Ya, that's a good point. You are correct, as you said, in absence of magnetic field nuclei will have random spin and they produce a small magnetic filed. These nuclei will have intrinsic angular moment but the net spin of all nuclei is very nearer to zero due to random orientation of individual spins. So practically it can be considered as net zero spin compared with nuclei with spin oriented with or opposite to external magnetic filed when it is applied. Thanks a lot for your interest and suggestion.

[@aswathim6684]

Very good explanation

[@pujachaurasiya7751]

Thank u sir, explained well..first time I understood the topic spectroscopy .

[@egpat]

Glad to hear that. Keep watching.

[@dwtrowe]

Beast

[@prasunaponnuru9046]

Very good sir,ur lecture is very clear& easily understand to studends,thank u verymuch🙏

[@lauren9095]

Thank you for this helpful video! I really appreciate it :)
On a side note - I noticed that at 11:09, the m value for I = 0 should be 1, not 0 (as presented).

[@pratikshetye7004]

No I guess I = 0 and m should be = 1 and not 0 as presented

[@pradeepbhakar6029]

Yes m should be 1

[@annapooranir3054]

Really good and easy to understand..Thank you sir

[@Jatin_kumar_]

Sir how is value for I calculated?

[@pavisreviews3041]

Crystal clear 👌

[@mahmadgondal4933]

Sir ... I have a question
When we provide RF the electrons can also absorb the radiation,so why nuclei absorb???

[@addu_mansoori]

Thank u legend 🎉

[@shwethakachu8696]

Thank you so much sir

[@chemistryabcxyz2763]

The part 4 is not available. nmr spectroscopy in easy way part 4 egpat. How can I get it please

[@pradeepbhakar6029]

12:19 i think the multiplicity in case one is m=1 as 2i+1 and i =0 then m is equal to 1

[@biplabchatterjee2185]

Sir is 17O^2 is shown by NMR ACTIVE OR RAMAN ACTIVE..... please clarify my query sir

[@sainiranjanreddymaguluri1694]

Thank u very much sir

[@runningpharmabypriya7834]

Thank you very much for such informative session

[@egpat]

It's my pleasure. Thanks for watching

[@javeriasaeed2074]

The ever best video on NMR ,.... really helpful...thank you soo much 😊

[@sravanthi4312]

Explained excellently

[@egpat]

Glad you liked it. Thanks for watching

[@vishavjitsingh3451]

Well explained

[@saiteja6742]

Never before ever after...

[@dr.harleenkaur6932]

vvv nice explaination

[@cyrillvarghese3182]

Excellent

[@lalvarlawmhmar3722]

There can be signal for others than half

[@mahalakshmihr8918]

Tq soo much sir🥰🥰🥰👍👍

[@harshithathejaswini9518]

Awesome sir tqsm 🙏

[@egpat]

Welcome, thanks for watching.

[@sandrasuja525]

Thank you so much sir...tht helped me to understand the concept

[@egpat]

Glad to hear that. Thanks for watching.

[@veereshuppara6313]

Nice teaching 👌👍

[@egpat]

Thanks for liking

[@mekdesbelete8766]

an outsanding explanation tnks sir

[@egpat]

Most welcome

[@naseehan8856]

Very good ...in11:28 I=0,m=1 is right

[@egpat]

Thank you. Yes, as stated earlier in the video when I =0 , m value is 1. Thanks for watching.

[@naseehan8856]

@@egpat Yes right 👍 I watched 3 parts of nmr.very useful

[@hemadictation123]

Nice explanation sir tq

[@egpat]

You're most welcome

[@karanpreetsingh4654]

Nmr spectroscopy range please tell

[@sainiranjanreddymaguluri1694]

In case 1 m=1 while comparing the cases there is m=0

[@sharmapharmacy4124]

Hlo sir very nice

[@abdurrazaq3657]

Sir ur explaining very well but try urdu or hindi .as for english so many british are there

[@nusrat9127]

This way of teaching is very excellent

[@egpat]

Thanks for liking.

[@akibansari47]

Nice

[@bhaskarreddychinta2709]

Is nmr applicable to compounds that donot contain hydrogen?

[@egpat]

Yes, it can be used for silica and other inorganic compounds also.

[@midcrizzz812]

More than 1H NMR scientist will use 13C NMR...

[@user-lt2cu1fo1w]

Which app you are used for making this video 😢

[@khushbubedi1426]

Wao Thanku so much

[@egpat]

Welcome, thanks for watching

[@mythilimohan3587]

Tnx to made tis🔥

[@egpat]

You are welcome. thanks for watching

[@thamizselvi4823]

Nitrogen 14 is even, it is given under both odd.

[@pradeepbhakar6029]

Individually the number of protons are 7 and neutron is also 7 therefore these both are odd

[@olupotmoses275]

i feel am prepared for m MSC Exam now

[@parthsharma6079]

You are from South India?

[@MeIsUser]

8:56 doubt

[@nandlalsavaliya1849]

🙏🙏🙏🙏🙏🙏🙏

[@dr.d.srividya4911]

We are supplying RF not EMR

[@elmiranadirova2737]

12:36 tell it to deuterium NMR

[@eagleacademy2346]

14 odd ????

[@chemicalworld7800]

Nmr active nuclei I should not be equal to 0....other than 0 can be anything not only 1/2

[@egpat]

When I value is 1 or greater it results in non-spherical charge distribution resulting in signals with variable line width which are not easy to study. But when I=1/2 it leads to spherical charge distribution which is easy to study. That's why nuclei with I =1/2 are selected for NMR spectroscopy.

[@chemicalworld7800]

@@egpat but we talking about nmr signal

[@egpat]

Yes, NMR signal better observed with nuclei I as 1/2. Can you give any example of nuclei studied in NMR with different I value?

[@chemicalworld7800]

Boran 11
Chorine 35
Both I=3/2

[@egpat]

That's great. You are right. So these are the quadrupolar nuclei. But here in this video we are discussing NMR spectroscopy for pharmaceutical analysis where we study nuclei mainly like proton, and carbon in organic compounds which have I value as 1/2. As you said, quadrupolar nuclei are useful to study inorganic nuclei like Cl and B. Thanks for your interest and watching the video.

[@harisonviju8331]

I wish my our online classes were like this..😁

[@pnsnarayana4714]

What is I sir

[@aleemleem8110]

How can 14 will odd sir,,

[@pradeepbhakar6029]

Individually the number of protons are 7 and neutron is also 7 therefore these both are odd

[@kholazahoor9717]

N is 14 and 7 how can this be included in both odd?
14 is an even number!

[@pradeepbhakar6029]

Individually the number of protons are 7 and neutron is also 7 therefore these both are odd

[@donaldthustra_2997]

Nearly all of the information presented in this video is wrong. The claim that you can only observe NMR signals from spin-1/2 nuclei is especially agregious.

[@ramyasrircs9417]

spin quantum number is l not 'i' ...you have been constantly calling it "i"

[@soumyadeepsarkar7819]

Nuclear spin quantum no. is denoted by "I"

[@pradeepbhakar6029]

Bhai orbital angular momentum is "L"

[@arnazmaryam539]

how desperate did i have to be to reach here:)

[@arunadhikari2303]

can I = 3/2 GIVES NMR

[@erikzuiderweg6824]

yes, and also I=1, but rhe signal is difficult to observe

[@kameshrajd9480]

7.26🤣🤣14 is odd number???😬

[@shindekrushna8170]

It is about number of neutrons bro, i.e. 7 and this is odd.

[@SouvikNagYT]

You dumb, sir is talking about neutron number which is odd

[@dranjups8911]

It's based on number of protons and neutrons, it's odd in number...

[@ranaalimudassar5859]

😂😂

[@pradeepbhakar6029]

Individually the number of protons are 7 and neutron is also 7 therefore these both are odd

[@j.hephzibahpriyadarshiniix5199]

Thank you very much sir

[@egpat]

You are welcome.