Hello.... I am not from the physics background so was struggling to understand this; you explained it so well that all my basics about NMR is now clear.... Thankyou so much!!!
Your way of explanation is too good. Truly this video is helpful for easy to understand about NMR spectroscopy . I 💜 it. Thank you so much for valuable information.
Hello Sir... superb explanation...😊 u really made NMR so easy.... please do more videos on COSY, NOESY, FT NMR, 13C, SPIN Relaxation Phenomenona and Other concepts that are present in NMR spectroscopy
Hi, Nice explanation.. It would be better to describe why Resonance term is used in the technique.. and please check once regarding "No spin " in "No external magnetic field". The concept is, in no external magnetic field nuclei with 1/2 spin will be arranged in random, when an external magnetic field is applied, the nuclei with 1/2 spin will allign to the field. And further is as described. Ignore it, if it is irrelevant.
Ya, that's a good point. You are correct, as you said, in absence of magnetic field nuclei will have random spin and they produce a small magnetic filed. These nuclei will have intrinsic angular moment but the net spin of all nuclei is very nearer to zero due to random orientation of individual spins. So practically it can be considered as net zero spin compared with nuclei with spin oriented with or opposite to external magnetic filed when it is applied. Thanks a lot for your interest and suggestion.
Thank you for this helpful video! I really appreciate it :) On a side note - I noticed that at 11:09, the m value for I = 0 should be 1, not 0 (as presented).
When I value is 1 or greater it results in non-spherical charge distribution resulting in signals with variable line width which are not easy to study. But when I=1/2 it leads to spherical charge distribution which is easy to study. That's why nuclei with I =1/2 are selected for NMR spectroscopy.
That's great. You are right. So these are the quadrupolar nuclei. But here in this video we are discussing NMR spectroscopy for pharmaceutical analysis where we study nuclei mainly like proton, and carbon in organic compounds which have I value as 1/2. As you said, quadrupolar nuclei are useful to study inorganic nuclei like Cl and B. Thanks for your interest and watching the video.
Nearly all of the information presented in this video is wrong. The claim that you can only observe NMR signals from spin-1/2 nuclei is especially agregious.
Hello.... I am not from the physics background so was struggling to understand this; you explained it so well that all my basics about NMR is now clear.... Thankyou so much!!!
Glad it was helpful! Thanks for watching.
The best video on NMR. Clear with appropriate examples and concise. Thankyou Sir
Glad it was helpful! Thanks for watching.
This was the only video that helped me better understand the basics of NMR, after watching several videos. Thank you.
Great to hear! Thanks for watching.
he is the best teacher . A true spirit of a mentor . The Real Man .
Thanks for liking.
Your way of explanation is too good. Truly this video is helpful for easy to understand about NMR spectroscopy . I 💜 it. Thank you so much for valuable information.
It is for the first time I could understand The NMR spectroscopy
Thank you sir and expecting more and more videos
Glad it is useful. Thank you. Definitely I will upload more videos, let me know any specific topic you are more interested. Thanks for your interest.
Can u give me ppt of NMR spectroscopy
Hello Sir... superb explanation...😊
u really made NMR so easy.... please do more videos on COSY, NOESY, FT NMR, 13C, SPIN Relaxation Phenomenona and Other concepts that are present in NMR spectroscopy
You are the best teacher.
Great video sir! loved the explanation😍 I also love the way u say "Protawwn"
Thanks!
Hi, Nice explanation.. It would be better to describe why Resonance term is used in the technique.. and please check once regarding "No spin " in "No external magnetic field". The concept is, in no external magnetic field nuclei with 1/2 spin will be arranged in random, when an external magnetic field is applied, the nuclei with 1/2 spin will allign to the field. And further is as described. Ignore it, if it is irrelevant.
Ya, that's a good point. You are correct, as you said, in absence of magnetic field nuclei will have random spin and they produce a small magnetic filed. These nuclei will have intrinsic angular moment but the net spin of all nuclei is very nearer to zero due to random orientation of individual spins. So practically it can be considered as net zero spin compared with nuclei with spin oriented with or opposite to external magnetic filed when it is applied. Thanks a lot for your interest and suggestion.
Explained in simple way..tq sir
The ever best video on NMR ,.... really helpful...thank you soo much 😊
Thank you for this helpful video! I really appreciate it :)
On a side note - I noticed that at 11:09, the m value for I = 0 should be 1, not 0 (as presented).
No I guess I = 0 and m should be = 1 and not 0 as presented
Yes m should be 1
Clear understanding to any chemistry students
Very good explanation
This way of teaching is very excellent
Thanks for liking.
Very good ...in11:28 I=0,m=1 is right
Thank you. Yes, as stated earlier in the video when I =0 , m value is 1. Thanks for watching.
@@egpat Yes right 👍 I watched 3 parts of nmr.very useful
Thank you very much for such informative session
It's my pleasure. Thanks for watching
Excellent explained wow👍
Excellent teaching
Well explained . Concepts are clear sir . Thank you so much
an outsanding explanation tnks sir
Most welcome
Thank u legend 🎉
12:19 i think the multiplicity in case one is m=1 as 2i+1 and i =0 then m is equal to 1
Very nice explanation sir.upload more videos sir
Sir how is value for I calculated?
Super sir.good explanation
Very good sir,ur lecture is very clear& easily understand to studends,thank u verymuch🙏
Sir ... I have a question
When we provide RF the electrons can also absorb the radiation,so why nuclei absorb???
Well explained
You are a good teacher. Thank you
Thank you! Keep watching.
Thank you sir. This video helped me a lot👌
Glad to hear that. Thanks for watching.
Sr why we use RF why not other part of emr
Explained excellently
Glad you liked it. Thanks for watching
Waoooo sir tq so much 👍🙏🙏🙏🙏🙏💐💐 unbelievable sir
Thank u you sir it is really helpful and easy to understand 👍
Sir is 17O^2 is shown by NMR ACTIVE OR RAMAN ACTIVE..... please clarify my query sir
Well explained 👌🏻 ..... Thank u sir 🙂
Glad you liked it. Thanks for watching.
Nitrogen 14 is even, it is given under both odd.
Individually the number of protons are 7 and neutron is also 7 therefore these both are odd
Crystal clear 👌
Thank u sir, explained well..first time I understood the topic spectroscopy .
Glad to hear that. Keep watching.
Beast
vvv nice explaination
You are from South India?
Sir ur explaining very well but try urdu or hindi .as for english so many british are there
Tq soo much sir🥰🥰🥰👍👍
There can be signal for others than half
Awesome sir tqsm 🙏
Welcome, thanks for watching.
Nice teaching 👌👍
Thanks for liking
Which app you are used for making this video 😢
Thank you so much sir...tht helped me to understand the concept
Glad to hear that. Thanks for watching.
The part 4 is not available. nmr spectroscopy in easy way part 4 egpat. How can I get it please
Really good and easy to understand..Thank you sir
Nice explanation sir tq
You're most welcome
i feel am prepared for m MSC Exam now
Excellent
Nmr spectroscopy range please tell
Thank you very much sir
You are welcome.
In case 1 m=1 while comparing the cases there is m=0
Never before ever after...
I wish my our online classes were like this..😁
Nice
We are supplying RF not EMR
Is nmr applicable to compounds that donot contain hydrogen?
Yes, it can be used for silica and other inorganic compounds also.
More than 1H NMR scientist will use 13C NMR...
12:36 tell it to deuterium NMR
Wao Thanku so much
Welcome, thanks for watching
Hlo sir very nice
8:56 doubt
Nmr active nuclei I should not be equal to 0....other than 0 can be anything not only 1/2
When I value is 1 or greater it results in non-spherical charge distribution resulting in signals with variable line width which are not easy to study. But when I=1/2 it leads to spherical charge distribution which is easy to study. That's why nuclei with I =1/2 are selected for NMR spectroscopy.
@@egpat but we talking about nmr signal
Yes, NMR signal better observed with nuclei I as 1/2. Can you give any example of nuclei studied in NMR with different I value?
Boran 11
Chorine 35
Both I=3/2
That's great. You are right. So these are the quadrupolar nuclei. But here in this video we are discussing NMR spectroscopy for pharmaceutical analysis where we study nuclei mainly like proton, and carbon in organic compounds which have I value as 1/2. As you said, quadrupolar nuclei are useful to study inorganic nuclei like Cl and B. Thanks for your interest and watching the video.
Tnx to made tis🔥
You are welcome. thanks for watching
What is I sir
How can 14 will odd sir,,
Individually the number of protons are 7 and neutron is also 7 therefore these both are odd
N is 14 and 7 how can this be included in both odd?
14 is an even number!
Individually the number of protons are 7 and neutron is also 7 therefore these both are odd
14 odd ????
spin quantum number is l not 'i' ...you have been constantly calling it "i"
Nuclear spin quantum no. is denoted by "I"
Bhai orbital angular momentum is "L"
🙏🙏🙏🙏🙏🙏🙏
can I = 3/2 GIVES NMR
yes, and also I=1, but rhe signal is difficult to observe
Nearly all of the information presented in this video is wrong. The claim that you can only observe NMR signals from spin-1/2 nuclei is especially agregious.
how desperate did i have to be to reach here:)
7.26🤣🤣14 is odd number???😬
It is about number of neutrons bro, i.e. 7 and this is odd.
You dumb, sir is talking about neutron number which is odd
It's based on number of protons and neutrons, it's odd in number...
😂😂
Individually the number of protons are 7 and neutron is also 7 therefore these both are odd
Thank you so much sir
Thank u very much sir