2^a = 40 - 2^a 2 . 2^a = 40 2^a = 20 log(2^a) = log(20) a log(2) = log (20) answer = (log(20)) / (Log 2). My advice would be "try not to over think it". I think you are meant to be able to write down the answer easily. (I know it is not always the case, though. Some of the questions I see on youtube are much much harder).
2^a = 40 - 2^a
2 . 2^a = 40
2^a = 20
log(2^a) = log(20)
a log(2) = log (20)
answer = (log(20)) / (Log 2). My advice would be "try not to over think it". I think you are meant to be able to write down the answer easily.
(I know it is not always the case, though. Some of the questions I see on youtube are much much harder).
Nice and beautiful presentation by the beautiful lady.
Thank you for explaining. There is another writing way of the final answer.
a = 2+(log5)/(log2) = 2+(1-log2)/(log2) = 2+1/(log2)-1 = 1 + 1/(log2)
20 2^10 2^2^5 1^2^1 2^1 (a ➖ 2a+1).
a =( log5 +log4) /lo2
1+1/lg2.
Mam log20 (4.5)ok log 4+log 5 how ple explain
It's a law in trigonometry.