though i am not from aktu but your lectures are making complete sense to me....bow down to sir who have done such great work for us during this pandemic🙏🙏
Thank you very much sir!!! I am so grateful to Saraswati Mata that I found out that you have taught EMFT as well as you helped me a lot in my first year and I am so grateful and happy at the same time that Saraswati Mata has allowed me and blessed me to once again gain knowledge from you. We students are so grateful to have you as our teachers sir, I pray to Ram Ji that you and your loved ones succeed in all of your works and may all of you always stay blessed by Ram Ji Jai Siya Ram
Top quality explanation.The thing that's makes you a brilliant teacher is that you explain all the little little concepts that's causes problems(Specially where to use vector sign).Very nice teaching sir ❤
Let take two identical positive charges q1 and q2. There are four points (a), (b), (c), (d) . q1 was initially located at point (a), and q2 was at point (d). Distance between (a) to (d) is taken 1 lightsecond. Distance between (b) and (c) is also about 1 lightsecond ( a little less) (a)...(b)................(c)...(d) q1.................................q2 q1is moved from (a) to (b) toward q2, and in a similar way, q2 is moved from (d) to (c) toward q1. Let say they both were pushed for half a second. (For Energy given) Force on q1=Kq1q2/r^2 (For energy output) Force on q2 =Kq1q2/r'^2 When we think about r, we found that it would be somewhere between distance of (a) - (d) and (b) - (d), as the electric field of q2 will be the same there for 1 second. But for r′, it is between (a)-(d) and (b) - (c), so r>r′. Therefore, the force on q2 is greater. Assume that you are q1 and are pushed for 1/2 second over a very short distance. You will find that field of q2 were the same there for that time period as a result of the velocity of the electric field. So, the q2 for q1 was at (d) during push. Thus, q1's average distance from q2 was somewhere between (a) - (d) and (b) - (d). However, for r′ taken for force on q2 for receiving signal was different from r. Here, I am q2 and was moved at the same time, but when your changed electric field reached me after 1 second, I was also moved closer. So, for me, you moved closer, and I also moved a little closer to you, which makes my average distance from q1 less than r. Seems like output energy(signal) was more than input given on q1. Tell me how the velocity still not violating the law of conservation of energy
Because of this simple explanation of yours, I derived the whole theorem in main exam today.Thank You Sir.
though i am not from aktu but your lectures are making complete sense to me....bow down to sir who have done such great work for us during this pandemic🙏🙏
Sir, you're a gem for all of us students!!
Thank you very much sir!!! I am so grateful to Saraswati Mata that I found out that you have taught EMFT as well as you helped me a lot in my first year and I am so grateful and happy at the same time that Saraswati Mata has allowed me and blessed me to once again gain knowledge from you. We students are so grateful to have you as our teachers sir, I pray to Ram Ji that you and your loved ones succeed in all of your works and may all of you always stay blessed by Ram Ji Jai Siya Ram
Vry nycc sir and thanks a lot. .....m sari videos dekh rha hun and mere sare topic clear ho rahe h apki vaje se sir thanks sirr vry thanks
Top quality explanation.The thing that's makes you a brilliant teacher is that you explain all the little little concepts that's causes problems(Specially where to use vector sign).Very nice teaching sir ❤
Very helpful sir....sir please continue making such vdeos
Maine bohot teacher dekha hai ,per aap jeisa nhi koiee 🙏🙏🙏🙏🙏🙏🙏
Awesome video,pure yt pr aisa Explaination kisi me bhi nhi Kiya ❤
Thank you sir for explaining each and every concept in depth ....it really helped me a lot in understanding the entire topic in a simple and easy
way.
Heartily Thank you sir...
For making (Teaching ) Fully Maxwell Equation..
RCUB Karnataka.
Dhaasu sir jo padaye dil se padaye aur dil se hote huye dimak mei uter gya
Very nice explanation sir I understand it very clearly....after watching lots of videos finally I get perfect explanation of this topic
Bahut Acha Laga ye video Superb explanation aise hi rahiyega sir hamesha👍🙏🙏
Thanks and Also Share with your friends group
Very very thanks sir , you make it so easy that anyone can understand the concept with interest.
In IGNOU textbook it is not very clear. But sir explained in very simple way that I understood very easily.
Amazing explanation! Thank you sir! 🙏🏻
Greatful to you sir for delivering such informative and extremely Helpful Video in this complicated topics...💝💝💗💗
Keep it up, sir.💝
thank you me exam ke phle 45 min apka video dekha 100% sahi likh ke aaya thanks
Very well explanation 👍
I understood very well..... Tysm sir 🙏
Wow sir yahi to chahiye tha bahut achche se samjhaya h🙏👍
Thx sir for this video , it is very easy method to derived poynting vector derivation.
Once again thank you gurudev.
🙏🙏🙏🙏🙏🙏🙏🙏
Really helpful video...easy to understand.
You teaches conceptually, which is the prime need of today's era.
🙏🙏🙏wah sir bahut achhe se apne explain kiya bahut asani se smjh me aa gya ❤❤❤
Thanks for uploading this video sir 😊
Your channel has very helpful content.
Thanks sir very nice you have excellent teaching experience I appreciate you are your talent
I will always be thankful to you
Ye video me 2024 me dekh raha hu 😂😂😂 ab hath n jode
Awesome explanation sir🙏🙏🙏🙏🙏🙏🙏🙏🙏
Sir apka lacture bahut achha samagh me AATA ha thank you sir
Wowww!!!!
Thanks A Lot Sir. Your Videos Are Very Helpful For Me
really outstanding explanation. it is really helpful for me ,
Thanks a lot sir...your explanation is outstanding🙌🏻🙌🏻🙌🏻
Bhut helpful h sr
Very nice 😊
Zabardasst🔥❤️
Sir you are so great 😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊
Welcome
Thanks a lot sir
Very well explain ❤
THANK YOU SIR YOUR VIDEOS ARE EXCELLENT AND EASY TO UNDERSTAND
Bahut bhadiya sir
Very helpful Sir🙏
Thanks sir very nice you have excellent techniques for teaching
Thank you so much sir hamlogo ko itna help krne liye🙏🙏
Thank you sir...cleared all concepts!
nice video sirji
Thanku so much Sir.....I always pass every Semester bcz of U...😌😌
Thanks sir
Sir next video uploaded Diffraction grating pleases
nice guru ji
Thank you sir .
It is best explanation ever.
Thx ..sir ji❤️👍
Thanks sir nice lectures
Nice lecture sir
OSM EXPLANATION
very good approach. Please make videos on Classical mechanics , rigid body, Lagrangian , Hamiltonian and related topics.
Bahut bahut dhanyavad sir
very good explanation sir
Sir you're a legend. Many thanks!
Awesome lecture sir✨🙏🙏💫
Very nice video sir but please upload the lecture of fraunhofer diffraction due to double slit please sir
Thank you Guru g 🙏🙏🙏
Sir b.teach first year first semester ke AKTU university exam m aane vale important questions ke uper video bna dijiyega sirr plzzzzzzzzz
Bhai mila ky important
Hello bhai aapka exam wagaira clear ho gaya
the best sir
Thank You ☺️
Nice video sir
Thanks for this faith
Thank❤ you🥰 so much Sir...for this clear concept and derivation
Manja aa gaya sir
Sir transverse nature of em wave,skin depth
👍
excellent Sir make a video on fresnels equation and waveguides transmission
Thanks a lot sir, very helpful:)
Very nice sir 👍👍👍👍
Thanks sirji
Aap jaise teacher University me kyu NH hote 🥺🥺
Thnk u so much sir😊
We are those lucky people jo sir se live padhte hain
Thanku so much sir🙏
Salutes..
Very nice lucture
Thanksssssss...... sir thanks alot
Sir hats off.
Thanks sir jii
welcome rinku and thanks for taking interest in poynting theorem derivation
Sir important questions bhi karadijie
Thanks sir ....
Welcome
Thanks sir ji 🙏🙏🤘👍🥰
It's really great explanation sir as compare whole videos on UA-cam.....🔥❤️
Thanku sir
Hello sir u r explaining very good but u should use white board with marker , this board and chalk creating unnecessary noice 😔
mujhe tho orgasm ho jata h chalk ki awaj sune kr
Thank you so much
Your method is amazing
👍
I have seen many teachers but not like you,
Best explanation..😁
Thank you so much sir ❤️
Sir plz lorentz gauge and coulomb gauge par video bnaye
Thank you sir
Nice lectures sir ! From pakistan kindly make more more lectures about EMFT / Electrodynamics / E & M
Very nice sir
Let take two identical positive charges q1 and q2. There are four points (a), (b), (c), (d) . q1 was initially located at point (a), and q2 was at point (d). Distance between (a) to (d) is taken 1 lightsecond. Distance between (b) and (c) is also about 1 lightsecond ( a little less)
(a)...(b)................(c)...(d)
q1.................................q2
q1is moved from (a) to (b) toward q2, and in a similar way, q2 is moved from (d) to (c) toward q1. Let say they both were pushed for half a second.
(For Energy given) Force on q1=Kq1q2/r^2
(For energy output) Force on q2 =Kq1q2/r'^2
When we think about r, we found that it would be somewhere between distance of (a) - (d) and (b) - (d), as the electric field of q2 will be the same there for 1 second. But for r′, it is between (a)-(d) and (b) - (c), so r>r′. Therefore, the force on q2 is greater.
Assume that you are q1 and are pushed for 1/2 second over a very short distance. You will find that field of q2 were the same there for that time period as a result of the velocity of the electric field. So, the q2 for q1 was at (d) during push. Thus, q1's average distance from q2 was somewhere between (a) - (d) and (b) - (d).
However, for r′ taken for force on q2 for receiving signal was different from r. Here, I am q2 and was moved at the same time, but when your changed electric field reached me after 1 second, I was also moved closer. So, for me, you moved closer, and I also moved a little closer to you, which makes my average distance from q1 less than r.
Seems like output energy(signal) was more than input given on q1.
Tell me how the velocity still not violating the law of conservation of energy
Thank you sir 🙏🙏🙏
Sir ye emw pressure kya hota h please reply soon.
sir ho apke jaise
SUPER SIR
Tanq so much sir