Розмір відео: 1280 X 720853 X 480640 X 360
Показувати елементи керування програвачем
Автоматичне відтворення
Автоповтор
thank so much for this video. Not only is this a perfect exercise for my exam tomorrow but it has a very interesting result, I would've never expected this
I just got surprised with the result of this integral!Great 🤓Thank you so much dear *QN³* 💖
You the man! 😭🙌🏽💯
Why from z^(n-2) we couldn't define z=0 branch cut?
🤓👍 *Super like*💓
Good Good But , note you can distribute The lim on multiple value , that easy 'Thank you more
Please, I suggest you solve the following integral by complex variable: x^(b-1)/(x^a+1)^s [0, infinity).😀😀😀
Why a b-1 instead of just a b on the exponent?
@@qncubed3 I found the integral like this. I think that is the real challenge.😀
@@qncubed3 I was thinking and I think this integral is better for your channel. x^(a-1)/(x^(a)+1)^b [0, +infinity)
thank so much for this video. Not only is this a perfect exercise for my exam tomorrow but it has a very interesting result, I would've never expected this
I just got surprised with the result of this integral!
Great 🤓
Thank you so much dear *QN³* 💖
You the man! 😭🙌🏽💯
Why from z^(n-2) we couldn't define z=0 branch cut?
🤓
👍 *Super like*
💓
Good Good
But , note you can distribute The lim on multiple value , that easy '
Thank you more
Please, I suggest you solve the following integral by complex variable: x^(b-1)/(x^a+1)^s [0, infinity).😀😀😀
Why a b-1 instead of just a b on the exponent?
@@qncubed3 I found the integral like this. I think that is the real challenge.😀
@@qncubed3 I was thinking and I think this integral is better for your channel. x^(a-1)/(x^(a)+1)^b [0, +infinity)