Star Problem # 1 from Algebra | Problem Series for JEE Aspirants

𝗧𝗲𝗹𝗲𝗴𝗿𝗮𝗺 𝗖𝗵𝗮𝗻𝗻𝗲𝗹 𝗟𝗶𝗻𝗸 : t.me/rankbuddy
𝗗𝗼𝘄𝗻𝗹𝗼𝗮𝗱 𝗼𝘂𝗿 𝗔𝗽𝗽 : play.google.com/store/apps/de...
𝗗𝗼𝘄𝗻𝗹𝗼𝗮𝗱 𝗪𝗶𝗻𝗱𝗼𝘄𝘀 𝗔𝗽𝗽𝗹𝗶𝗰𝗮𝘁𝗶𝗼𝗻 : drive.google.com/file/d/1fYt3...
𝗛𝗲𝗹𝗽𝗹𝗶𝗻𝗲 𝗡𝘂𝗺𝗯𝗲𝗿 : 8800825254
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Free Maths Content For JEE Aspirants
#bhannatmaths #jee2025 #jee

[@BHANNATMATHS]

𝗧𝗲𝗹𝗲𝗴𝗿𝗮𝗺 𝗖𝗵𝗮𝗻𝗻𝗲𝗹 𝗟𝗶𝗻𝗸 : t.me/rankbuddy
𝗗𝗼𝘄𝗻𝗹𝗼𝗮𝗱 𝗼𝘂𝗿 𝗔𝗽𝗽 : play.google.com/store/apps/details?id=rankbuddy.com
𝗗𝗼𝘄𝗻𝗹𝗼𝗮𝗱 𝗪𝗶𝗻𝗱𝗼𝘄𝘀 𝗔𝗽𝗽𝗹𝗶𝗰𝗮𝘁𝗶𝗼𝗻 : drive.google.com/file/d/1fYt3pekZ6CTJZAkY0U5Mwn51N5PnO3n7/view?usp=sharing
𝗛𝗲𝗹𝗽𝗹𝗶𝗻𝗲 𝗡𝘂𝗺𝗯𝗲𝗿 : 8800825254

[@abhilashsatapathy]

Guru dev ek sawal main fans gaya hoon
show that 2sinx+tanx >= 3x 0

[@sneaky6969]

Sir star problem 2 me
Last me ek trigo equation bn rhi h
Cosec(3x) + 1/2[sec(x)] =1
Where x=pi/n
Ye equation solve nhi hori h sir
Plz correct me if i am wrong

[@HarshChauhanOfficial11]

Same question given by Ashish Agrawal sir in lecture 3 in basic maths
From prayas jee 2025

[@ParveenKumar-or5rp]

Yes also in lakshya jee 2024

[@trolllogic890]

😂

[@JEEAdvanced01]

हां भाई मैं भी prayash 2025 batch में हूं पर sir ने दूसरे तरीके से करवाया है

[@lynxprime1778]

Love this series

[@H.R.Everything]

Gajab.

[@AkashVerma-bp1mq]

Appreciated content guru ji

[@KrishnaDubey527]

came in Aakash Adv FTS

[@MdSaif-sm1kp]

Same problem Ashish sir ne prayas batch me basic Mathematics me bhi karwaya hai

[@mathist-monster101]

Thank you Sir❤❤❤

[@AmjadMiah-yf8is]

Thank you guruji ❤️

[@Pradip-sy3wl]

Thanks guru ji

[@vastavarya]

Sir I mailed you solution of this question

[@abhijitgoswami2279]

Sir ka mail id kaha pe hai ,,, plzzzz batana ???

[@VaishnaviM-ch2hc]

​@@abhijitgoswami2279About section mein hai

[@LsEagle18]

Thank you so much sir

[@smeettiple8154]

Thank you sir

[@pramodsingh7569]

Thanks

[@godknowsmyname6084]

Alternative:
let x and 1/x be two positive numbers since x>0
By using am and gm we get that
x+1/x≥2 so the min is 2---------->1
And now similarly if we do taking x^3,1/x^3 and x^6,1/x^6
We would end up getting the minimum values of these as 2
So by substituting in the equation we get the following
2^6-4/2^3+2
i.e; 60/10 and which is
6 ans.

[@YASH-SHARMA.iitian]

Aese hi mene kiya

[@iamyv555]

Good mera bhi yahi approch tha maine socha kisi ka nhi hai but tera hai well done🔥

[@ishaankumar4587]

Its a wrong approach tho

[@ishaankumar4587]

For example if an equation is (x+1/x)/x²+x+1 the min value of function above and below will be diff

[@ishaankumar4587]

This approach just makes no sense

[@Education-35]

Sir itna guumane ki kya zarurat thi
AM>_GM
Jindabaad hai hamare paas
😎😎😎
JEE aspirant
2025
🔥🔥🔥

[@SAHILGAMMER..]

Sir mara math bohot weak tha but jab sa ap ko follow Kiya lag ta Hain ma maths ma kab weak tha love you sir ❤❤

[@lakshyadhimanld027]

Easy problem

[@shikhasharma9526]

Solved and got answer but already in coaching so no need to mail but enjoy solving the questions on your channel

[@suramyashee7367]

same approach but i put x+/x =t

[@Amit_368B]

Me Also do that 😊

[@shoryagoel1411]

Darpok PPL
Direct socho direct🌚

[@hamzasiddiqui4931]

Matched sir

[@SaurabhYadav-hr9nk]

I am in class 9 but I got very happiness to solve this

[@mayukachha]

Sir given ek odd fuction hai to tending to zero par is ki value zero sa pas hogi the us logic sa ham kha sakthe hai na is equation ki value nearly zero honi chaiya for min value

[@AnkurSingh-wy2pl]

Dy/dx=o for minima

[@DivyanshKeshari-cc9rx]

❤

[@pepperjohnns]

Use AM-GM concept, u get the answer directly

[@JitendraKumar0013]

Same question Ashish Aggarwal sir droppers jee but different approach

[@Mr.OM_2.0]

sir maine am gm se 5 sec me sahi solve kardiya

[@user-cx3jy6un7g]

Sir currently i am unable to solve these type of questions can you please make a video on how do we build our thinking towards these questions

[@rajjhalani4354]

Sir star problem nhi aayi abhi tk tg pe....kb tk aayegi??

[@rajjhalani4354]

Sir I mailed u this answer yesterday only.

[@DarnaZaruriHai4208]

sir I solved by myself but I take your biggest hint that is let alpha and beta 😢😢

[@KritarthShuklaA]

sir agr isme x=1(x ki minimum value) put karde tab bhi answer aaraha 6 hai ,,,,,, to sir ye approach sahi hai ya galat?????????

[@ChetanSingh-pb7td]

Easy

[@DeepeshShashawat-re9jd]

Answer of today's question of trigonometry is 7

[@Naman_shukla410]

Sir mene dy/dx=0 kiya lekin answer nhi aa rha . Please anyone send the solution by this method🙏

[@AjaySingh-ji3xp]

I have solved this problem 3 years ago by am Gm concept

[@nandansabharwal139]

i also solved by that method as sequence and series chapter is going on in my coaching...it seemed to be easier but a bit lengthy than the given method

[@mohitchhiroliya5586]

SIR AOD KE LECTURES COMPELETE KERWA DIJIYE PLEASE

[@abhisinha-qx5rn]

I have a question for curious personality ; x^0.5 +Y^0.5 =18, X+Y=164 then find the value of x and y

[@Amardeep_singh360]

X= 100, 64 both value can satisfy this relation.

[@abhisinha-qx5rn]

@@Amardeep_singh360 That's right

[@shephalikashyap2243]

A similar question was solved in only shakuntala devi solved problem by aman sir go watch it

[@Utsav_D_Yadav]

I went with a simpleton approach using binomial and used limit x tends to 0+, I need to work on Approaches. 😅😢

[@unknownperson-zx5lo]

6

[@hemanth9158.]

Sir give solution of
f(y)-f(x)=(x^x/y^y).f(y^y/x^x). Given f'(1)=1

[@ramenguy6827]

All those saying putting x+1/x=2
In the equation you all are wrong you can't use the minima of one function in the numerator and denominator

[@animationera6009]

Damn too easy x+1/x is always >=2😂

[@AjaySingh-ji3xp]

Minimum 6 answer

[@jordansrivastav19]

Kisi bhi number me uska reciprocal krkr add krenge to wo hamesha greater than equal to 2 hoga agr wahh number positive hai to...!
By using this concept we can answer in max 10 sec 🤫

[@LSPD839]

bhai ye samjhao mujhe samjh nhi aaya mai isske baare me aware nhi hu

[@whaddafaq]

​@@LSPD839 bhai uska mtlb hai - x + 1/x ≥ 2 . Iska proof bhi thnhe google pr mil jayega

[@ROHITKINGC]

​@@whaddafaqlol iska kaunsa proof bro. x>0 hai to x+1/x mein 1 dalo to 2, aur badhaate jao to >2

[@shivamchahal3302]

@@ROHITKINGClol am-gm se proof hota h .

[@whaddafaq]

@@ROHITKINGC koi irrational value rkh du to kya bolega fir chomu 🤡

[@naitik_singh_]

x+1/x ko hole square me kyu likha minimum value to pahale hi 2 dikh rahi thi

[@d.j.b.drawingofficial7886]

I have solved this but I didn't know how to send the ans to you .
Main bohot ummed se aya tha apko send karne .
Telegram account hain nahi ..
Download karne ko jagah hain nahi .
Mail pehle kisiko Kiya nahi ,
Aur abhi try Kiya mail karne ka abb Gmail synk ho raha hain nahi

[@motivationmastery5442]

Can we solve it with AM GM inequalities?? 🤔🤔

[@Indian-357]

Complex hojayega

[@Eren15232]

X+1/x=t

[@imsparshyt]

lmaoooooooooo i did this same question some days ago. this was given by Ashish sir in pw prayas batch

[@AjaySingh-ji3xp]

Itna easy sawal hain maine ise bana kalam uthaye solve kar diya kyunki yeh sawal maine pehle kisi coaching ki study material se lagaya tha

[@d.j.b.drawingofficial7886]

Aap konsi class main hain ?

[@ElasticGum]

Konsi coaching ka material?

[@AjaySingh-ji3xp]

@@ElasticGum Allen Career institute kota Rajasthan study material me diya tha mere bhai ki coaching ki sheet me tha

[@ElasticGum]

@@AjaySingh-ji3xpohh Accha

[@DineshBehera870]

Thank you sir I got confidence from this question❤❤❤❤

[@dixit....family...wonders110]

Koi kal ka ques btado pls, i am not on telegram

[@PHOENIX-vq1rv]

Abhi dala nahi sir ne

[@sagarrajput7760]

Sir I solved with AM GM inequality

[@sagarrajput7760]

Is it possible

[@godknowsmyname6084]

Yep I did using am and gm

[@adarshraj7190]

solved under 1 minutes ngl

[@TheShubhamVishwakarma]

Ans 6

[@TheShubhamVishwakarma]

Minimum value of( x + 1/x ) =2 at x=1
For x >0

[@KrishNarsaria]

Black book problem

[@anvitmagadum7003]

Sir can we solve using derivatives?

[@AlokBurnwal-gp2pg]

Our unacademy module has this exact question.....

[@jyotirathor7930]

Sir question nahi aaya

[@shivanshsingh6959]

I solve this question with the help of differentiation

[@shoryagoel1411]

Farzi qn😂

[@GaganGarg-bx2ps]

Sir i mailed you the solution of this question

[@toofaaniHINDU]

Good

[@sagarrajput7760]

Where should we mail the solution