I remember when I was in college (about 35 years ago) attending the Electricity 101 class, all seemed so cryptic and confusing but you explain just in ten minutes what took me days to understand, and everything is so clear that I wish I had a teacher like you. Awesome. Thank you.
I love how you explain your answer for this problem. I hope you can create more example problems concerning different theorems (Branch current, maxwell, kcl/kvl, nodal analysis, superposition, thevenin and norton's).
I was watching it thinking, "wow, pretty darn good, writing backwards behind plexiglass," and then, "ooh, he's lefty too. That's rare!" and then, "oh. Flipped the video." Regardless, nice explanation of the concepts and showing how to "see" into the circuit from the Thevenin check point perspective.
So i am confused about how the thevenin voltage is between terminals A and B, but when you re-insert the load resistor in between these two terminals, the thevenin voltage does not drop across the load resistor. May you explain this to me? thanks
Excellent explanations. Knowing that there are any number of ways to solve the ckt, the simpler (thus faster) method instead of Superposition would have been to use “Special Thevenin” without the 4K and then to stick it back in to come up with a final Vth answer. He could even have left the 4K in and used Millman for a quicker solution.
hi professor, now I am a student. In an exam, I solved a problem like you in the video, but my professor think that I am wrong. I am not sure if I am wrong or my prefessor is wrong. May I send you my solution and you check it if my solution is ok or not? thanks
@@ElectronXLab it's not my assignment, just a question in an exam, my professor's answer is different from mine. So I wanted you to see my solution and find my errors. ok forget it. Thanks anyway.
Because the 10k is in series with the voltage source and since we want to make the resistors in series to the voltage source, we can just pick up the 2k and 4k that are in parallel, sum them up (i.e 2k//4k), the result will be in series with both the 10k and the voltage source (which is what we intended) so by finding the voltage drop across the 1.333 (i.e 2k//4k) is the same as Vab
YOU DID NOT DO THE MATH AS HOW YOU GOT THE 2.857. JUST BECAUSE IT IS UNDERSTOOD BY YOU DOES NOT MEAN IT IS UNDERSTOOD BY SOMEONE ELSE PLEASE BE DETAILED IN ALL YOUR PROBLEM SOLVING.
All over youtube, this is the only channel whose explanation is beginner friendly.
I remember when I was in college (about 35 years ago) attending the Electricity 101 class, all seemed so cryptic and confusing but you explain just in ten minutes what took me days to understand, and everything is so clear that I wish I had a teacher like you. Awesome. Thank you.
I'm glad to have helped, sometimes just seeing things the second (or third) time around makes things make sense.
I love how you explain your answer for this problem. I hope you can create more example problems concerning different theorems (Branch current, maxwell, kcl/kvl, nodal analysis, superposition, thevenin and norton's).
thanks alot this video is so much easier to understand than most
Glad it helped!
Wait for the RTH step how is 10k in parallel with 2k?
Because there is node there.
Because the source is shut down, so basically the nodes that link 10K and 2K are the same, and for this reason we can say they're in parallel
no one gonna talk about how he's writing backwards?
I wish I had the skill to write backwards like that. I'm just using software to mirror the video
@@ElectronXLab That's genius!!
I was watching it thinking, "wow, pretty darn good, writing backwards behind plexiglass," and then, "ooh, he's lefty too. That's rare!" and then, "oh. Flipped the video."
Regardless, nice explanation of the concepts and showing how to "see" into the circuit from the Thevenin check point perspective.
@@ElectronXLab 👍👍👍
How is the 2k in parallel? It contadicts other videos. If its a speci direction due to removing Vs, thsy should be noted
when you short the voltage sources, the 2k is in parallel with the 10k and the 4k resistors
How????????????????????????@@ElectronXLab
@@ElectronXLabsuppose the 2k was shifted so that it was lying up and to the right of the 4k. Would it now be in series to the other 2 resistors?
@@otriyoghosh bro just drop out
Thank you for this precious video Now I understand how to slove complex circuit thevnin theorem
So i am confused about how the thevenin voltage is between terminals A and B, but when you re-insert the load resistor in between these two terminals, the thevenin voltage does not drop across the load resistor. May you explain this to me? thanks
Excellent explanations. Knowing that there are any number of ways to solve the ckt, the simpler (thus faster) method instead of Superposition would have been to use “Special Thevenin” without the 4K and then to stick it back in to come up with a final Vth answer. He could even have left the 4K in and used Millman for a quicker solution.
Great tip!
I'm lost and I've been an engineer 40 years... never needed this cause I never could believe it
am confused the Rth is equal to Req. How is the parallel sum of all resistors 1.18k ohms
Thank you so much I understood perfectly
Why do you use voltage division for superposition? For example, for the 10V source, why would V_AB not get affected by the 2K ohm resistor?
4:05 How did you get 2.857K as the combonation of the 10K and 4K?
(10000^-1 + 4000^-1)^-1 = 2857
@@ElectronXLabI got another question do you have a video that is solely for thevenin?
@@foryourculture_ this one maybe: ua-cam.com/video/hfyfThbrqos/v-deo.htmlsi=fVvYrxVFgQKT_5sh
Great video as always! Thank you
Thanks again! I'm really glad my videos are continuing to be helpful
Thankyou, that was brilliantly explained!
I see why 4k||10k but wouldn't the result be in series with the 2k resistor? ((4||10)+2)
yes
This was life saving, Thanks!
Just wondering, is VL the same as VAB? What's VL analyzing for? I was thinking VL should be equal to VAB so that their voltage shall be the same...
New subscriber unlocked
Thanks!
You bet! Thank You!
Where did the 12k come from?
Great video!! Helped so much.
Thank you sir for your help!!!
Why is it -10 and not +10 at 4:22 but it is +24 at 5.23 when the current is going the same way on both?
For the initial circuit, I put the 10V source "upside down" - positive at the bottom and negative at the top.
What will be the Vth if it was between 10k ohm ?
How did you get the 2.85?
It's the parallel combination of the 10k and 4k resistors
damn best explanation i got for this,
this was helpful 🤜🤛
Great Teacher
Is the VAb solved by using superposition theorem?
Yes!But it is just only use simple node voltage way to find out Eab !
Great video!
Sir, what happened 1.33 Kilo ohm?
Great vid legend
Well explained
Thank you Sir
YOU ARE GOATED
Thank you
You're welcome
hi professor, now I am a student. In an exam, I solved a problem like you in the video, but my professor think that I am wrong. I am not sure if I am wrong or my prefessor is wrong. May I send you my solution and you check it if my solution is ok or not? thanks
I'm sorry, I won't be able to help you with your assignment. Hopefully you can find a classmate to work with.
@@ElectronXLab it's not my assignment, just a question in an exam, my professor's answer is different from mine. So I wanted you to see my solution and find my errors. ok forget it. Thanks anyway.
Thank sir but u have to be slow and clear when lecturing please
For those guys confused
Rth=2.5536ohm
Wow... I wish UA-cam (and ElectronX Lab) would have been around when I was in EE (40 years back).
✨🏅🏆
Why did you do 2k plus 4k instead of 10k+4k?
Because the 10k is in series with the voltage source and since we want to make the resistors in series to the voltage source, we can just pick up the 2k and 4k that are in parallel, sum them up (i.e 2k//4k), the result will be in series with both the 10k and the voltage source (which is what we intended) so by finding the voltage drop across the 1.333 (i.e 2k//4k) is the same as Vab
YOU DID NOT DO THE MATH AS HOW YOU GOT THE 2.857. JUST BECAUSE IT IS UNDERSTOOD BY YOU DOES NOT MEAN IT IS UNDERSTOOD BY SOMEONE ELSE PLEASE BE DETAILED IN ALL YOUR PROBLEM SOLVING.