OCR A Level Chemistry 2022 Paper 1 Walkthrough (Periodic table, elements and physical chemistry)

In this video I go through the OCR A level Chemistry 2022 paper 1 (Periodic table, elements and physical chemistry) paper.
I've added chapters to the video for ease of access to the questions you need to go through as this is quite a long video.
Link For the Inorganic ions and Complexes colours sheet: www.ocr.org.uk/Images/598991-...

[@ravaaaa555]

Thank you so much, you explain everything really well. deserved my subscribe, keep it going!

[@applegoos]

1:06:34 I'm no chemistry expert but i don't think it needs to be a drastic negative to be feasible at all temperatures. Temperatures bellow 0K are physically not possible as it would mean the particles have negative energy so if the required temp is any number that is negative I'm pretty sure its feasible at all temps.

[@ChemKit]

Yeah that was pointed out before by someone else but that is true, it is impossible as the particles have no kinetic energy but thanks for pointing that out!

[@moninico]

Thank you so much!!!!

[@momomxchi]

Thank u soo muchh!!!!!

[@alicia7552]

Thank you!!!

[@aryangupta2481]

ty very helpful

[@cwrwn928]

Thanks

[@hxvoc_7708]

for 1:11:44 why dont we multiply 500 by avagadros constant. Condisering the units its kj divide by mols so to get rid of moles wont you times by 1 mol(avagadros) ?

[@randomuser12455]

u divide because it is kg/mol and mol X avagadro constant is number of molecules so in theory if you divide by avagadros constant you would be doing (kj)/(mol X avagadro constant) which is equal to kj/molecule kj per molecule which is just kj as molecules do not have a unit

[@user-bz6ke9qp1l]

thanks

[@OGGY365]

Why is Cu (II) + I- not equal to CuI2

[@deuterium4.028]

Thank you! :)

[@ChemKit]

No worries

[@kripaupadhyay6596]

for 7 tho, say we didnt know it was exothermic, how would we differentiate from it being pos or neg

[@ChemKit]

From the equation we can see it’s a combustion reaction because an alkane reacts with oxygen to produce co2 and h2o and combustion reactions are always exothermic

[@R333xna]

@@ChemKitsir I thought it would be reactants - products for exo and products - reactants for endo am I wrong?

[@evangelinepiper6630]

Why is there not a negative one charge on the empirical formula for thentramsition metal question 2:16

[@evangelinepiper6630]

I mean plus one

[@jas67bir]

Hi Can you do the other papers from this year

[@ChemKit]

Sure

[@poy110]

Will you do paper 2 and 3 too

[@ChemKit]

Yes I’m currently recording paper 2 I should hope to make paper 3 shortly after

[@JohnSmithaj]

🙏🙏

[@anisaxahmed]

This is great, could you do one on OCR B Salters pls

[@ChemKit]

Sure I’ll try to make the 2022 OCR B papers after I finish OCR A

[@bellasophiex7846]

at 2hrs 6mins why did you multiple mol by 5 for CaCO3 because if its 1:5 wouldn't you divide by 5?

[@ChemKit]

Because to produce one mole of Z you need 5 moles of CaCO3

[@ChemKit]

Because you can notice this by the calcium’s Z has 5 calcium’s whereas CaCO3 has 1

[@maxyboy2933]

For No.10 it says that it’s condensation of ammonia gas, would that not mean that it’s H2(g) + 3N2(g) = 2NH3(g)? Or is my equation wrong?
P.s thanks for the video it’s great!

[@ChemKit]

As you said it’s a condensation reaction it’s a physical change of NH3 not a combination of the products you mentioned to form NH3. So for condensation it would be NH3(g) => NH3(l)
Hopefully this makes sense and thank you hope the video helped!

[@iwishtobesupernatural3212]

Thank you. Please could you do one for paper 2?

[@ChemKit]

Ok

[@qafrd5487]

1:06:40 Its impossible for T to be below 0K. Its like saying particles have -ve KE.
But Thanks for the video! Really helpful

[@ChemKit]

Oh yeah true thanks for pointing that out it completely slipped my mind! I’m glad the video helped

[@TommyGee.]

Why does nobody do ocr B paper walkthroughs?

[@ChemKit]

Yh true we need ocr B

[@diyakapoor5504]

please do one for paper 2 and 3🙏

[@ChemKit]

Ok

[@arellayolanda8901]

in question 4 as oxygen is O3 why do we still divide it by 32 as we would O2 it really confuses me as surely we should divide by 48

[@ChemKit]

Is this for the multiple choice question 4?

[@ChemKit]

Because the oxygen is O2 on the products side and not ozone (O3)

[@arellayolanda8901]

@@ChemKit yes thank you so much that makes more sense! :)

[@floxwood3958]

@@ChemKitwhat do you mean by the product side? Is it because it states it’s an oxide in the question?

[@masoud1082]

at 1:04:50 why did you assume delta h = t delta s @ChemKit

[@nomanchaudry2494]

use the Gibbs formula delta G=delta H - T delta S. then equate delta G to 0 to find the temperatures of feasibility and then rearrange for T delta S. that's how he got to that stage. hope that helps

[@littlebirdonyourdoorstep]

Thank you!!!!