ChemKit
ChemKit
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OCR A Level Chemistry 2022 Paper 2 │ PART 2 (Q16-Q18) Walkthrough.
In this video I go through the OCR A level Chemistry 2022 paper 2 (Synthesis & Analytical Techniques) paper.
Please make any requests for papers you guys would like me to make a tutorial on, in the comments.
OCR A Level Chemistry Data Sheet: www.ocr.org.uk/Images/643856-data-booklet.pdf
Subscribe you opened the description box anyway 💀
Переглядів: 999

Відео

OCR A Level Chemistry 2022 Paper 2 Part 1 (MCQ) Walkthrough
Переглядів 1,6 тис.4 місяці тому
In this video I go through the OCR A level chemistry 2022 paper 2 (Synthesis & Analytical Techniques). I have now split videos into parts to make it easy to find the question you’re looking for and helps me when I edit the videos, thanks for all the support in the comments as this paper was highly requested!
OCR A Level Chemistry 2022 Paper 1 Walkthrough (Periodic table, elements and physical chemistry)
Переглядів 16 тис.10 місяців тому
In this video I go through the OCR A level Chemistry 2022 paper 1 (Periodic table, elements and physical chemistry) paper. I've added chapters to the video for ease of access to the questions you need to go through as this is quite a long video. Link For the Inorganic ions and Complexes colours sheet: www.ocr.org.uk/Images/598991-colours-of-inorganic-ions-and-complexes-poster-.pdf
OCR AS Level Chemistry 2022 Paper 2 Walkthrough (Depth In Chemistry)
Переглядів 2,6 тис.11 місяців тому
In this video I go through the OCR AS Level Chemistry 2022 Paper 2. I will now move onto the three A-level Papers for the 2022 series. If there are any other chemistry papers you would like me to walkthrough please let me know in the comments.
OCR AS Level Chemistry 2022 Paper 1 Walkthrough (Breadth In Chemistry)
Переглядів 4,5 тис.11 місяців тому
In this video I go through the OCR AS Level Chemistry 2022 Paper 1. I will make the video for paper 2 soon, and move onto the three A-level Papers. If there are any other chemistry papers you would like me to walkthrough please let me know in the comments.

КОМЕНТАРІ

  • @anxccc5310
    @anxccc5310 3 місяці тому

    question 4a). how is it less gas moles to the right?

  • @Minecraftsteve56
    @Minecraftsteve56 3 місяці тому

    Can you do walkthroughs for ocr b?

  • @peachesandapricots5010
    @peachesandapricots5010 3 місяці тому

    thank you so much for your help Sir 😊

  • @thebros1232
    @thebros1232 3 місяці тому

    For the double bond group, is it necessary to have it on the top for the optical isomer in 16biv or can you put it anywhere as long as the groups swap for the left box

  • @JohnSmithaj
    @JohnSmithaj 3 місяці тому

    🙏🙏

  • @Equalhippo3156
    @Equalhippo3156 3 місяці тому

    I dont get why you divided by 0.05 in q25a if both are in excess and none are limiting

  • @OGGY365
    @OGGY365 3 місяці тому

    Why is Cu (II) + I- not equal to CuI2

  • @applegoos
    @applegoos 3 місяці тому

    1:06:34 I'm no chemistry expert but i don't think it needs to be a drastic negative to be feasible at all temperatures. Temperatures bellow 0K are physically not possible as it would mean the particles have negative energy so if the required temp is any number that is negative I'm pretty sure its feasible at all temps.

    • @ChemKit
      @ChemKit 3 місяці тому

      Yeah that was pointed out before by someone else but that is true, it is impossible as the particles have no kinetic energy but thanks for pointing that out!

  • @peaceandlovewillhealtheworld
    @peaceandlovewillhealtheworld 3 місяці тому

    Thank you!!!!

  • @evangelinepiper6630
    @evangelinepiper6630 3 місяці тому

    Why is there not a negative one charge on the empirical formula for thentramsition metal question 2:16

  • @TommyGee.
    @TommyGee. 3 місяці тому

    Why does nobody do ocr B paper walkthroughs?

    • @ChemKit
      @ChemKit 3 місяці тому

      Yh true we need ocr B

  • @maxyboy2933
    @maxyboy2933 3 місяці тому

    For No.10 it says that it’s condensation of ammonia gas, would that not mean that it’s H2(g) + 3N2(g) = 2NH3(g)? Or is my equation wrong? P.s thanks for the video it’s great!

    • @ChemKit
      @ChemKit 3 місяці тому

      As you said it’s a condensation reaction it’s a physical change of NH3 not a combination of the products you mentioned to form NH3. So for condensation it would be NH3(g) => NH3(l) Hopefully this makes sense and thank you hope the video helped!

  • @hxvoc_7708
    @hxvoc_7708 3 місяці тому

    for 1:11:44 why dont we multiply 500 by avagadros constant. Condisering the units its kj divide by mols so to get rid of moles wont you times by 1 mol(avagadros) ?

    • @randomuser12455
      @randomuser12455 3 місяці тому

      u divide because it is kg/mol and mol X avagadro constant is number of molecules so in theory if you divide by avagadros constant you would be doing (kj)/(mol X avagadro constant) which is equal to kj/molecule kj per molecule which is just kj as molecules do not have a unit

  • @deuterium4.028
    @deuterium4.028 4 місяці тому

    Thank you! :)

    • @ChemKit
      @ChemKit 3 місяці тому

      No worries

  • @qafrd5487
    @qafrd5487 4 місяці тому

    1:06:40 Its impossible for T to be below 0K. Its like saying particles have -ve KE. But Thanks for the video! Really helpful

    • @ChemKit
      @ChemKit 3 місяці тому

      Oh yeah true thanks for pointing that out it completely slipped my mind! I’m glad the video helped

  • @DogKann
    @DogKann 4 місяці тому

    Thank you kind sir

  • @bellasophiex7846
    @bellasophiex7846 4 місяці тому

    When will u upload the rest please and thank you 🙏

    • @ChemKit
      @ChemKit 4 місяці тому

      Should be in the next few days hopefully

  • @bellasophiex7846
    @bellasophiex7846 4 місяці тому

    Amazing

  • @bellasophiex7846
    @bellasophiex7846 4 місяці тому

    For question 7, if you weren’t given the options, is there a way to also find the number of carbons like you did for the 12 hydrogens? Please

    • @ChemKit
      @ChemKit 4 місяці тому

      Yes by using the general formula of alkanes which is CnH2n+2 since you know there are 12 hydrogens: 2n+2 = 12 -> (from H2n+2) Therefore rearranging for n: n = 5 so there are 5 carbons

    • @ChemKit
      @ChemKit 4 місяці тому

      Because they told you it’s an alkane in this instance

  • @bellasophiex7846
    @bellasophiex7846 4 місяці тому

    at 2hrs 6mins why did you multiple mol by 5 for CaCO3 because if its 1:5 wouldn't you divide by 5?

    • @ChemKit
      @ChemKit 4 місяці тому

      Because to produce one mole of Z you need 5 moles of CaCO3

    • @ChemKit
      @ChemKit 4 місяці тому

      Because you can notice this by the calcium’s Z has 5 calcium’s whereas CaCO3 has 1

  • @Mandurance
    @Mandurance 4 місяці тому

    Thanks boss

  • @ChemKit
    @ChemKit 4 місяці тому

    Question 9: The answer should be C as the nitrile group also gets hydrogenated to an amine group to give us an extra 4 hydrogens on top of the 4 extra hydrogens from the hydrogenation of the alkenes to give us 8 added hydrogens and so we have 4 x H2 for the equation, so we do 4 x 0.05 to give us 0.2 and then we do 0.2 x 24 to give us 4.80dm3 and hence C. I’ll remake a video on that question to make it more clearer. Thanks to @katarinajana3618 for pointing that out

    • @chloeb6093
      @chloeb6093 4 місяці тому

      I thought reduction of nitriles only happens with high temp and pressure / nickel catalyst

    • @Equalhippo3156
      @Equalhippo3156 3 місяці тому

      @@chloeb6093 exactly

  • @katrinajana3618
    @katrinajana3618 4 місяці тому

    For Q9 the answer is C

    • @ChemKit
      @ChemKit 4 місяці тому

      Oh it is thanks for pointing it out I completely overlooked the hydrogenation of the CN as well

  • @arellayolanda8901
    @arellayolanda8901 4 місяці тому

    in question 4 as oxygen is O3 why do we still divide it by 32 as we would O2 it really confuses me as surely we should divide by 48

    • @ChemKit
      @ChemKit 4 місяці тому

      Is this for the multiple choice question 4?

    • @ChemKit
      @ChemKit 4 місяці тому

      Because the oxygen is O2 on the products side and not ozone (O3)

    • @arellayolanda8901
      @arellayolanda8901 4 місяці тому

      @@ChemKit yes thank you so much that makes more sense! :)

    • @floxwood3958
      @floxwood3958 4 місяці тому

      @@ChemKitwhat do you mean by the product side? Is it because it states it’s an oxide in the question?

  • @danielzv588
    @danielzv588 4 місяці тому

    when are you going to upload part 2?

    • @ChemKit
      @ChemKit 4 місяці тому

      I’m recording it now so probably in a day or 2

    • @danielzv588
      @danielzv588 4 місяці тому

      @@ChemKit can u upload it plss

    • @ChemKit
      @ChemKit 4 місяці тому

      @@danielzv588Yh sorry it’s coming out today I was very busy last week

  • @diyakapoor5504
    @diyakapoor5504 4 місяці тому

    please do one for paper 2 and 3🙏

  • @masoud1082
    @masoud1082 5 місяців тому

    at 1:04:50 why did you assume delta h = t delta s @ChemKit

    • @nomanchaudry2494
      @nomanchaudry2494 5 місяців тому

      use the Gibbs formula delta G=delta H - T delta S. then equate delta G to 0 to find the temperatures of feasibility and then rearrange for T delta S. that's how he got to that stage. hope that helps

  • @omar6115
    @omar6115 5 місяців тому

    Bro please balance your audio .

  • @adamkhandoc
    @adamkhandoc 5 місяців тому

    For 5ci how are the moles of bromobutane the actual yield and not theoretical ?

  • @adamkhandoc
    @adamkhandoc 5 місяців тому

    my goat

  • @jas67bir
    @jas67bir 5 місяців тому

    Hi Can you do the other papers from this year

  • @aminuh
    @aminuh 5 місяців тому

    there's not a lot of views on it but sir this has helped a lot, so thank you!

  • @kripaupadhyay6596
    @kripaupadhyay6596 6 місяців тому

    for 7 tho, say we didnt know it was exothermic, how would we differentiate from it being pos or neg

    • @ChemKit
      @ChemKit 4 місяці тому

      From the equation we can see it’s a combustion reaction because an alkane reacts with oxygen to produce co2 and h2o and combustion reactions are always exothermic

    • @R333xna
      @R333xna 4 місяці тому

      @@ChemKitsir I thought it would be reactants - products for exo and products - reactants for endo am I wrong?

  • @ihavenoname5958
    @ihavenoname5958 6 місяців тому

    This guys saving my brain cells

  • @poy110
    @poy110 7 місяців тому

    Will you do paper 2 and 3 too

    • @ChemKit
      @ChemKit 4 місяці тому

      Yes I’m currently recording paper 2 I should hope to make paper 3 shortly after

  • @iwishtobesupernatural3212
    @iwishtobesupernatural3212 8 місяців тому

    Thank you. Please could you do one for paper 2?

  • @momomxchi
    @momomxchi 8 місяців тому

    Thank u soo muchh!!!!!

  • @moninico
    @moninico 8 місяців тому

    Thank you so much!!!!

  • @alicia7552
    @alicia7552 8 місяців тому

    Thank you!!!

  • @anisaxahmed
    @anisaxahmed 8 місяців тому

    This is great, could you do one on OCR B Salters pls

    • @ChemKit
      @ChemKit 8 місяців тому

      Sure I’ll try to make the 2022 OCR B papers after I finish OCR A

  • @aryangupta2481
    @aryangupta2481 8 місяців тому

    ty very helpful

  • @ravaaaa555
    @ravaaaa555 9 місяців тому

    Thank you so much, you explain everything really well. deserved my subscribe, keep it going!

  • @_hxsna_5349
    @_hxsna_5349 9 місяців тому

    Thank you so much this is really helpful , can you please do the 2021 and 2020 AS chem papers

  • @aftanprodhan
    @aftanprodhan 9 місяців тому

    thanks

  • @cwrwn928
    @cwrwn928 9 місяців тому

    Thanks

  • @ChemKit
    @ChemKit 10 місяців тому

    *MISTAKE IN QUESTIONS 9 AND 10* QUESTION 9) The answer should be D as I multiplied 2.41x10^24 by 2 instead of 3. The reason you multiply it by 3 is because you have 1 mole of Mg2+ and 2Cl- QUESTION 10) The answer should also be D, as chemical reactivity is not a viable explanation as the question asks about boiling points. The reason D is correct is because as we go down Group 7 the number of electrons start to increase, and so London forces also start to increase therefore more energy is required to overcome the Intermolecular (London) forces, and so it has a higher boiling point. Hopefully this cleared up any questions on the mistakes I made, and sorry about that I'll try my best to make sure this doesn't happen again. Also thanks to @erkanfnr5872 for pointing it out.

  • @erkanfnr
    @erkanfnr 10 місяців тому

    9 is D is 3x4x6.02x10^23 and 10 is D ?

    • @ChemKit
      @ChemKit 10 місяців тому

      Oh I must of made a mistake then thank you for pointing that out

  • @nebulaevie4683
    @nebulaevie4683 11 місяців тому

    thank you!! i’m going through past papers for revision for mocks and there’s some questions i couldn’t wrap my head around but this helped a bunch!!