The high level information is in 3GPP TS 38.300 specification, See "Table 5.1-1: Supported transmission numerologies". The various physical layer specification mention Normal and Extended CP.
In 14:00, you have a longer CP in two symbols regardless of the numerology that you are using. However, the longer CP should be at the beginning of the slot, in the first symbol. Therefore you should have 1 longer CP for 15 KHz, 2 for 30 KHz, 4 for 60 KHz, etc. Is that correct?
Thanks for your question. For Normal CP there are only 2 “larger CP’s” per 1ms frame. i.e at the start and at the mid point. If you look at the equation @ 12:18 you can see that the larger CP is used at I=0 and I=7 x 2^µ. The latter would make it: µ=0 (7), µ=1 (14), µ=2 (28), µ=3 (56), µ=4 (112) etc. As such, it would occur at the start and at the mid frame point. Hope that helps!
It is very nice video for someone who starts with 5g nr. Thank you. Great job :)
Very good explanation, detailed and precise, thanks for the lecture !
ua-cam.com/video/FePO75uS3Ak/v-deo.html
Waiting for part 2:)
maybe we need to buy it?
True but now all the info is out there .. check out ibwaves 5g deep dive videos
Excellent
very well presentation and explanation
very helpful video tutorial. Excellent explanation. Thank you.
Excellent presentation,good communicator
ua-cam.com/video/FePO75uS3Ak/v-deo.html
thanks for this helpful video. Is there already a part II?
Excellent video!
Where you do find the Numerology 60kHz(u=2) which support Extended CP ? Is this in spec?
The high level information is in 3GPP TS 38.300 specification, See "Table 5.1-1: Supported transmission numerologies". The various physical layer specification mention Normal and Extended CP.
Excellent!!
Is the formula for delta(f) incorrect? Seems like it should be 2^mu * 15. Referring to the formula in the table as seen at 2:22
Thanks for spotting. Yes, you are correct, it should be 2^µ.
In 14:00, you have a longer CP in two symbols regardless of the numerology that you are using. However, the longer CP should be at the beginning of the slot, in the first symbol. Therefore you should have 1 longer CP for 15 KHz, 2 for 30 KHz, 4 for 60 KHz, etc. Is that correct?
Thanks for your question. For Normal CP there are only 2 “larger CP’s” per 1ms frame. i.e at the start and at the mid point. If you look at the equation @ 12:18 you can see that the larger CP is used at I=0 and I=7 x 2^µ. The latter would make it: µ=0 (7), µ=1 (14), µ=2 (28), µ=3 (56), µ=4 (112) etc. As such, it would occur at the start and at the mid frame point. Hope that helps!
How the numerology reduces the delay in 5G ?
Sir may i know 1physical resource block = how many frames?
could you give slides of this presentation?
ua-cam.com/video/FePO75uS3Ak/v-deo.html
Better to say "time slot" rather than "slot"
The formula for sub carrier spacing is wrong. It is supposed to be power of 2
Great spot. The formula at 01:12 should say 2 to the power of the numerology: “2^µ · 15 [kHz]”.
ua-cam.com/video/FePO75uS3Ak/v-deo.html