Problems on Stable Conformation of Cyclohexane | Different Problems | Unique Concepts
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- Опубліковано 8 вер 2024
- The video deals with different and unique problems on stability of different confirmations of cyclohexane.
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Sir
You have made a good attempt to explain the concepts.
But, please correct the order of stability of the conformations of cyclohexane..
The order is
Chair > twist boat > boat > half chair.
Also, it would be better if you explain by using either prentice hall molecular models or molecular vision darling models to have a better visualisation of these interactions.
Option 1
Thanks sir ...it's really helpful
Option 1 is correct in last question
The order of stability is chair> twist boat> boat >half chair....15:57
Sir ji , your's honestly teaching. Very Very thanks lots Sir .
Option 1 is correct bcz Me and OH are cis on 1,4position .....so they go on axial equatorial position in cyclohexane... only 1st nd 3rd option is possible but in 3rd their is two 1,3 diaxial interaction so it is less stable nd 1st one is correct
option 1 is stable due to hydrogen bonding and the bulky methyl group is in equatorial position
Yes
Sir your videos are really helpful.. kindly make a video how to solve or how to predict the major product in organic chemistry..As it is asked in many CSIR problems in part C..
Really helpful.... Keep going..thank you
Stability order for cylohexane is chair>t. Boat>boat>h. Chair.. This is correct.
Almost clear explanation sir and ans is 1st Option due to hydrogen bonding.
Very much ideal guidance. Keep going on sir. We will definitely watch the next coming videos.👏👏👏👏
Sir keep solving previous year question papers untill exam it most beneficial
Very well explained sir
Sir all of your video is too much helpful. thank you sir.
Sir Plz tell me which book I shall follow for practice chapterwise problem for Inorganic, Organic, Physical. Plz sir.
Thnku..bhot hi acha padhate sir ap
Very very thank you sir.
1 is the correct. due to intra molecular H bonding....
3 also have anomaric effect
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TQ so much sir
tons of thank you sir
Respected sir,
Their is confusion in options. The equitorial position of hydroxy and methyl group are stable than axial.
Thanking you.
Nice explanation 😊
Thank you 😊
Hydroxy group us hydrogen s hydrogen bonding krega Jo F,O,N s attached ho sir , carbon s add hua hydrongen , H- bond nhi bnata
Option 1 because it is a cis 12 type and OH is axial position and there is no Diaxial interaction.
The stability of cyclohexane will be chair> twist boat>boat>half boat
And the order of stability in cyclohexane will be chair, twist boat, boat, half chair.
sir 1 have intramolecular effects that s ok ,but 3 have also anomaric effects
3 is the most stable structure of compound A because of hydrogen bonding
The answer for the Last question is option 2
is that Right sir
Hi pls explain Hammmet ,Taft equations pls
Sir y not option c sir I got confused in option a and c here in option c methyl and oH grp are in (a,e) I felt plz tell about option c y not
Twist boat form of cyclohexane is more stable than boat sir....but in video you said boat is more stable than twist boat??
In last question I m confused sir. Apne btaya ki 1,4 trans (a,a) (e,e) hoga then y option 1 is correct??
Cis hewo
Bcz in question their is 1,4 cis confirmation
46 C right answer sir
Q. 1 wrongly explained, in 1,4 there is no chance of h bonding.
Hello sir....
How hydrogen binding is possible
Sir... Option no. 1 in last question
There is no change for H bond due to absence of hydrogen.
sir correct ans 1
1 option
Option 1 is correct answer
Option 1 is correct??
Option 1
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A is correct Answer
Explanation for 1,4 difluorocyclohexane is wrong
1 st option .
Half boat or half chair
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For June 2020 batch has already started and it's about to end withing 10-15 days.
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1
Dear sir, answer is 3 because anomaric effect? Please say the answer sir thank you
Answer is option 1 due to intramolecular H bonding between Hydrogen of OH and cyclic oxygens.
Ans1
1st like and 1st view
😊
1 option is correct...
Yes
1 answer because due to H bond
Yes
Sir expected cut off kya h june vale exam ka
105-110 for GEN JRF
Which is answer 1 or 3
Answer is option 1 due to intramolecular H bonding between Hydrogen of OH and cyclic oxygens.
@@AllBoutChemistry yes..thank you very much brother
Ans....is 1
Ans is 1
Apna stability galt likhi ha -chair>twist boat>boat>half chair hogi
Ans will be 1
Hydrogen bond not shared by carbon. 1st question explain completely wrong.
If you sure provide reference
1 option
1