Volumes of Revolution : ExamSolutions

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  • Опубліковано 23 сер 2024
  • Tutorial on volumes of revolution
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КОМЕНТАРІ • 25

  • @ExamSolutions_Maths
    @ExamSolutions_Maths  15 років тому

    Thanks for your comments

  • @ExamSolutions_Maths
    @ExamSolutions_Maths  11 років тому

    sin^2(some angle) + cos^2(same angle) always = 1 Try it on your calculator. Say sin^2 (62)+cos^2(62) or sin^2(78) + cos^2(78) etc.

  • @8PetrStejskal
    @8PetrStejskal 8 років тому +4

    hello, why my calculator gives error back when putting 1/(tan(pi/6)) ??? thx

    • @AK476056
      @AK476056 5 років тому

      Your calculator is not in radians mode

  • @RShahProductions
    @RShahProductions 11 років тому +3

    Dem birds tweeting at the end!!

  • @xBustedHeart
    @xBustedHeart 9 років тому

    so since the formula for about the x axis is pi x the integral of y² dx so for about the y axis it would by pi x the integral of x² dy. And in this case for finding the volume generated about the y axis the x must be made the subject of the formula, right?

    • @ExamSolutions_Maths
      @ExamSolutions_Maths  9 років тому +1

      ***** That's correct. Check this out www.examsolutions.net/maths-revision/core-maths/integration/applications/volume%20of%20revolution/y-axis/tutorial-1.php

  • @ExamSolutions_Maths
    @ExamSolutions_Maths  11 років тому

    Look on my website for your module and then look under trig. identities. It is all explained there.

  • @aldicoverdale5137
    @aldicoverdale5137 9 років тому

    I plugged the third equation from the end into my calculator and got 248.826713. but when I plugged the end equation which was just a simpler version of it I got 27.9? why is this so?

  • @ExamSolutions_Maths
    @ExamSolutions_Maths  11 років тому

    For which board and module?

  • @ExamSolutions_Maths
    @ExamSolutions_Maths  11 років тому

    Ah, the video for volumes about the x-axis is uploaded but about the y-axis is still to be made.

  • @danielhiggins2009
    @danielhiggins2009 11 років тому +1

    would you mind explaining how you got this cos2A=1-2sin^2A?
    i read your comment above but have still got no clue.

    • @oifsdhnjiocnsrtyuhjnj
      @oifsdhnjiocnsrtyuhjnj 6 місяців тому

      cos(2A)= cos (A+A).
      The Double Angle formula states cos(A+B) = cos(A)cos(B) - sin(A)sin(B).
      Hence cos(A+A) = cos(A)cos(A) - sin(A)sin(A).
      We can simplify this to "cos^2(A) - sin^2(A)", and (since "cos^2(X) + sin^2(X) = 1"), we can substitute "cos^2(A)" as "1 - sin^2(A)".
      This leads to "1 - sin^2(A) - sin^2(A)" which finally leads us to 1 - 2sin^2A.

  • @MzVixen05
    @MzVixen05 13 років тому

    Thank You So MUCH!!!

  • @Bladebreak3r
    @Bladebreak3r 11 років тому

    The question says the curve is "rotated through 2pi radians about the x-axis." What does that mean?

    • @Kaizen-dy5ps
      @Kaizen-dy5ps Рік тому

      Hello person from 10 years ago, do you know what this means now?

    • @Bladebreak3r
      @Bladebreak3r Рік тому

      @@Kaizen-dy5ps unfortunately not. Ten years ago I was in school and now I've forgotten everything I ever learned, so I don't even know what radians means anymore

  • @ExamSolutions_Maths
    @ExamSolutions_Maths  11 років тому

    That's what happens when you record a video at dusk! At least no dogs barking this time or a police car going up the road.

  • @conorosullivan4081
    @conorosullivan4081 14 років тому

    ty v much

  • @RShahProductions
    @RShahProductions 11 років тому

    Ahaha, you're an absolute legend! Dedicated!!

  • @th2
    @th2 15 років тому

    great vid

  • @indudas2478
    @indudas2478 5 років тому

    how do you get -sinx from -2cos2x