Is Subset an Equivalence Relation? | Set Theory

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  • Опубліковано 19 сер 2024

КОМЕНТАРІ • 9

  • @keldonchase4492
    @keldonchase4492 11 місяців тому

    Thank you!

  • @benshapiro8506
    @benshapiro8506 Рік тому

    also "set" of all sets is not a set so can't have ANY relation on it.
    me being Bertrand Russell nitpicky.

  • @combinedmathsbysachithband5680
    @combinedmathsbysachithband5680 3 роки тому

    sir does power set relation is equivalence relation?

  • @itsev6970
    @itsev6970 3 роки тому

    U r amazing

    • @WrathofMath
      @WrathofMath  3 роки тому

      Thanks a lot for watching and for your support, Lavern! Let me know if you ever have any video requests!

  • @TurningTablesforyou
    @TurningTablesforyou 4 роки тому

    Prove that the relation `R={(x,y): x, y in N and x-y \" is divisible by 7 \"}` defined on

    • @vonBottorff
      @vonBottorff Рік тому

      Are you talking modulo relative to set theory?

  • @deepakpriyadharshan
    @deepakpriyadharshan 3 роки тому

    Is the subset relation anti symmetric?

    • @WrathofMath
      @WrathofMath  3 роки тому

      Thanks for watching and good question! Recall what an antisymmetric relation is. If R is an antisymmetric relation, and a and b are distinct, then it must be that if aRb, it doesn't hold that bRa. In other words, if aRb and bRa, it must be that a = b. Distinct elements cannot relate in both directions if a relation is antisymmetric.
      So, for sets A and B, if A is a subset of B and B is a subset of A, does that imply that A = B? If so, subset is an anti-symmetric relation. So what do you think?