Heisenberg uncertainty principle | Chemistry | Khan Academy

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  • Опубліковано 8 лют 2025
  • Definition of Heisenberg uncertainty principle. Calculating uncertainty in position given the uncertainty in momentum for Bohr model of hydrogen. Created by Jay.
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КОМЕНТАРІ • 64

  • @JyotiThakurC
    @JyotiThakurC 4 роки тому +12

    Thanks Khan Academy , your method of teaching is legendary.

  • @PrincePalmUwU
    @PrincePalmUwU 8 років тому +30

    Thank you so much for this video as I'am a person with, ''Learning Disability'' going for a career for either EMT-P or UA-camr but EMT-P have a Principles Of Chemistry Math classes which I haven't been taught but since I have that problem (Apparently) you explained everything perfectly for us to understand, Thanks! I will continue to learn from your video's before pursuing my careers further!! :)

    • @bamitsbaxer3881
      @bamitsbaxer3881 6 років тому

      Shit Srsly? OMFG rofl

    • @007myzorro
      @007myzorro 6 років тому +2

      What courageous from you !! IIShadow. Keep further, you will finally see the light , I wish it for you!

  • @ani-dutta
    @ani-dutta 6 років тому +26

    I tried to hit the like button as fast as I could but I missed

  • @vijgenboom2843
    @vijgenboom2843 3 роки тому +2

    A BIG thank you! ❤️

  • @Dyslexic-Artist-Theory-on-Time
    @Dyslexic-Artist-Theory-on-Time 7 років тому +3

    It is nice to see 4π representing our three dimensional space!!!
    A sphere 4π of probability ∆×∆pᵪ≥h/4π

  • @sadiashafi7928
    @sadiashafi7928 4 роки тому

    Well-done sir

  • @Austin1-0-8
    @Austin1-0-8 2 роки тому

    So basically the uncertainty you selected in the beginning for momentum of 10% is not possible because it results in the uncertainty of the position being larger than the size of the electron shell so the uncertainty of the momentum would have to be higher in order for the uncertainty of position to be within the possible size of the atom, is that correct? Because you just chose a random number 10% not an actually measured uncertainty and it happened to not be possible?

  • @sheikayaz189
    @sheikayaz189 9 років тому +2

    useful

  • @PoliticaV
    @PoliticaV 2 роки тому

    Smart man

  • @johntindell9591
    @johntindell9591 7 років тому

    Thank you so much

  • @likhithkunder1314
    @likhithkunder1314 8 років тому +23

    in our we have to actually calculate without the calculator 😢😢

  • @bamitsbaxer3881
    @bamitsbaxer3881 6 років тому +1

    Hey.....can I round off 2.838 to 3? Like 2.838 ~ 3?
    THIS IS BUGGING ME HOW DOES ROUND OFF EVEN WORK
    does ∆2 ~3? I mean even if it is equal to 2 ± xÅ? I mean Srsly,man. Heisenberg also said that ñß* { π* × |3 ± 8.7â (â is a vector) }

  • @tachyonhummingbird1107
    @tachyonhummingbird1107 7 років тому

    Does h/4pi tell us the certainty been less greater than to the uncertainty of hx and hp?

  • @delalias5754
    @delalias5754 9 років тому +1

    cant hear the sounds,.. increase the volume

  • @albertnortononymous9020
    @albertnortononymous9020 5 років тому

    At some point, it seemed like he was confusing p (position) with ρ (momentum).

  • @Spicystoic
    @Spicystoic 8 років тому +2

    why did he divide plank's constant by 4pi?

  • @marcryan658
    @marcryan658 6 років тому +1

    9:50 *Sigh of relief*

  • @beshoedits3228
    @beshoedits3228 3 роки тому

    Yeaaaah , wire

  • @gertyth3pon
    @gertyth3pon 8 років тому +3

    So basically what you're saying is none of this makes any sense? Looks like I'm on the right page then.

    • @valeriobertoncello1809
      @valeriobertoncello1809 8 років тому +5

      The classic view of a particle is a point-like object, but it turns out to be more intuitive.
      In fact you always require a group of points to define its position: a volume (shaped by a wave function).
      This volume isn't always the same: at low energy levels (or speeds, or temperatures) it shrinks and at high levels it grows.
      But when energy goes up, the volume of possibilities cannot go up too, it's like the correlation between energy and potential energy of an object falling, they are complementary: initially energy is small and potential high.
      Then, while accelerating, more and more potential energy converts into energy.
      However, for the principle of conservation of mass-energy, the sum of the two values must be always constant, like the sum of the possible positions ("volume") and the energy of a particle must be constant.
      They are two faces of the same medal.

  • @rakhshandamujib2793
    @rakhshandamujib2793 7 років тому +1

    I just sometimes wonder, what would I do had Khan Academy not been there.

  • @zakirshah5060
    @zakirshah5060 7 років тому

    Nice video sir

  • @bengundersen8316
    @bengundersen8316 7 років тому +1

    hecc

  • @nihaljalal5693
    @nihaljalal5693 8 років тому

    How 6.626*10^-34 became h

    • @im_fuzion_5436
      @im_fuzion_5436 8 років тому +1

      It's a constant

    • @NoobPlaysEverything
      @NoobPlaysEverything 8 років тому

      it is the plank's constant

    • @rv1111
      @rv1111 7 років тому

      Nihal Jalaluddin
      I think it is the shortest length of matter
      You can't go smaller then the plank length
      (I'm referring to ant man)

    • @saxetvidenskab3335
      @saxetvidenskab3335 6 років тому

      His length and constant are different i think.

  • @FreeRangeHuman4083
    @FreeRangeHuman4083 6 років тому

    KAAAAHHHHHHHNNNN

  • @jimjohn2035
    @jimjohn2035 3 роки тому +1

    who's here after Breaking Bad

  • @chancesire
    @chancesire 3 роки тому

    For me, only quantum mechanics makes sense 😂

  • @nicholaspetrish8383
    @nicholaspetrish8383 9 років тому +1

    h/2pi is Planck's constant. h/4pi is incorrect.

    • @MrFrisfruit
      @MrFrisfruit 9 років тому +10

      +Nicholas Petrish No, only the 'h' represents the planck's constant, h/2pi is the reduced planck constant.

    • @NoobPlaysEverything
      @NoobPlaysEverything 8 років тому +5

      h is the planks constant not h/4pi

    • @zacharyivanhawkins251
      @zacharyivanhawkins251 8 років тому +1

      the right side of the equation is h/4pi. (h being planks constant).

    • @tachyonhummingbird1107
      @tachyonhummingbird1107 7 років тому

      That's what I was thinking!!

    • @tachyonhummingbird1107
      @tachyonhummingbird1107 7 років тому

      @Kyle I was taking h/2pi as a fact that it is the reduced constant but thank you I agree with you

  • @ShmanleyJnr
    @ShmanleyJnr 8 років тому

  • @FugieGamers
    @FugieGamers 8 років тому

    This isn't chemistry, it's quantum physics

    • @Alex-cr8bj
      @Alex-cr8bj 8 років тому +12

      technically all of chemistry is physics.... but this is covered in chemistry courses

    • @hanxia9862
      @hanxia9862 7 років тому +1

      A lot of areas in chemistry and physics overlap as you advance in both areas

  • @someone229
    @someone229 6 років тому +3

    WTF It's h/2pi NOT h/4pi

    • @int16_t
      @int16_t 6 років тому

      Why there is 2 pi and 4 pi?

    • @smackie001
      @smackie001 6 років тому

      That's what I was thinking

    • @beretperson
      @beretperson 6 років тому +3

      No, that's ħ, but the uncertainty principle is ħ/2, which is the same as h/4pi

    • @int16_t
      @int16_t 6 років тому +1

      @@beretperson Thanks i got it now!
      h bar is the reduced planck constant. If we solve h/4pi the answer will also equal to h bar/2

  • @iraseidman2706
    @iraseidman2706 8 років тому

    When you double the radius from 5.3*10^-11 you get 1.06*10^-10 which should be 1.6*10^-11!

    • @sanyasingh9625
      @sanyasingh9625 8 років тому +1

      no we ll get 10.6 × 10^-11 n thats what they wrote...

    • @NoobPlaysEverything
      @NoobPlaysEverything 8 років тому +1

      (5.3*10^-11) * 2 => 10.6*10^-11 => 1.06*10^-10

  • @delalias5754
    @delalias5754 9 років тому +1

    cant hear the sounds,.. increase the volume

    • @dearrain5639
      @dearrain5639 8 років тому

      me too 😞 my headset are broken 😢