Thank you so much for this video as I'am a person with, ''Learning Disability'' going for a career for either EMT-P or UA-camr but EMT-P have a Principles Of Chemistry Math classes which I haven't been taught but since I have that problem (Apparently) you explained everything perfectly for us to understand, Thanks! I will continue to learn from your video's before pursuing my careers further!! :)
Hey.....can I round off 2.838 to 3? Like 2.838 ~ 3? THIS IS BUGGING ME HOW DOES ROUND OFF EVEN WORK does ∆2 ~3? I mean even if it is equal to 2 ± xÅ? I mean Srsly,man. Heisenberg also said that ñß* { π* × |3 ± 8.7â (â is a vector) }
So basically the uncertainty you selected in the beginning for momentum of 10% is not possible because it results in the uncertainty of the position being larger than the size of the electron shell so the uncertainty of the momentum would have to be higher in order for the uncertainty of position to be within the possible size of the atom, is that correct? Because you just chose a random number 10% not an actually measured uncertainty and it happened to not be possible?
The classic view of a particle is a point-like object, but it turns out to be more intuitive. In fact you always require a group of points to define its position: a volume (shaped by a wave function). This volume isn't always the same: at low energy levels (or speeds, or temperatures) it shrinks and at high levels it grows. But when energy goes up, the volume of possibilities cannot go up too, it's like the correlation between energy and potential energy of an object falling, they are complementary: initially energy is small and potential high. Then, while accelerating, more and more potential energy converts into energy. However, for the principle of conservation of mass-energy, the sum of the two values must be always constant, like the sum of the possible positions ("volume") and the energy of a particle must be constant. They are two faces of the same medal.
Thanks Khan Academy , your method of teaching is legendary.
Thank you so much for this video as I'am a person with, ''Learning Disability'' going for a career for either EMT-P or UA-camr but EMT-P have a Principles Of Chemistry Math classes which I haven't been taught but since I have that problem (Apparently) you explained everything perfectly for us to understand, Thanks! I will continue to learn from your video's before pursuing my careers further!! :)
Shit Srsly? OMFG rofl
What courageous from you !! IIShadow. Keep further, you will finally see the light , I wish it for you!
I tried to hit the like button as fast as I could but I missed
genius
It took me a second but that's a pretty good joke
Damnnn lol
A BIG thank you! ❤️
It is nice to see 4π representing our three dimensional space!!!
A sphere 4π of probability ∆×∆pᵪ≥h/4π
useful
Well-done sir
in our we have to actually calculate without the calculator 😢😢
how do you do that??
Using log, anti-log tables
Does h/4pi tell us the certainty been less greater than to the uncertainty of hx and hp?
Smart man
Thank you so much
Hey.....can I round off 2.838 to 3? Like 2.838 ~ 3?
THIS IS BUGGING ME HOW DOES ROUND OFF EVEN WORK
does ∆2 ~3? I mean even if it is equal to 2 ± xÅ? I mean Srsly,man. Heisenberg also said that ñß* { π* × |3 ± 8.7â (â is a vector) }
So basically the uncertainty you selected in the beginning for momentum of 10% is not possible because it results in the uncertainty of the position being larger than the size of the electron shell so the uncertainty of the momentum would have to be higher in order for the uncertainty of position to be within the possible size of the atom, is that correct? Because you just chose a random number 10% not an actually measured uncertainty and it happened to not be possible?
cant hear the sounds,.. increase the volume
why did he divide plank's constant by 4pi?
hbar /2
its definition
9:50 *Sigh of relief*
At some point, it seemed like he was confusing p (position) with ρ (momentum).
Yeaaaah , wire
I just sometimes wonder, what would I do had Khan Academy not been there.
Nice video sir
So basically what you're saying is none of this makes any sense? Looks like I'm on the right page then.
The classic view of a particle is a point-like object, but it turns out to be more intuitive.
In fact you always require a group of points to define its position: a volume (shaped by a wave function).
This volume isn't always the same: at low energy levels (or speeds, or temperatures) it shrinks and at high levels it grows.
But when energy goes up, the volume of possibilities cannot go up too, it's like the correlation between energy and potential energy of an object falling, they are complementary: initially energy is small and potential high.
Then, while accelerating, more and more potential energy converts into energy.
However, for the principle of conservation of mass-energy, the sum of the two values must be always constant, like the sum of the possible positions ("volume") and the energy of a particle must be constant.
They are two faces of the same medal.
KAAAAHHHHHHHNNNN
For me, only quantum mechanics makes sense 😂
How 6.626*10^-34 became h
It's a constant
it is the plank's constant
Nihal Jalaluddin
I think it is the shortest length of matter
You can't go smaller then the plank length
(I'm referring to ant man)
His length and constant are different i think.
hecc
who's here after Breaking Bad
h/2pi is Planck's constant. h/4pi is incorrect.
+Nicholas Petrish No, only the 'h' represents the planck's constant, h/2pi is the reduced planck constant.
h is the planks constant not h/4pi
the right side of the equation is h/4pi. (h being planks constant).
That's what I was thinking!!
@Kyle I was taking h/2pi as a fact that it is the reduced constant but thank you I agree with you
This isn't chemistry, it's quantum physics
technically all of chemistry is physics.... but this is covered in chemistry courses
A lot of areas in chemistry and physics overlap as you advance in both areas
WTF It's h/2pi NOT h/4pi
Why there is 2 pi and 4 pi?
That's what I was thinking
No, that's ħ, but the uncertainty principle is ħ/2, which is the same as h/4pi
@@beretperson Thanks i got it now!
h bar is the reduced planck constant. If we solve h/4pi the answer will also equal to h bar/2
When you double the radius from 5.3*10^-11 you get 1.06*10^-10 which should be 1.6*10^-11!
no we ll get 10.6 × 10^-11 n thats what they wrote...
(5.3*10^-11) * 2 => 10.6*10^-11 => 1.06*10^-10
cant hear the sounds,.. increase the volume
me too 😞 my headset are broken 😢