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N = input('Enter the the value of N(Value of N in N-Point DFT)'); x = input('Enter the sequence for which DFT is to be calculated'); n=[0:1:N-1]; k=[0:1:N-1]; WN=exp(-1j*2*pi/N); % twiddle factor nk=n'*k; WNnk=WN.^nk; Xk=x*WNnk; MagX=abs(Xk) % Magnitude of calculated DFT PhaseX=angle(Xk)*180/pi % Phase of the calculated DFT figure(1); subplot(2,1,1); plot(k,MagX); subplot(2,1,2); plot(k,PhaseX); -------------*****-------------- OUTPUT Enter the the value of N(Value of N in N-Point DFT)4 Enter the sequence for which DFT is to be calculated [1 2 3 4] MagX = 10.0000 2.8284 2.0000 2.8284 PhaseX = 0 135.0000 -180.0000 -135.0000 Respected sir why phase is getting like this can u explain
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Does the matrix twiddle apply just when we have 4 point of DTF for exemple if we have x[n]={1 2 3 4} we can apply twiddle matrix . BUT if we have for exemple x[n]={1 2 3 } can we apply the twiddle matrix ??
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Abhishek Kumar 1 second ago 1 subscribers why sir your all discrete signal processing videos get private ..plz open the videos because we are learning from their and we have reachedthe half of the course then i see you private your videos of discrete signal processing please sir try to understand our feelings and please open the videos for some time thatsa why we are complete our courses soon
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U should mention N=? & only then we can solve the problem.. here we see L=4... If N>L then we have to use zero padding method. If N=L then just do (2.pi)/N i.e. the domain will divide in N parts. & phase difference will be (2.pi)/N . and if u find N
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Great Explanation. I quickly picked it up while watching on 2X speed
12:55 in video the double underlined term , that is power of e should be divided by N
Ya, ur right
My right ear is functioning well now.
NO WORDS FOE U SIR...JAI SHREE RAM...
Thank you so much. Good and clear explanation
This guy is Awesome. Thank you very much.
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How to solve IDFT in matrix method ? Plz upload a video on this.
12:00 sir there will be 2 pi n k/ N
/N was missing
On point with Concept! :)
Thank u so much sir....
very nice explanation nailed it .
hello, can you help about Signals in the Taylor-Fourier subspace?
N = input('Enter the the value of N(Value of N in N-Point DFT)');
x = input('Enter the sequence for which DFT is to be calculated');
n=[0:1:N-1];
k=[0:1:N-1];
WN=exp(-1j*2*pi/N); % twiddle factor
nk=n'*k;
WNnk=WN.^nk;
Xk=x*WNnk;
MagX=abs(Xk) % Magnitude of calculated DFT
PhaseX=angle(Xk)*180/pi % Phase of the calculated DFT figure(1);
subplot(2,1,1);
plot(k,MagX);
subplot(2,1,2);
plot(k,PhaseX);
-------------*****--------------
OUTPUT
Enter the the value of N(Value of N in N-Point DFT)4 Enter the sequence for which DFT is to be calculated [1 2 3 4]
MagX = 10.0000 2.8284 2.0000 2.8284
PhaseX = 0 135.0000 -180.0000 -135.0000 Respected sir why phase is getting like this can u explain
Thank u sir👌
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very nice explanation sir
awesome sir.
Does the matrix twiddle apply just when we have 4 point of DTF
for exemple if we have x[n]={1 2 3 4} we can apply twiddle matrix .
BUT
if we have for exemple x[n]={1 2 3 } can we apply the twiddle matrix ??
Dougmi Youssef
yes then use padding zero to match length
and if there are 5 elements i.e. [n]={1 2 3 5 6},than how we'll solve it??
make own matix
can this method of using circle be applicable even when solving 6 points DFT?
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same question ... but no why he don't answering?
thank you SIR
the first sample in dft is always the multiplication or addition of the samples of x(n)
addition!
super
Please follow the title what you kept
is possible to calculate x[n] by using this method,plz reply
Abhishek Kumar
1 second ago
1 subscribers
why sir your all discrete signal processing videos get private ..plz open the videos because we are learning from their and we have reachedthe half of the course then i see you private your videos of discrete signal processing please sir try to understand our feelings and please open the videos for some time thatsa why we are complete our courses soon
Sir if suppose i have 5 points then how we will construct the circle?
Must response becoz we are following your method.
did you get the answer?
thank you very much.......
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if my signal is (1,2,3,4,5),, then how will i get twiddle matrix..?
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U should mention N=? & only then we can solve the problem.. here we see L=4... If N>L then we have to use zero padding method. If N=L then just do (2.pi)/N i.e. the domain will divide in N parts. & phase difference will be (2.pi)/N . and if u find N
Tq sir
why you have deleted 2nd 3rd and 4th lecture in DFT????? Please upload it again ..
والله وكفؤ فهمتها 😘😻
Thanks very much
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Ok then how to calculate 5 point DFT in matrix
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Tq sir