Maximum Power Transfer

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  • Опубліковано 27 жов 2024

КОМЕНТАРІ • 52

  • @emreo.9196
    @emreo.9196 3 роки тому +3

    I am a Mechanical Engineering Student but now I am in love with EEE :) Thanks a lot

  • @timir079
    @timir079 8 років тому +37

    What the hellllll.....I cant even Imagine that "Maximum power theorem" could be explained in just so simple way that too in 10 minutes....... In next 5 hours i have my final exams and i don't have any clue to pass. I know definitely this question might be there.
    I was just gonna mug up this question as it is explained with the highest complexity in my book.
    Thank you thank you thank you thank you so very much!!!!!!!!!!!!!!!!!!!!!!!

    • @johnrobenault3140
      @johnrobenault3140 7 років тому +6

      About 90% of the time, difficulties in class material is because of how incredibly convoluted the explanations are. Somehow, we've come to believe it must be this way. Maybe someday we'll catch on, but for now, just go to youtube.

    • @wajeehkhalil3986
      @wajeehkhalil3986 5 років тому +3

      so didi you pass the exam ??

  • @mc.phoenix3045
    @mc.phoenix3045 9 місяців тому

    Thanks very much! you are the one person that finally simplified how to find out the maximum power transfer

  • @goham2558
    @goham2558 6 років тому +7

    Such a great professor; would love to have taken one of his classes.

  • @redrounin1440
    @redrounin1440 8 років тому +6

    short and sweet and easy to follow. Thank you!

  • @wajeehkhalil3986
    @wajeehkhalil3986 5 років тому +1

    Zahid haddad , it was so wonderful watching you doing the calculas stuff. thumbs up

  • @strangeperson700
    @strangeperson700 5 років тому +3

    I love this man, he saved my life.

  • @daisy-fb5jc
    @daisy-fb5jc 5 років тому

    Ok, I finally understand what they are talking about... it's just right here!!!

  • @hamitrizabegdili2017
    @hamitrizabegdili2017 2 роки тому +1

    That was so useful and brief. Thanks

  • @asb7880
    @asb7880 8 років тому +2

    thanks bro you helped me with my load line and power transfer lab

  • @aakarshpratap3200
    @aakarshpratap3200 9 років тому +3

    thank you. I guess i am gonna rock in my tests :)

  • @shivamprakash8194
    @shivamprakash8194 7 років тому +1

    one of the most important lessons

  • @mariomuawad7815
    @mariomuawad7815 2 роки тому

    Thanks a lot for making this video, made my life a lot easier

  • @MarcoNabil
    @MarcoNabil 6 років тому +1

    YOU ARE A GREAT PERSON SIR

  • @Sam-rl6ok
    @Sam-rl6ok 4 роки тому

    Great and spoon feeding.. Thank you som much Prof

  • @s-codes14
    @s-codes14 2 місяці тому

    I love this guy

  • @1HayesEng
    @1HayesEng 7 років тому +1

    Simple, load resistance must not be less or more than the internal of the solar cell's resistance for MAX power transfer.
    Summery, Voltage drop of the cell and the load must be the same. This is Impedance matched. = max energy transfer...

    • @1HayesEng
      @1HayesEng 7 років тому

      To get maximum power transfer from a solar cell. Use the 1/2 of open voltage method.
      1. Measure the solar cells open voltage in full sun light, no load.
      2. Add load resistors until 1/2 of unloaded voltage is measured. Now max power transfer is achieved. Impedance matched.. So if no load voltage is .5v and loaded voltage is .25v it is at max-transfer of Power. 1:1

  • @MrSarimjavaid
    @MrSarimjavaid 8 років тому +8

    at 04:32 derivative of RL is zero not of Rth, right?

    • @rahult9732
      @rahult9732 8 років тому

      derivative of a constant is zero and derivative of a variable with respect to itself is one ,so what's wrong ?

    • @zachwalford5918
      @zachwalford5918 8 років тому +2

      +Rahul T RL is not the constant, Rth is.

    • @tahirhussain6117
      @tahirhussain6117 6 років тому

      RL is not constant RTh is constant

  • @MrKhalidele
    @MrKhalidele 9 місяців тому

    شكرا دكتور

  • @RB-pg3br
    @RB-pg3br 6 років тому +1

    Great video thanks a lot!

  • @bhagyalaxmimohanty8397
    @bhagyalaxmimohanty8397 7 років тому +1

    it is the best easy derivation I could calculate the power easily

  • @askariwaqar
    @askariwaqar Рік тому

    -2Rl where it went. How you remove it.

  • @chemlover1008
    @chemlover1008 5 років тому

    Why we don't take the entire resistance IN P=I^2R

  • @rigilk5684
    @rigilk5684 5 років тому

    great sir

  • @izabelnithin1695
    @izabelnithin1695 5 років тому +1

    Thank you

  • @rubenayla
    @rubenayla 4 роки тому

    Great Thanks!

  • @numanahmed6719
    @numanahmed6719 5 років тому +1

    why does Vth remain Vth since it is a Constant like Rth should it not also be 0?

    • @samtzam3774
      @samtzam3774 5 років тому

      Then constant in calculus is something different of the constant that you think. So, for that forgot the term constant that confusing and use the terms scaler and offset. The derivative of a scaler is the scaler and the derivative of an offset is 0.
      A scaler derived as any constant that multiplies a quantity that is function of the derivative variable and an offset is an constant that added or subtracted form the derivative variable.

  • @meeckelgurung988
    @meeckelgurung988 6 років тому +1

    Thank u very much

  • @TheChosenOne66501
    @TheChosenOne66501 6 років тому

    4:27 His exhale sounds like Darude - Sandstorm

    • @nhfanful
      @nhfanful 6 років тому

      Those sound like scratches

  • @yucel2378
    @yucel2378 6 років тому +1

    that was awesome

  • @engmac18
    @engmac18 8 років тому +1

    Thank you!!!

  • @Haxan786
    @Haxan786 5 років тому

    You should have to solve an example

  • @ser7ser7i
    @ser7ser7i 7 років тому

    Thank you.

  • @rpuneethkumar007
    @rpuneethkumar007 6 років тому

    Thanks a lot

  • @w00borg34
    @w00borg34 7 років тому +1

    bless up

  • @krishnendudakshi7108
    @krishnendudakshi7108 4 роки тому

    thank you sir.

  • @andimuhammadrifki5053
    @andimuhammadrifki5053 6 років тому +1

    Max power max power

  • @islam-sk7nq
    @islam-sk7nq 2 роки тому

    thanks sir

  • @pranaymeshram9266
    @pranaymeshram9266 8 років тому

    Thnx bro

  • @سيف-ر6س6ك
    @سيف-ر6س6ك 3 роки тому

    احسنت

  • @mdruhulaminkhan7207
    @mdruhulaminkhan7207 6 років тому

    bangla chai......

  • @muralep8527
    @muralep8527 6 років тому

    Not really good