In order to turn off Thyristors we need to satisfy 2 conditions 1: T1 should be reversed biased 2: The current flowing through T1 should be below the holding current of T1 in semiconvertor during pi
Voltage drop in the load contribute a potential difference making the Thyristor forward biased, current circulates within the load and the rectifier acting like a free wheeling diode.
I am having trouble understanding the negative portion of Vo. Even after the input supply has reversed ( pi < angle < pi + alpha) the SCR keeps conducting since the holding current persists. Now I think this is only possible when the voltage accross SCR is such that it makes this holding current flow through it, for this to be the case the negative voltage across the inductor must be greater than the applied AC voltage. And if this the case why do we say that we see applied AC which now has become negative at Vo and not that Vo in this case is difference between supply and inductor voltage ?
So I think all forms of controlled rectifiers contribute to reactive power and displacement power factor, right?
Why is T1 still conducting irrespective of being reverse biased in semicontrol negative half cycle?
In order to turn off Thyristors we need to satisfy 2 conditions
1: T1 should be reversed biased
2: The current flowing through T1 should be below the holding current of T1
in semiconvertor during pi
Voltage drop in the load contribute a potential difference making the Thyristor forward biased, current circulates within the load and the rectifier acting like a free wheeling diode.
I am having trouble understanding the negative portion of Vo. Even after the input supply has reversed ( pi < angle < pi + alpha) the SCR keeps conducting since the holding current persists. Now I think this is only possible when the voltage accross SCR is such that it makes this holding current flow through it, for this to be the case the negative voltage across the inductor must be greater than the applied AC voltage. And if this the case why do we say that we see applied AC which now has become negative at Vo and not that Vo in this case is difference between supply and inductor voltage ?
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