A-Level Maths B7-06 Graphs: Sketching the Modulus of a Linear Function

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[@jacobb7379]

comparing it to completing the square - such a good method, never heard of it before. Thanks!

[@jackbrasier-creagh9139]

this guy is a legend

[@ogb18gang62]

I love your videos my dawg. Praying they get me through my exam today. Big love

[@adwait13godse]

Nicely explained in easy way

[@zaynali3649]

Cheers mate very good explanation love it

[@anish7183]

Nicely edited

[@eeyumpeeyum]

Wow! Very clearly explained! :)

[@abdulwasay5790]

why is he so damn underrated

[@lidiabejerea9292]

Why isn't the vertex (5,0) for Q3? I though you have to take the modulus (positive) of 5

[@TLMaths]

But x=-5 makes what is inside the modulus zero, and hence y is zero at that point. So the vertex is at (-5,0).

[@muhammadabubakar3521]

Good job..keep it up.. well wishes from Pakistan❤

[@vuyyurisatyasrinivasarao3140]

Good sir

[@seeyar4620]

how come the coordinates arent (5,0) for the third question? doesn't it become positive either way when it's a modulus function? or is it because we are completing the square? thanks

[@TLMaths]

If you substitute x=5 into the equation y = |2x + 10| you get y = |2*5+10| = 20, not zero. When you substitute a negative number in, you don't change it to being positive before you substitute it in.

[@yuhongleong4294]

Nice video, thanks❤

[@SM-tm5ji]

How come it hasn’t been reflected for when y

[@TLMaths]

When x = 3, you get y = |3 - 3| - 3 = -3, so the graph definitely goes below the x-axis?