The Stress Tensor and Traction Vector

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  • Опубліковано 28 січ 2025

КОМЕНТАРІ • 36

  • @kenankenan6371
    @kenankenan6371 2 місяці тому +3

    Absolutely brilliant !!! The Strength of materials and Continuum mechanics classes should be teached like this. Rigor always come after intuition. First create some intuition then jump into the rigor. Which is rare among the lecturers. Thank you dear Dr. Please dont stop making this videos. Future engineers and scientist needs mentors like u. God bless you

    • @DrSimulate
      @DrSimulate  2 місяці тому +1

      Thank you so much for this very nice and motivating comment!

  • @Prashanth-yn9zd
    @Prashanth-yn9zd 5 місяців тому +2

    I demonstrated that a symmetric stress tensor implies the conservation of angular momentum in my continuum mechanics exam, but I truly understood the concept just now. Thank you for showing the visualization.

  • @BoZhaoengineering
    @BoZhaoengineering Місяць тому

    Hello Dr.Simulate, my motivation to learn tensors is to calculate multi-axis fatigue. The critical plane method requires engineers to pull out stress components from FEA and manipulate these stress components using local coordinates. Your courses online in tensor and continuum mechanics are very helpful for me to understand the basic concept of tensor and its stress components. Thank you for your instruction video!

  • @aymannoir
    @aymannoir Місяць тому

    Thank you for the videos, very simple and high quality.

  • @emrekt22
    @emrekt22 7 місяців тому +1

    loving this series so far!

  • @whmi8498
    @whmi8498 7 місяців тому +5

    You deserve millions of subscribers. Take love brother 💖💗💞

  • @manasmahale5906
    @manasmahale5906 7 місяців тому +1

    You are my favorite YT channel !

  • @marquesjr.5796
    @marquesjr.5796 7 місяців тому +1

    Amazing work! These visualizations about continuum mechanics helps a lot to understand faster the abstract part of this theory! Thank you so much!!!!

  • @lowsugar8155
    @lowsugar8155 7 місяців тому +1

    Good visualization. Your presentation shows that continuum mechanics is a kind of beautiful art.

  • @vineethravi3493
    @vineethravi3493 7 місяців тому +4

    keep up doing god's work.

  • @TheAncientColossus
    @TheAncientColossus 3 місяці тому +2

    3:59 This is incorrect. Wikipedia says the opposite.
    Assuming a material element (see figure at the top of the page) with planes perpendicular to the coordinate axes of a Cartesian coordinate system, the stress vectors associated with each of the element planes, i.e. T(e1), T(e2), and T(e3) can be decomposed into a normal component and two shear components, i.e. components in the direction of the three coordinate axes. For the particular case of a surface with normal unit vector oriented in the direction of the x1-axis, denote the normal stress by σ11, and the two shear stresses as σ12 and σ13.
    NOT 11, 21, 31.

    • @DrSimulate
      @DrSimulate  3 місяці тому +1

      This comment was made several times. The index order does not matter for a symmetric tensor. It's just a matter of definition. I chose the index ordering the way I did, because in this way if you compute t = sigma * n with n being one of the unit normal vectors of the infinitesimal cube, you get the traction at the surfaces of the infinitesimal cube.
      The formula t = sigma * n is commonly used in continuum mechanics. In wikipedia (en.wikipedia.org/wiki/Cauchy_stress_tensor) the traction is defined differently as T = n * sigma, which is why there the rows of sigma are the tractions acting on the infinitesimal cube.

    • @TheAncientColossus
      @TheAncientColossus 3 місяці тому

      @@DrSimulate Cool. The official index for all engineering purposes is i,j - orientation, direction. This is shown in practically all engineering textbook. For example, the xy shear stress is drawn on the x-face in all drawings of a 2D stress state. It is so confusing for students to see it flipped to j,i, randomly without explanation in your videos.

    • @johannesjoensuu7946
      @johannesjoensuu7946 2 місяці тому +1

      @@TheAncientColossus Yep, would be nice to mention it but I can only imagine how much there is to consider doing these videos so it's easy to overlook or forget.

    • @TheAncientColossus
      @TheAncientColossus 2 місяці тому

      @@johannesjoensuu7946 Fair point.

  • @omars_projects
    @omars_projects 3 місяці тому +1

    Nice video, thanks for the explanation, keep it up :)

  • @kamalahmadov4418
    @kamalahmadov4418 3 місяці тому +1

    thanks for your work

  • @ninhhoang616
    @ninhhoang616 7 місяців тому +2

    Great video. Hope you make more videos.

  • @SeanFlournoy
    @SeanFlournoy 7 місяців тому +2

    Beautiful video! Is there a reason why the indices of the stress tensor in your video are opposite to those of the Cauchy stress tensor? What I mean by that is I have been taught that the first index i indicates normal plane where stress is acting, and second index j indicates direction of the stress. Thanks!

    • @DrSimulate
      @DrSimulate  7 місяців тому +2

      @@SeanFlournoy Hey! I would argue like this: it is very common to associate the first index of a tensor/matrix with the rows and the second index with the columns of the tensor/matrix. This means that for example for the first column the second index is always one. Now take for example the vector n = (1,0,0), i.e. the normal vector of the right surface. Multiplying sigma with n to obtain the traction at this surface results in the first column of sigma (for which the second index is always one). This means that the second index defines at which surface the traction is acting.
      Of course this discussion is a bit pointless for a symmetric tensor. It is always a matter of definition :)

  • @zahraakhalife9150
    @zahraakhalife9150 4 місяці тому +1

    Thank you ❤

  • @TheAncientColossus
    @TheAncientColossus 3 місяці тому

    11:12 Why does the stress TENSOR increase on the narrow parts of the geometry? Or does the traction VECTOR increase?

    • @DrSimulate
      @DrSimulate  3 місяці тому

      Both should increase in the narrow part of the geometry. If you "cut" the geometry at any height, the resulting vertical force should be the same. In the narrow part of the geometry, the force distributes over a smaller area and hence the stress and traction are greater.

  • @geep1232
    @geep1232 14 днів тому

    Thank you!!!

  • @vicovargas1
    @vicovargas1 7 місяців тому +1

    Amazing videos

  • @quocbaoleoan4465
    @quocbaoleoan4465 2 місяці тому

    Can you please advise me what kind of software that can be used to create the simulation in this video, Dr.? Many thanks.

    • @DrSimulate
      @DrSimulate  2 місяці тому +1

      Sure, I use Fenics for finite element simulations and then I use Manim and Matplotlib for the animations. :)

    • @quocbaoleoan4465
      @quocbaoleoan4465 2 місяці тому

      @DrSimulate thank you Dr

  • @TozzaYT
    @TozzaYT 7 місяців тому

    I thought traction was getting utilising friction to move, or something along those lines