Finding C programming hard? We’ve got you! 🚀Get 60% off on Programiz PRO Lifetime Plan this Black Friday-pay once for skills that last forever. Don’t miss out, it’s a limited-time offer! 👉Grab your discount now: bit.ly/blkfriday-24-yt
As a person who just started learning Software Engineering I have found these videos most helpful indeed. Definitely subscribing and recommending this channel to any other people I may come across who are in the process of learning software engineering. Great job !!!
Very good very dope. Spent 3 week eeking by in class not knowing the semantics of calling a function. Solved weeks long headache in less than 20 minutes. Appreciate it a million times over!
for the last question A and C is correct but difference the first just call and second calling and store value inside integer which will cast the result from double to integer
#include int multiplyNumbers(int number1, int number2){ int product = number1*number2; return product; } int main(){ int result= multiplyNumbers(7,8); printf("result=%d", result); return 0; }
16:33 programming task #include int Addnumber(){ int number, number2; printf("Enter a first values: "); scanf("%d",&number); printf("Enter a second values: "); scanf("%d",&number2); int sum = number + number2; return sum; } int main() { int result =Addnumber(); printf("Result = %d", result); return 0; }
These tutorials have been the best for simple explanations and work great to code along too and practice, THANK YOU! for the problem i think its answer is C #include #include int multNumbers(int number1, int number2); int main() { int number1; int number2;
printf("Enter Number 1: "); scanf("%d",&number1); printf("Enter Number 2: "); scanf("%d",&number2); int sum = multNumbers(number1,number2);//dont call this too early remember its proceedural printf("The result of %d * %d = %d",number1, number2, sum); return 0; } int multNumbers(int number1, int number2){ int product = number1 * number2; return product; }
@@bwon8233 to my understanding you're creating space to hold the values you're going to be taking from the user. And in the function we're not initializing, we are doing a method call to the function miltNumbers. That reference is being passed as the arguments number1 and number2.
😍 Watched all the 15 videos. Really appreciatable work... Mam u r teaching very well.. waiting with expectation for upcoming tutorials.. pls make videos for remaining Syntax .. thank u❤️
#include int productnumbers(int number1, int number2); int main(){ int result = productnumbers(4,5); printf("result is %d", result); return 0; } int productnumbers(int number1, int number2){ int product = number1 * number2; return product; printf("after return"); } programing quiz Awnser.
Q. What is the correct way to call the following function? int test(double num1, int num2) { ... } A. test(8.3, 2); B. test (2, 8.3); C. int result = test(8.3, 2); D. int result = test(2, 8.3);
Answer for Proggramming Task Today: #include int multification(int num1, int num2); int main(){ int n1, n2; printf("Enter number 1:"); scanf("%d",&n1); printf("Enter number 2:"); scanf("%d",&n2); int res = multification(n1, n2); printf("Result = %d",res); return 0; } int multification(int num1, int num2){ int multi = num1 * num2; return multi; }
// can you create a function, takes two floating numbers, performs the multiplication of two numbers, returns the result using function prototype? #include float multiplyNumbers(float num1,float num2); int main(){ float result= multiplyNumbers(5.2,2.5); printf("Result is %.2f",result); return 0; } float multiplyNumbers(float num1,float num2){ float product = num1 * num2; return product; }
#include int multiply(int num1,int num2){ int result = num1 * num2; return result; } int main() { int result = multiply(10,5); printf("Result = %d", result);
// Online C compiler to run C program online #include int multiplication(int a,int b){ int product = a*b; return product; } int main() { int result = multiplication(9,3); printf("result is %d",result); }
For this video's task, here is a code sample and maybe it will be helpful to someone :) // can you create a function, takes two numbers, performs the multiplication of two numbers, returns the result ? #include int addNumbers(int number1, int number2) { int sum = number1 * number2; return sum; } int main (void) { int result = addNumbers(9, 5); printf("Result = %d ", result); return 0; }
@@comptime Exactly, something like this but I named it product instead of multiply: //Create a function that takes two numbers, performs the multiplication of the numbers and return the result// #include int productnumbers(int number1, int number2){ int product = number1 * number2; return product; } int main(){ int result = productnumbers(65,43); printf("Result = %d", result); return 0; }
by the void method and the return method: (without the printf and scanf parts) /*//Chap 15.3 Function Prog.Task// void multiNum(int num151, int num152){ int prod15 = num151 * num152; printf("The Product of %d and %d is %d
", num151, num152, prod15); } int main() { multiNum(2,6);*/ //Return// int multiNum2(int num1512, int num1522){ int prod152 = num1512 * num1522; return prod152; } int main() { int result153 = multiNum2(6,7); printf("Result 2 = %d", result153);
# include #include void multiplyNumbers(int number1,int number2){ int multiply = number1* number2; printf("multiply of %d and %d is %d ", number1,number2, multiply); } int main(){ multiplyNumbers(2,2); return 0; }
#include int multiplication(int num1, int num2){ int result = num1 * num2; printf("The multiplication of %d and %d is %d", num1, num2 ,result); } int main(){ multiplication(7, 4); }
option c is right to call a function programing task: #include #include int product(int number1,int number2); int main() { int result=product(5,5); return 0; } int product(int number1,int number2) { int product=number1*number2; printf("produt=%d",product); return product; }
#include void multiply(int num1,int num2){ int result = num1 * num2; printf("result of %d and %d is %d", num1, num2, result); } int main(){ multiply(4,7); return 0; }
#include int calc(a,b){ int mult=a*b; return mult;} int main(a,b){ printf("write a and b:"); scanf("%d %d",&a,&b); int mult=calc(a,b); printf("the multiplication is %d",mult); return 0; } i wrote it im so proud of me
include int multi(int num1, int num2); int main() { multi(7, 6); return 0; } int multi(int num1, int num2) { int result = num1 * num2; printf("Multiplication of %d and %d is %d", num1, num2, result); return multi; }
Programming Task #include //Prototype of the Function int multiply_two_ints(int number1, int number2); int main() { // Write C code here int num1, num2; // Asking for the first Number printf("First Number: "); scanf("%d", &num1); // Asking for the Second number printf("Second Number: "); scanf("%d", &num2); // calling the function 'multiply_two_ints' int result = multiply_two_ints(num1,num2); { printf("Result = %d", result); } return 0; } //defining the Function int multiply_two_ints(int number1, int number2) { int mult = number1 * number2; return mult; }
Function for the multiplication of two numbers - #include void multiNum(int num151, int num152){ int prod15 = num151 * num152; printf("The Product of %d and %d is %d
", num151, num152, prod15); } int main() { int num151; printf("Enter a number: "); scanf("%d", &num151); int num152; printf("Enter a number: "); scanf("%d", &num152); multiNum(num151,num152); return 0; }
#include int multi(int a,int b){ int ento= a*b; return ento; } int main(){ int a,b; printf("enter two numbers :"); scanf("%d %d",&a,&b); int result = multi(a,b); printf("result=%d",result); return 0; }
#include int add(int number1, int number2); int main() { int result = add(13, 14); printf("result = %d", result); return 0; } int add(int number1,int number2){ int answer = number1 * number2; return answer; printf("complicated"); }
#include int main (){ int month; printf("enter two integer"); scanf("%d",&month); switch(month){ case 1: printf("january"); break; case 2: printf("february"); break; case 3: printf("march"); break; case 4: printf("april"); break; case 5: printf("may"); break; case 6: printf("jun"); break; case 7: printf("july"); break; case 8: printf("august"); break; case 9: printf("september"); break; case 10: printf("octomber"); break; case 11: printf("november"); break; case 12: printf("december"); break; } return 0; thank you mam, for teaching c switch program. .}
int multiply(int num1,int num2){ return num1 * num2; } int main(){ int result = multiply(6,3); printf("%d",result); } you can directly return the multiplications coz there r no any other tasks
Finding C programming hard? We’ve got you!
🚀Get 60% off on Programiz PRO Lifetime Plan this Black Friday-pay once for skills that last forever. Don’t miss out, it’s a limited-time offer!
👉Grab your discount now: bit.ly/blkfriday-24-yt
Please I need your help !!!!
#include
#include
int function(int a, int b)
{
int i=a;
if (i
As a person who just started learning Software Engineering I have found these videos most helpful indeed. Definitely subscribing and recommending this channel to any other people I may come across who are in the process of learning software engineering. Great job !!!
now, that's what you call teaching. my prof can't even make me understand this sub T^T. but you did it in just a few minutes. thank you very much.
Glad we could help!
@@programizstudios thanks to you, I think I ace ng exam today 😉
I agree very well explained!!
I completed my 12th one month ago and learning C language for the first time and these series were really very very helpful. thanks a lot🤗
Very good very dope. Spent 3 week eeking by in class not knowing the semantics of calling a function. Solved weeks long headache in less than 20 minutes. Appreciate it a million times over!
One of the best lectures for this topic on the internet
for the last question A and C is correct but difference the first just call and second calling and store value inside integer which will cast the result from double to integer
#include
int multiplyNumbers(int number1, int number2){
int product = number1*number2;
return product;
}
int main(){
int result= multiplyNumbers(7,8);
printf("result=%d", result);
return 0;
}
this was very easy to understand with walk throughs of clear examples. I know more now than I did 13min ago, thank you for your time.
These videos are very helpful! 17 minutes for a tutorial is very professional
Padma mam you are so cool
i am in first year CS student your teaching is superb
This is the best video explaining functions in C that I could find from both searches in English and Spanish, great job guys, thank you!
Best way to teaching I love all the videos of this channel ❤️
16:33 programming task
#include
int Addnumber(){
int number, number2;
printf("Enter a first values: ");
scanf("%d",&number);
printf("Enter a second values: ");
scanf("%d",&number2);
int sum = number + number2;
return sum;
}
int main()
{
int result =Addnumber();
printf("Result = %d", result);
return 0;
}
wrong bro , programming task multiply by taking two numbers
it should be int sum = number * number2;
These tutorials have been the best for simple explanations and work great to code along too and practice, THANK YOU!
for the problem i think its answer is C
#include
#include
int multNumbers(int number1, int number2);
int main() {
int number1;
int number2;
printf("Enter Number 1:
");
scanf("%d",&number1);
printf("Enter Number 2:
");
scanf("%d",&number2);
int sum = multNumbers(number1,number2);//dont call this too early remember its proceedural
printf("The result of %d * %d = %d",number1, number2, sum);
return 0;
}
int multNumbers(int number1, int number2){
int product = number1 * number2;
return product;
}
I get this buy why did we initialize number1 and number2 in both the function and main
@@bwon8233 to my understanding you're creating space to hold the values you're going to be taking from the user. And in the function we're not initializing, we are doing a method call to the function miltNumbers. That reference is being passed as the arguments number1 and number2.
😍
Watched all the 15 videos. Really appreciatable work... Mam u r teaching very well.. waiting with expectation for upcoming tutorials.. pls make videos for remaining Syntax .. thank u❤️
very elegant person you are, accompanied with good skill of teaching. looking forward to see more of your work. Thank you
#include
int productnumbers(int number1, int number2);
int main(){
int result = productnumbers(4,5);
printf("result is %d", result);
return 0;
}
int productnumbers(int number1, int number2){
int product = number1 * number2;
return product;
printf("after return");
}
programing quiz Awnser.
result is 20
I’ve watched hours of videos and tNice tutorials one is the first that explains it in a way a complete beginner could understand! Great videoccccccccc
Finally I understood what passing a value in function means my gosh it took me so many videos 😂 on UA-cam
Hey same😂 but still not understood
Thank you for clear explanation. For begginers it is very easy to understand, even if they do not know english so good.
you just render every thing in programming easier
Q. What is the correct way to call the following function?
int test(double num1, int num2) {
...
}
A. test(8.3, 2);
B. test (2, 8.3);
C. int result = test(8.3, 2);
D. int result = test(2, 8.3);
A
Option:A
C. int result = test(8.3, 2);
Option A( 8.3, 2);
@@adarshyadav1423 Why the answer will be A?? According to me , answer should be C
bro they are helping us more than the teachers of our colleges
wow! you make C so interesting for me😥. Thanks!💗 i recommend this for anyone!
Answer for Proggramming Task Today:
#include
int multification(int num1, int num2);
int main(){
int n1, n2;
printf("Enter number 1:");
scanf("%d",&n1);
printf("Enter number 2:");
scanf("%d",&n2);
int res = multification(n1, n2);
printf("Result = %d",res);
return 0;
}
int multification(int num1, int num2){
int multi = num1 * num2;
return multi;
}
Thorough explanation and so clear to grasp quickly. Thank you for these valuable contents through this valuable channel. I am grateful.
#include
void addNumbers(double number1, double number2){
double sum = number1 + number2;
printf("%lf + %lf = %.2lf", number1, number2, sum);
}
int main(){
addNumbers(5.2, 3.55);
}
for 9:38
PROGRAMMING TASK:
1.
#include
int multiplication(int num1, int num2) {
int product = num1 * num2;
return product;
}
int main() {
int result = multiplication(2,3);
printf("Result = %d", result);
return 0;
}
OUTPUT :
Result = 6.
2.
#include
int multiplication(int num1, int num2) {
int product = num1 * num2;
printf("Product of %d & %d in %d", num1, num2, product);
return product;
}
int main() {
multiplication(2,3);
return 0;
}
OUTPUT:
Product of 2 & 3 is 6.
So helpful tutorials and your website as well.
Your way of teaching is really good.
لا معليكم مني جيت اذاكر لغه سي هنا لأن شرح دكتورتي تحفه الصدق🙂
Dhanyabaad didi bich bich ma ra vannu vaxa ramro xa 😂😂
// can you create a function, takes two floating numbers, performs the multiplication of two numbers, returns the result using function prototype?
#include
float multiplyNumbers(float num1,float num2);
int main(){
float result= multiplyNumbers(5.2,2.5);
printf("Result is %.2f",result);
return 0;
}
float multiplyNumbers(float num1,float num2){
float product = num1 * num2;
return product;
}
#include
int multiply(int num1,int num2){
int result = num1 * num2;
return result;
}
int main()
{
int result = multiply(10,5);
printf("Result = %d", result);
return 0;
}
finally a detailed video on this topic, thank you ma'am
// Online C compiler to run C program online
#include
int multiplication(int a,int b){
int product = a*b;
return product;
}
int main() {
int result = multiplication(9,3);
printf("result is %d",result);
}
#include
#include
int operation(int num1,int num2)
{
int multiply =num1*num2;
return multiply;
}
int main(){
int result=operation(5,6);
printf("result = %d",result);
return 0;
}
Good❤
Your understanding is excellent🙂🙂
For this video's task, here is a code sample and maybe it will be helpful to someone :)
// can you create a function, takes two numbers, performs the multiplication of two numbers, returns the result ?
#include
int addNumbers(int number1, int number2)
{
int sum = number1 * number2;
return sum;
}
int main (void)
{
int result = addNumbers(9, 5);
printf("Result = %d
", result);
return 0;
}
correct
It is better if you name the function as multiplyNumbers.
@@comptime Exactly, something like this but I named it product instead of multiply:
//Create a function that takes two numbers, performs the multiplication of the numbers and return the result//
#include
int productnumbers(int number1, int number2){
int product = number1 * number2;
return product;
}
int main(){
int result = productnumbers(65,43);
printf("Result = %d", result);
return 0;
}
so here if i put the name hello instead of addnumbers it doesn't matter?
I already thought I would never understand it. Thanks!
Amazing teaching skills……. Helps alot to understand functions……✨✨✨
Thank you....this video explained functions very simply...and her accent is cute XD
Please do more videos. I really like this simple way of explanations and demonstrations.
A is the correct answer.
it's so well explained thank for this gift may God Bless you
#include
void calculateNumbers(double num1, double num2)
{
double sum = num1 + num2;
printf("sum of %lf and %lf is %lf", num1, num2, sum);
}
int main()
{
calculateNumbers(8.7,9.1);
}
I like this, Thank You😊🙌
by the void method and the return method: (without the printf and scanf parts)
/*//Chap 15.3 Function Prog.Task//
void multiNum(int num151, int num152){
int prod15 = num151 * num152;
printf("The Product of %d and %d is %d
", num151, num152, prod15);
}
int main() {
multiNum(2,6);*/
//Return//
int multiNum2(int num1512, int num1522){
int prod152 = num1512 * num1522;
return prod152;
}
int main() {
int result153 = multiNum2(6,7);
printf("Result 2 = %d", result153);
🤩 "Voice"
# include
#include
void multiplyNumbers(int number1,int number2){
int multiply = number1* number2;
printf("multiply of %d and %d is %d ", number1,number2, multiply);
}
int main(){
multiplyNumbers(2,2);
return 0;
}
#include
int multiplication(int num1, int num2){
int result = num1 * num2;
printf("The multiplication of %d and %d is %d", num1, num2 ,result);
}
int main(){
multiplication(7, 4);
}
option c is right to call a function
programing task:
#include
#include
int product(int number1,int number2);
int main()
{
int result=product(5,5);
return 0;
}
int product(int number1,int number2)
{
int product=number1*number2;
printf("produt=%d",product);
return product;
}
why option C? i thought the option A is right....
#include
void multiply(int num1,int num2){
int result = num1 * num2;
printf("result of %d and %d is %d", num1, num2, result);
}
int main(){
multiply(4,7);
return 0;
}
Thanks madam for your services
#include
int calc(a,b){
int mult=a*b;
return mult;}
int main(a,b){
printf("write a and b:");
scanf("%d %d",&a,&b);
int mult=calc(a,b);
printf("the multiplication is %d",mult);
return 0;
} i wrote it im so proud of me
include
int multi(int num1, int num2);
int main()
{
multi(7, 6);
return 0;
}
int multi(int num1, int num2)
{
int result = num1 * num2;
printf("Multiplication of %d and %d is %d", num1, num2, result);
return multi;
}
Making understanding easy, thanks
Thank you so much mam B. TECH-IT
First year mam very helpful mam
Thanks for your best lessons
soo helpful tuto
Programming Task
#include
//Prototype of the Function
int multiply_two_ints(int number1, int number2);
int main() {
// Write C code here
int num1, num2;
// Asking for the first Number
printf("First Number: ");
scanf("%d", &num1);
// Asking for the Second number
printf("Second Number: ");
scanf("%d", &num2);
// calling the function 'multiply_two_ints'
int result = multiply_two_ints(num1,num2); {
printf("Result = %d", result);
}
return 0;
}
//defining the Function
int multiply_two_ints(int number1, int number2) {
int mult = number1 * number2;
return mult;
}
Thank you so much
Function for the multiplication of two numbers -
#include
void multiNum(int num151, int num152){
int prod15 = num151 * num152;
printf("The Product of %d and %d is %d
", num151, num152, prod15);
}
int main() {
int num151;
printf("Enter a number: ");
scanf("%d", &num151);
int num152;
printf("Enter a number: ");
scanf("%d", &num152);
multiNum(num151,num152);
return 0;
}
Wounder full teaching mam
// Online C compiler to run C program online
#include
#include
double multiplynos(double number1, double number2);
int main()
{
//float result= sqrt(80);
//printf("Square root is : %.2f",result );
double mum = multiplynos(8.45455,2.454656);
printf("Multiplication is %lf",mum);
return 0;
}
double multiplynos(double number1, double number2)
{
double mum = number1 * number2;
return mum;
}
return where, return how, return why, return when?
#include
int multi(int a,int b){
int ento= a*b;
return ento;
}
int main(){
int a,b;
printf("enter two numbers :");
scanf("%d %d",&a,&b);
int result = multi(a,b);
printf("result=%d",result);
return 0;
}
what a beautiful and smart woman.This lesson was so helpful thank you.
#include
int add(int number1, int number2);
int main() {
int result = add(13, 14);
printf("result = %d", result);
return 0;
}
int add(int number1,int number2){
int answer = number1 * number2;
return answer;
printf("complicated");
}
int multiply(int n1,int n2)
{
int result=n1*n2;
printf("%d",result);
return result;
}
int main()
{
int a,b;
multiply(4, 5);
return 0;
}
Options A and C, according to the next video C #16 respectively at 16:00 and 14:25.
Thanks C compiler.😅
#include
int main (){
int month;
printf("enter two integer");
scanf("%d",&month);
switch(month){
case 1:
printf("january");
break;
case 2:
printf("february");
break;
case 3:
printf("march");
break;
case 4:
printf("april");
break;
case 5:
printf("may");
break;
case 6:
printf("jun");
break;
case 7:
printf("july");
break;
case 8:
printf("august");
break;
case 9:
printf("september");
break;
case 10:
printf("octomber");
break;
case 11:
printf("november");
break;
case 12:
printf("december");
break;
}
return 0;
thank you mam,
for teaching c switch program.
.}
#include
void Thanks(){
printf("Thanks a million dear instructor
");
}
int main () {
Thanks();
printf("Go Ahead, please");
return 0;
}
thank you programiz team
The answer of the quiz is A
So easy to understand...
Mam you are very skillfull in coding 🥰🥰help us and upload more videos plzz
#include
int multiplyNumbers(int number1, int number2){
float multiplication= number1 * number2;
return multiplication;
}
int main(){
float result = multiplyNumbers (5, 2);
printf("Product = %f", result);
return 0;
}
this best course
#include
#include
#include
void calculator(int num1, int num2) {
int result = num1 * num2;
printf("Product of %d * %d = %d", num1, num2, result);
}
int main() {
calculator(5,2);
return 0;
}
THANK YOU SO SO MUUUUUCH
Thank you so much for this video!!! Very helpful!
You are so welcome!
You are the best ❤️
#include
void multiplyNumbers(double num1 , double num2){
double sum = num1 * num2;
printf("the sum is %.1lf", sum);
}
int main() {
multiplyNumbers(9,2);
return 0;
}
thank you programiz team..!!
Happy programming.!
Thanks it helped me install it
Thanks ma'am
C. int result = test(8.3, 2);
Very helpful tutorials, Thanks.
thanks for the great support
I hope ou can keep it up
good work king, love you
Thank you very much!!
thank u
very well defined and constructive video
#include
double calculateProduct(){
double a, b;
printf("Choose two numbers to multiply by each other: ");
scanf("%lf %lf", &a, &b);
double product = a * b;
return product;
}
int main() {
double result = calculateProduct();
printf("%lf
", result);
return 0;
}
Thank you, this was so helpful
I've been using you're website for a month lol
Very helpful. Thanks
1 #include
2 int multiplyNumbers(int num1, int num2)
3 {
4 int product = num1 * num2;
5
6 return (product);
7 }
8 int main()
9 {
10 int result = multiplyNumbers(8, 7);
11 printf("Result = %d", result);
12 return (0);
13 }
int multiply(int num1,int num2){
return num1 * num2;
}
int main(){
int result = multiply(6,3);
printf("%d",result);
}
you can directly return the multiplications coz there r no any other tasks