These small videos are abundant in knowledge. i have been dependent on these videos since my graduation time. now I'm pursuing my master's. Thank you so much, madam.
Thanks a lot!! Could you please tell in dN/dt=rN (k-N)/k why do we divide (k-N) by k? I understand the fact that at N=k the rate of change of graph i.e. slope is 0 thus we add an extra term in case of Logistic Curve, but I'm unable to deduce the reason of dividing by k. Btw good explanation, it really helped...pls keep uploading short videos for a topic.
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These small videos are abundant in knowledge. i have been dependent on these videos since my graduation time. now I'm pursuing my master's. Thank you so much, madam.
Great!! 💝
Thanks a lot!! Could you please tell in dN/dt=rN (k-N)/k why do we divide (k-N) by k? I understand the fact that at N=k the rate of change of graph i.e. slope is 0 thus we add an extra term in case of Logistic Curve, but I'm unable to deduce the reason of dividing by k.
Btw good explanation, it really helped...pls keep uploading short videos for a topic.
Thank you 😊
The expression (k-N)/k is used to calculate the proportion of carrying capacity that is still available for population growth
@@NehasBiology gotcha' 💝
Nice explanation
Thank you mam
Good mam
K-N/K?
Yes, The logistic growth equation can be given as dN/dt= rN ((K-N)/K).