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x = 1/2(3+√5) = [(√5 +1)/2]^2. So, x^4= 1/2(47+21√5) and √x = 1/2(√5+1). Similarly, y=1/2(3-√5) = [(√5 -1)/2]^2. Thus, y^4 = 1/2(47-21√5) and √x = 1/2(√5-1). Thus, E = 34√5.
34√5
E=9.4 approximate
Ειναι χ=[3+(5)^(1/2)]/2 y=[3-(5)^(1/2)]/2 χ+y=3 χy=1 (χ)^(1/2)+(y)^(1/2)=(5)^(1/2) ( χ)^(1/2)=[1+(5)^(1/2)]/2 (y)^(1/2)=[(5)^(1/2)-1]/2 τελικα Ε=38+17×(5)^(1/2)-38+17×(5)^(1/2)=34×(5)^(1/2)
x = 1/2(3+√5) = [(√5 +1)/2]^2. So, x^4= 1/2(47+21√5) and √x = 1/2(√5+1). Similarly, y=1/2(3-√5) = [(√5 -1)/2]^2. Thus, y^4 = 1/2(47-21√5) and √x = 1/2(√5-1). Thus, E = 34√5.
34√5
E=9.4 approximate
Ειναι χ=[3+(5)^(1/2)]/2 y=[3-(5)^(1/2)]/2
χ+y=3 χy=1 (χ)^(1/2)+(y)^(1/2)=(5)^(1/2) ( χ)^(1/2)=[1+(5)^(1/2)]/2 (y)^(1/2)=[(5)^(1/2)-1]/2 τελικα Ε=38+17×(5)^(1/2)-38+17×(5)^(1/2)=34×(5)^(1/2)