Lecture 32-Boundary conditions for Electromagnetic fields

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  • Опубліковано 11 вер 2024

КОМЕНТАРІ • 15

  • @ozzyfromspace
    @ozzyfromspace 4 роки тому +5

    Great lecture! One question though: at 17:15 did you forget to divide I by L or did I miss something?

  • @niladripramanik8362
    @niladripramanik8362 3 роки тому +1

    wonderful all doubts cleared , thank you sir

  • @aaquibmomin2916
    @aaquibmomin2916 6 років тому +1

    its great sir thank you soo much for giving the most difficult topic in very easy ans fastest way.

  • @danielnewhouse5044
    @danielnewhouse5044 5 років тому

    The principle that you need that is not considered a boundary condition is that intensity in = intensity out, for a steady state solution in the presence of a perfect conductor. There are 3 corollaries that feed into it. They are deduced from the existence of the universe.

  • @treasure_moments
    @treasure_moments 5 років тому +1

    Loved the explanation !!

  • @arjunmalviya1293
    @arjunmalviya1293 4 роки тому

    Wonderful. Thanks to nptel program.

  • @ozzyfromspace
    @ozzyfromspace 4 роки тому +1

    At the beginning when you said in reality, the boundary is a really thin (nonzero) layer over which the properties e,u,sigma change from region 1 to region 2 continuously, I got the impression you could experimentally determine a continuous relation for the aforementioned material properties (eg. logistic functions over a few angstroms) and bypass the need for boundary conditions altogether. Is this valid?
    I've wanted to do E&M analysis on a system consisting of an RF cavity with a thin loop that moves in response to a resonance, and having a continuous wave function makes it easier to compute (I haven't tried it, it just sounds easier). Can you get by without boundary conditions? Many thanks.

  • @rubelchowdhury9374
    @rubelchowdhury9374 3 роки тому

    Thank you more than very much

  • @phlearninghub4782
    @phlearninghub4782 6 років тому

    Amazing...sirr..thanq..

  • @romelelectronics
    @romelelectronics 6 років тому

    Thank u sir , i need also more videos

  • @sana-ur-rahman1202
    @sana-ur-rahman1202 6 років тому

    awesome

  • @mukeshsaw9659
    @mukeshsaw9659 6 років тому

    Sir when I solve waveguide then take boundary conditions E tangential equal to zero and magnetic field normal is equal to zero why?

    • @HimanshuVerma-hi5ye
      @HimanshuVerma-hi5ye 5 років тому

      Because in WG's wall conductor both tengential and normal component of electric field are zero..Or in other words E=0 inside a conductor..

  • @vinaykushwaha5223
    @vinaykushwaha5223 4 роки тому

    4:33 those names always confuse me...now its clear.

  • @gouranganeog6035
    @gouranganeog6035 5 років тому +3

    You explain in a very complicated way and using methods different from the normal simple ones. Besides, you draw and write too small, that too leaving too little space in between. In short, you mix up everything. This is the problem with lecturers who know more. Thank God you don't teach me. I don't know how a few are liking and appreciating your lecture, still you videos are not watched by many. There are channels whose videos get much more views that yours. This is because they know how to make things easy, but you know how to make things complex. I didn't understand a single topic, nor did I have the patience to hear you out. Sorry but I feel this way.