I was converting -12 (Dec) into Binary and found a 32 bit answer. Then I took the last 8bit and converted it to decimal and the answer was 244😂. Our college book didn't cleared the concept of 1's compliment & 2's compliment. That's why that calculator operation took me in a thought loop. Then I found this video & it took me out of that loop❤. Now this concept is clear to me. Thank you❤
@13:26 the subtration of 2^8 i.e 256 and 34 should result in 222(011011110) but your subtraction gives only 196(11000100) as a result . I would like you to change it for others who can understand now better!
To represent signed Binary no. we use MSB bit to store 0 or 1. But if we want to represent an octal number say (-24)8 in signed form. Then in that case MSB will store what numbers to denote +ve and -ve numbers ? 0 & 7. I guess. Am I right?
The digital circuits and computers works on binary number system. And therefore to represent singed numbers, the MSB is used for sign representation. But for any other number system, simply one can put + or minus sign. When computer is dealing with such numbers (other than binary numbers), then first they are converted into binary. And the sign is also taken into account.
A very good video. Only 1 error. 2^8 representation in 8 bits is not possible. hence you made 9 dashes. Your 2s complement formula should be --> (2^n -1) - N +1
Why the table shown in magnitude form section has different representations.+7 - 0111 and -7 1000.Where as you explained earlier that in magnitude form we just to inverse the sign bit and copy all other bits as it is.
The table shown is for 1s complement form. The earlier representation which you are talking about is sign magnitude form. In that representation, the MSB is a sign bit. I hope, it will clear your doubt.
you said for positive number it's twos complement is it's binary form but again later u said twos complement of +32 is -32 that contradicts isn't the twos complement of +32 +32 in binary form itself
Here the earlier, I was refereeing to the representation. For positive numbers, the 2's complement representation is same as typical binary number representation. (Of course, but here the MSB is a sign bit) . But in the later case, I was referring to performing the 2s complement operation on the positive number. So, when you have a negative number let's say -32, then you can find its 2's complement representation by performing the 2's complement operation on +32. I hope, it will clear your doubt. If you still have any doubt then let me know here.
first you say -34 in binary is = 10100010 then next, you said '11011101 this represents -34 in 1s complement form' at 7:06. also , it is also called '1s complement of +34' . How can these two diff things be same ?
You mean in 2s complement addition? The carry in 2s complement addition is ignored. For more info, please check this video: ua-cam.com/video/brM0tpBAx8U/v-deo.html
The range that you are mentioning is true for 2's complement form, for 1s complement, and sign-magnitude form, the range is from, -(2^(n-1)-1) to (2^(n-1))-1
Timestamps:
0:00 Introduction
1:23 Unsigned Binary Numbers
2:12 Signed Binary Numbers
3:48 Sign Magnitude Representation
6:16 1's Complement Representation
10:08 2's Complement Representation
For notes, check this link:
www.allaboutelectronics.org/1s-complement-and-2s-complement-of-binary-numbers-signed-binary-number-representation/
Sir how can we get the 8 bit or any bit of any natural number.please sir tell quickly
Better explained than my lecturer
You've earned a new subscriber.
This channel always clear the doubts that any other can't. Thanks a lot
Yes bro so much ❤
i honestly never understood this topic until now ! Thanks so much
I was converting -12 (Dec) into Binary and found a 32 bit answer. Then I took the last 8bit and converted it to decimal and the answer was 244😂. Our college book didn't cleared the concept of 1's compliment & 2's compliment. That's why that calculator operation took me in a thought loop.
Then I found this video & it took me out of that loop❤. Now this concept is clear to me. Thank you❤
@13:26 the subtration of 2^8 i.e 256 and 34 should result in 222(011011110) but your subtraction gives only 196(11000100) as a result . I would like you to change it for others who can understand now better!
Me also having same doubt 😢
Excellent teaching style
its really sad with such content this channel is underrated
it has 500k, not that underrated...
Shortest and simplest way of teaching
thanks bro , you explain it better than my teacher
bro i have exam in 2 weeks idk anything about binary thanks to you atleast i know half adder and full adder
Great explanation! Liked it a lot...🤗🧠
Many many thanks from Bangladesh ❤️❤️this video helped me much.
Remarkable work please keep making great explanation videos.
Great job. Nice explanations and script.
Simply awesome explanation ❤️
You are more underrated than saiman says😊
In 4:23 can't understand the magnitude of 34 in 8bit 00110100
Good explanation and thank you
the best video on tthis topic
Short and clear video. I was confused with other videos and came here and it explained very well.
thank you so much
Great job.. nice explanations and script
In 13:01, (2^8 - 34) = (256 - 34) = 11011110 but in your calculation 11000100, how can it be? Can you please explain?
He made a mistake
Same question
omg well understood like never before , thank u so much
#300th like
Nice work sir
How can there be representation of decimal -8 in 2's complement when it doesn't exist in signed magnitude or even 1's complement for 4-bit binary?
Thanks you are the best
thank you sir helpful
Nicely explained!! Thanks.
Very helpfull
To represent signed Binary no. we use MSB bit to store 0 or 1.
But if we want to represent an octal number say (-24)8 in signed form. Then in that case MSB will store what numbers to denote +ve and -ve numbers ?
0 & 7. I guess. Am I right?
The digital circuits and computers works on binary number system. And therefore to represent singed numbers, the MSB is used for sign representation. But for any other number system, simply one can put + or minus sign. When computer is dealing with such numbers (other than binary numbers), then first they are converted into binary.
And the sign is also taken into account.
5:25 , the range would be { -2^(n-1)} to {2^(n-1) - 1}
I have a question though, how did you find the 2's complement form of -8 in 4bit, in the first place?
good video
A very good video. Only 1 error. 2^8 representation in 8 bits is not possible. hence you made 9 dashes. Your 2s complement formula should be --> (2^n -1) - N +1
thankyou so much sir🙏
thanks sarge
Best explanation 👍🏻
YOU ARE GENIUS 👍👍
13:24 sir please clearly explain the subtraction
I think there's some mistake 🙏
why does the 2nd and 3rd method for 2s complement of 34 produce different answers of 11011110 and 11000100?
It's amazing 😍
loved it
Why the table shown in magnitude form section has different representations.+7 - 0111 and -7 1000.Where as you explained earlier that in magnitude form we just to inverse the sign bit and copy all other bits as it is.
The table shown is for 1s complement form. The earlier representation which you are talking about is sign magnitude form. In that representation, the MSB is a sign bit. I hope, it will clear your doubt.
Please check the 3rd method,it's showing different results.
Which book is best for electrical b.sc.
Can you give the equivalent decimal value of the given 2’s Complement number (1110.1)2.
you said for positive number it's twos complement is it's binary form but again later u said twos complement of +32 is -32 that contradicts isn't the twos complement of +32 +32 in binary form itself
Here the earlier, I was refereeing to the representation. For positive numbers, the 2's complement representation is same as typical binary number representation. (Of course, but here the MSB is a sign bit) . But in the later case, I was referring to performing the 2s complement operation on the positive number. So, when you have a negative number let's say -32, then you can find its 2's complement representation by performing the 2's complement operation on +32. I hope, it will clear your doubt. If you still have any doubt then let me know here.
Do we need separate hardware when we are using 1st complimemt and 2nd complimemt encoding? Plzz guide
what is twos compliment of negative zero
first you say -34 in binary is = 10100010
then next,
you said '11011101 this represents -34 in 1s complement form' at 7:06.
also , it is also called '1s complement of +34' . How can these two diff things be same ?
Got it, basically, you see, 1s complement of a positive no. is the same as negative number representation.
ALL ABOUT ELECTRONICS
ALL ABOUT ELECTRONICS
What to do with the carry didgit in 2's complement?
You mean in 2s complement addition? The carry in 2s complement addition is ignored.
For more info, please check this video: ua-cam.com/video/brM0tpBAx8U/v-deo.html
Svp⭐️ si on’a le nombre signé suivant représenté sur 8 bits 10010111 est-ce que sa valeur en décimal sera -150 ou bien -23 ,et merci beaucoup
Isnt't there an error at 13:10 with the subtraction part?
Yes, there is a mistake in the representation . It should be 11011110.
If we have a binary signed number which is negatif in which form it could be represented ❣️
There are different ways of representation. It can be represented in either of 1s or 2s complement form.
@@ALLABOUTELECTRONICS it could be also represented by signed magnitude 💛
@@shizotaiko6137 Yes
n bit range was wrong its ; -(2^(n-1) to (2^(n-1))-1
The range that you are mentioning is true for 2's complement form, for 1s complement, and sign-magnitude form, the range is from, -(2^(n-1)-1) to (2^(n-1))-1
Sir, Please come on classification of binary codes and k-maps.
They will also be covered soon.
Okay Sir, Thank you..
Bhai -11 ka 2s complement form 11110101 hoga na ?
Yes, correct.
Thank you so s mucjni
Lol I completed this exam last week and now I am seeing something familiar
My exam is postponed due to increase in Corona cases
You don't even know how to subtract... the result is wrong here 12:57