Binomial Distribution 2: Canonical Link function

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  • Опубліковано 6 вер 2024
  • Previously, I demonstrated how to show that the binomial distribution is a member of the (natural) exponential family of distributions. This video tutorial demonstrates how to find the canonical link function of the binomial distribution.
    These short videos work through mathematical details used in the Multivariate Statistical Modelling module at UWE.

КОМЕНТАРІ • 12

  • @deetoher
    @deetoher  11 років тому +3

    You are very welcome. I mainly make these videos so that my students can use them as revision material; this is the level of detail I expect them to be able to (re)produce :)

  • @scarfacek
    @scarfacek 5 років тому

    This video is amazing. You filled in all the blanks

  • @madhukrishnann
    @madhukrishnann 2 роки тому

    So clearly explained. I am very grateful to you.

  • @voidsonvoid
    @voidsonvoid 8 років тому +1

    This was amazing. Thank you for posting.

  • @jayjayf9699
    @jayjayf9699 4 роки тому +2

    so basically the canonical link function is the link function in terms of the mean

  • @yunbowang2764
    @yunbowang2764 10 років тому +1

    This is really helpful!

  • @d1a2n3i5e8l
    @d1a2n3i5e8l Рік тому

    Thank you

  • @GiulianaVidal
    @GiulianaVidal 4 роки тому

    I need Deviance for Binomial, but i work with Brazilian books and use Y* = Yn... And will try with your notation for b(theta). Thanks

  • @muhammadshahbaz1130
    @muhammadshahbaz1130 7 років тому

    GREAT EFFORT
    THANKU

  • @jayjayf9699
    @jayjayf9699 4 роки тому

    Just came across your profile, you are a lecturer in the west of England, I am looking to do an actuary exam, do you recommend doing a MSc in Stats?

  • @1CTProj3ct5
    @1CTProj3ct5 8 років тому

    Hi there,
    Absolutely love this video! It's really helpful. Quick question though; when working out the expectation, I got
    np +log(1+e^(theta))
    Just wondering why it the answer is just np.
    Thanks in advance if you can help :D

  • @duane3000
    @duane3000 5 місяців тому

    is it not (1+theta)^-1