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I have a doubt . P ( 5 Heads | Normal Coin ) , shouldn't it be (499/500) * (1/2)^5 as By Generalised Basic Principle of COunting , P(Normal Coin) = 499/500 and then P ( 5 Heads given its a Normal Coin ) = (499/500) * (1/2)^5 ? . Btw , thanks for the intution !
Thought the exact same thing. Don't see why he has to use Bayes there. Pr(5 heads) is 0.03318 but that's with any coin, but we need Pr(5 heads with the drawn coin) which is different.
Copy my EXACT resume and cover letter, Kick start your quant applications with a 25%-DISCOUNT Summer Prep Sale using code DE29J7CY
buymeacoffee.com/myquantitative/extras
Need interview advice or want to chat? Drop me an email at myquantitative@gmail.com
Practise makes Perfect, more interview questions: ua-cam.com/play/PLaOlxMtlLosX8V6f3U_wZeMgNftNW_RYz.html
Unconventional advice aspiring Quants are not using enough! : ua-cam.com/video/BKs_1lVTNrs/v-deo.html
Nice 👍
@franklinmudole5676 Appreciate the comment Franklin! Are you currently applying for quant roles? Whereabouts are you based?
@@myquantitative currently based in Australia. Lets link up for a chat online. Intrigued to know more about your education etc.
I have a doubt . P ( 5 Heads | Normal Coin ) , shouldn't it be (499/500) * (1/2)^5 as By Generalised Basic Principle of COunting , P(Normal Coin) = 499/500 and then P ( 5 Heads given its a Normal Coin ) = (499/500) * (1/2)^5 ?
. Btw , thanks for the intution !
Thought the exact same thing. Don't see why he has to use Bayes there. Pr(5 heads) is 0.03318 but that's with any coin, but we need Pr(5 heads with the drawn coin) which is different.