Another question I have is at 20:30, when we deal with the resonance structures, do we need to consider the matter of trans or cis for the double bond? For example, the chlorine leaves and the methyl group is on the plane. But can it form a cis (Z) in the double bond? Thank you :)
For the problem with the secondary allylic and the H20 at 18:28 I'm confused as to why the whole chlorine group doesn't leave...? Wouldn't the that whole bond attached to the chlorine leave as well?
Hi Sir. Thanks for your video. I have a question at 16:50. Why do we have to draw a flipped configuration at this point? It seems that we don't need to consider stereochemistry because chlorine is on the plane :)
@@visuallearners1832 Thank you Sir!!! I think you explain a lot of important details that didn't appear in other ochem videos I've watched. Gratitude beyond words Sir!!
Both Cl and I are good leaving group. Relatively, I is a better LG then Cl. However, the driving force of this reaction is solubility. NaCl and NaBr do not dissolve in acetone, whereas NaI does.
It will eventually make a chiral center once nucleophile attack. So you should treat as such once carbocation created in order to get correct stereochemistry.
Another question I have is at 20:30, when we deal with the resonance structures, do we need to consider the matter of trans or cis for the double bond? For example, the chlorine leaves and the methyl group is on the plane. But can it form a cis (Z) in the double bond?
Thank you :)
For the 6th problem (11:50), once the Cl leaves, why can't you shift the charge over from the adjacent methyl? Is it because it's an Sn2 reaction?
Yes sn2
For the problem with the secondary allylic and the H20 at 18:28 I'm confused as to why the whole chlorine group doesn't leave...? Wouldn't the that whole bond attached to the chlorine leave as well?
It does. The remaining bond is actually methyl that was coming out of the page in the reactant. It becomes planar once carbocation is created.
@@visuallearners1832 OHHH okok I see what you mean! Thank you so much! This vid was really helpful :)
Hi Sir. Thanks for your video. I have a question at 16:50. Why do we have to draw a flipped configuration at this point? It seems that we don't need to consider stereochemistry because chlorine is on the plane :)
Since it is SN2 you will need to flip chirality. You can draw the product however you want as long as it has flipped chirality from the reactant.
@@visuallearners1832 Thank you Sir!!! I think you explain a lot of important details that didn't appear in other ochem videos I've watched. Gratitude beyond words Sir!!
Very helpful thank you soo much
Thank you so much, it helps a lot🙏
You are correct. Since it uses acetone (Aprotic) as solvent it will do SN2. So no rearrangements and carbocation formation.
Ok, amazing video by the way. EXTREMELY helpful
Thank you so much 🙏
what software do you use bro?
22:05 it's 2° right? Can we make it to be 3°??
It is secondary and benzylic. You cannot rearrange it to 3 as there is a benzene ring on the left side.
Sorry i dont understand on 11.10, where the chirality, like its attached to 2 methyl groups, its the same
Hey why is I replacing cl
Cl is a bad leaving grp right
Both Cl and I are good leaving group. Relatively, I is a better LG then Cl. However, the driving force of this reaction is solubility. NaCl and NaBr do not dissolve in acetone, whereas NaI does.
@@visuallearners1832 oh
Thank you for a very helpful video. For the very last example with SN1 reaction, how is that a chiral center after Br leaves?
It will eventually make a chiral center once nucleophile attack. So you should treat as such once carbocation created in order to get correct stereochemistry.
pls upload a pdf of thiss