A very tricky math question with factorial
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- Опубліковано 17 вер 2024
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6! = 2*3*4*5*6 = (2*4)*(3*5*6) = 8*90 =8*9*10. So 6!*7! =7!*8*9*10 = 10!. Not really very tricky
Divide both sides by 7!, so 6! = x(x-1)…etc., a product of consecutive integers, each greater than 7. Since 6! =720 and the first integer bigger than 7 is 8, we divide 720 by 8 to get 90, which immediately factors into 9 and 10, so the consecutive integers are 8,9,10 and therefore x = 10.
I would remove the words “very” and “tricky” from the title of this video.
Baby question
If you asked me to guess for the answer: 1. The answer will be bigger than 7! But less than 11! And reason is obvious 2. Half of 6 added to 7 is the number (which is 10) I will start for inspection.
Only one, really. 6!=5!•3!
Nothing tricky there: 6! = 2*3 * 5 * 2*2 * 3 * 2. Rearrange the prime factors to 5*2 * 2³ * 3² = 10 * 9 * 8. Combine that with 7! and you get 10! => x=10.
6! = 2*2*3*2*2*5*2*6 ? You mean 2*3*4*5*6, I hope.
@@henkn2 Thanks for the correction. I'll edit.
He’s taken 10 mins to go through the solution that could have taken 2 minutes.
Hi! I appreciate all the work you do especially the analysis of a problem so that at the end of your videos I can solve the problem like this one here on my own. Again thanks!
10 fx=1:for x=1 to 20:fx=fx*x:dg=1:for a=1 to 6:dg=dg*a:next a:df=dg^2*7/fx
20 df=(df-1)/df:if abs(df)
run in bbc basic sdl and hit ctrl tab to copy from the results window
التوافق والتبادل
I am watching this channel just to see how long you can take to solve look-see problems
6!*7!=10!=3628800 x=10 final answer
(6!×6!)×7=(6!)²7
=6! × 7 (1×2×3×4×5×6) = 6! × 7 × (1×2×3×2²×5×2×3)
=6! × 7 × (2⁴×3²×5)
=6! × 7 × 8 × 9 × 10
=10! (very easy question just need simple algebraic manipulation and rearrangement of terms that's all)
Took 1 minute to write and seconds to solve
I don't understand why you think that is the only one when it's easy to find others.
why is this 10 mins long
Because if it was as short as it should be, it wouldn't get much ad revenue.
Also because some people need time to grasp.
@@Thatcaffeinatedgirl Nobody needs 10 minutes to grasp that 6!=8*9*10.
6! = 1 × 2 × 3 × 4 × 5 × 6 =
= ( 2 × 4 ) × ( 3 × 5 × 6 ) =
= 8 × 90 = 8 × 9 × 10
7! × ( 8 × 9 × 10 ) = 10! = x!
x = 10
😁👍👋
6! = 2x3x5x2x2x3x2 = 8x9x10
6! x 7! = 10!
This isn't tricky. you take out 2x4 = 8 from 6! and you get 8! from the 7!. The rest is 3x5x6 = 3x30 = 90 = 9x10, so you get 10! = x!, x = 10. I didn't even need to write it down.
42 6^7 6^7^1 6^1^1 3^2^ (x ➖ 3x+2).
At 10:15, there is written that x=1*2*3...10, but actually x!=1*2*3...10. Probably it was a typo. Btw, pretty intresting task and solution.
Je partage la plupart des commentaires. Pourquoi ne pas dire simplement qu'on a déjà tous les facteurs jusqu'à 7 grâce à 7 ! Et qu'il ne nous reste plus qu'à voir si avec TOUS les facteurs de 6 !, on arrive à compléter un factoriel. On va donc essayer de trouver un facteur 8 puis 9 puis 10 etc.
On constate rapidement que 6! = 2×3×4×5×(2×3)
= (2×4)(3×3)(2×5) = 8×9×10
Donc 6!×7! = 10! donc x = 10.
Dommage, car ce tuto est clairement et proprement présenté mais une rédaction aussi lourde est à bannir. Elle donne l'impression d'un exercice très compliqué alors qu'il est plutôt simple.
10. Easy
Why a 10-minute video on something I can solve in a few seconds by simply looking at the thumbnail? Is it so that everyone actually clicks on the video to write a similar comment, therefore you earn social engagement and promotion of your channel? Is it?
10!
X=10
that was lucky
6!=1×2×3×4×5×6
7!=1×2×3×4×5×6×7
6!×7!=1×2×3×4×5×6×1×2×3×4×5×6×7
=(1×1)×2×3×4×5×6×1×2×3×(2×2)×5×(2×3)×7
=(1×1)×2×3×4×5×6×7×(2×2×2)×(3×3)×(2×5)
=1×2×3×4×5×6×7×8×9×10
=10!
As per question
X!=6!×7!
=10!
X=10
Tao valo lets say aschorjo
Sundor
Ehtesham
Now E=.4mc2
Ok
Hashim allah
Going for eh