Hi!!! for the second molecule, the third one has more charges (+1, -1 and -1) than the previous two, so does that stabilize or destabilize the molecule? I thought nature does not prefer charges..
Hey! You're exactly right! Because the third resonance form has a greater separation of charge, it will stabilize the molecule the least and so the other two resonance forms will make up the majority of the structure of the molecule.
In example 2 the middle structure why did convert the Pi bond into the sigma? Why did move the lone pair in the first structure that have the sigma bond in the first place
hey quick question. in problem one you started with oxygen as the central atom but, after drawing the resonance structure your central atom is a carbon?
AK LECTURES Hi. quick question about the first molecule. I know you previously told someone that its a carbon atom and not an oxygen but a problem still exists. The resonance form for the first molecule has a carbon atom without a complete octet, which violates the rules governing the method.
AK LECTURES can you please explain why the carbon (the resonance for the first example) can be written containing 6 electrons? doesnt the octet rule have to apply!? I'm not trying to be disrespectful! Just wandering
when trying to figure out more resonance structures, we still need to respect the maximum valence of atoms right? so for example, the neutral compound (third from the top) , are we allowed to shift a pair of electrons from the OH group AND also leave the bottom O connected via double bond? cus that would render C with 2 double bonds, and a single bond to the CH3 group, meaning carbon would have 5 of it's own electrons, wich would make it negative, but this would mean carbon just completed 5 bonds, wich should be ...impossible? since carbon cannot have more than 4 bonds.... atleast, this is what i assume
Love your channel man. You are extremely talented!
My ears validate todays lessons 👍👍
well done as nearly all of your videos.
First question has two different molecules. There is an Oxygen in place of the Carbon.... Good explanation though!
Thought the same thing, but the C just looks like an O because of the way he drew it. Look carefully and it's just an over-zealous C! :)
this might be a stupid questions, but in resonance can i move around a single electron, or do i have to always move a pair? thanks for the videos!
Is that for college?
Hi!!! for the second molecule, the third one has more charges (+1, -1 and -1) than the previous two, so does that stabilize or destabilize the molecule? I thought nature does not prefer charges..
Hey! You're exactly right! Because the third resonance form has a greater separation of charge, it will stabilize the molecule the least and so the other two resonance forms will make up the majority of the structure of the molecule.
AK LECTURES Thank you!!! I watched many videos of yours and you helped me so much! you are a life saver XD
River Zhang Thats awesome to hear! :-)
AK LECTURES, What does the actual molecule look like if it is somewhere in between the two resonance forms?
In example 2 the middle structure why did convert the Pi bond into the sigma? Why did move the lone pair in the first structure that have the sigma bond in the first place
It's OK! Thanks a lot!
hey quick question. in problem one you started with oxygen as the central atom but, after drawing the resonance structure your central atom is a carbon?
thats actually a carbon, not an oxygen. :-) sorry for being a bit sloppy.
AK LECTURES Hi. quick question about the first molecule. I know you previously told someone that its a carbon atom and not an oxygen but a problem still exists. The resonance form for the first molecule has a carbon atom without a complete octet, which violates the rules governing the method.
Isaak Sverdlov Its correct at it stands in the lecture.
AK LECTURES can you please explain why the carbon (the resonance for the first example) can be written containing 6 electrons? doesnt the octet rule have to apply!? I'm not trying to be disrespectful! Just wandering
Wondering
when trying to figure out more resonance structures, we still need to respect the maximum valence of atoms right?
so for example, the neutral compound (third from the top) , are we allowed to shift a pair of electrons from the OH group AND also leave the bottom O connected via double bond?
cus that would render C with 2 double bonds, and a single bond to the CH3 group, meaning carbon would have 5 of it's own electrons, wich would make it negative, but this would mean carbon just completed 5 bonds, wich should be ...impossible? since carbon cannot have more than 4 bonds.... atleast, this is what i assume
No. That is why we cannot use that resonance form. It simply contains a carbon with too many bonds (five as you mentioned).