Sir, please upload the rest of the course,in this pandemic situation we are completely depended on UA-cam (especially your channel). I totally understand you are doing it for free. But I hope you will upload more videos in this playlist before this semester is done. The very first video of this course is upload 10 months ago. So please look into it sir 🙏
Nice lecture sir. You have described very well. But one problem! I still have not understood the initial condition. Also, I did not get the example of torch light relating the zero initial condition. Would you mind to explain it with another very easy example?
He didn't explain this very well. I think he was saying that the torch is NOT an example of a linear system, because 1) it has a nonzero initial condition (battery charge) and 2) it is given no input, yet has an output. These are violations of the two rules he said must apply for LTI systems.
Thanks for the video, I have watched it a couple times now, at 3:33 you said the value of -1 to 1 is 1 please I am a bit confused as I assumed it will be 2 (1 - (-1) ).
We get an output(light) regardless of whether the torch is plugged in or not due to the power in the battery( initial conditions). But plugging in will give output resulting from the external source(zero state) and the battery( zero input).
no its (t-x), let x be shifted time. since we shift towards the negative time axis which is in the above case "-1"' meaning x=-1 ... therefore (t-(-1))=t+1.
Linear System: Will follow superposition Time Invariant: you will always know it because of how system parameters change, ex Aircraft mass changes in flight it is Time variant
Sir, please upload the rest of the course,in this pandemic situation we are completely depended on UA-cam (especially your channel). I totally understand you are doing it for free. But I hope you will upload more videos in this playlist before this semester is done.
The very first video of this course is upload 10 months ago. So please look into it sir 🙏
Nice lecture sir. You have described very well. But one problem! I still have not understood the initial condition. Also, I did not get the example of torch light relating the zero initial condition. Would you mind to explain it with another very easy example?
He didn't explain this very well. I think he was saying that the torch is NOT an example of a linear system, because 1) it has a nonzero initial condition (battery charge) and 2) it is given no input, yet has an output. These are violations of the two rules he said must apply for LTI systems.
When will you complete the course of control systems sir
great explanation sir
thanks Sir🙏❤
Nice lecture sir better understanding ...and also solved privious year Gate Questions sir .... related topics sir..... please..
Don’t worry about the questions, we will solve enough of them.
@@nesoacademy ok sir
@@nesoacademy how much time will u take to cover the course sir?
@@nesoacademy i mean till which month will u complete sir
@@zubair1411 noob
thank you
LTI? More like “My, oh my,” these videos are awesome!
-_-
Thanks for the video, I have watched it a couple times now, at 3:33 you said the value of -1 to 1 is 1 please I am a bit confused as I assumed it will be 2 (1 - (-1) ).
Not understood torch and battery example
We get an output(light) regardless of whether the torch is plugged in or not due to the power in the battery( initial conditions). But plugging in will give output resulting from the external source(zero state) and the battery( zero input).
Thanks for the videos.
I believe after shifting the signal to the left, we need to subtract 1 from the original signal, and not add 1 as in the video.
no its (t-x), let x be shifted time. since we shift towards the negative time axis which is in the above case "-1"' meaning x=-1 ... therefore (t-(-1))=t+1.
nice
Sir, can you please tell how you knew that you have to add those.
@Noob no1 noob
sir what do u mean if u time shift by factor 1 and how did u get it to x1*(x+1)?????????????????
we are shifting x1 by a factor of -1 so t0 = (-1), so as per formula x1 will change to x1(t-(-1)) which is nothing but x1(t+1)
Hello sir why is need the Take the initial conditions are zero for transfer function.
Please sir quick reply
In the example you showed where you analyze and shift the graph to obtain the result, is there a mathematical way of doing that as well?
How to know if a system is linear or time invariant?
Linear System: Will follow superposition
Time Invariant: you will always know it because of how system parameters change, ex Aircraft mass changes in flight it is Time variant
how many episode is estimated for control system?
7:00