YOU ARE A SAVIOR FROM GOD OH MY FREAKING GOD THANK YOU SO MUCH I KNOW YOU PROBABLY WON'T SEE THIS BECAUSE THIS IS A 2012 VIDEO BUT YOU JUST HELPED ME SO FREAKING MUCH THANKYOUTHANKYOUTHANKYOU
@4:33 if we are going to solve the 4th example in simpler method...it will be 2x+3 > x-2 Simplify: 2x-x > -2-3 = x > -5 And for me,that the final answer...
You always have constraints, its just that in some of the beginning ones, the solution was over 0 already. You can use solution sets anytime, they are just another way of expressing a solution!
+The Lone Hunt The 16 became a zero because anything with the exponent 1/2 is the equivalent of a square root of a number, therefore 16 to the power of 3/2 is equal to the square root of 16 to the power of 3. : )
YOU ARE A SAVIOR FROM GOD OH MY FREAKING GOD THANK YOU SO MUCH I KNOW YOU PROBABLY WON'T SEE THIS BECAUSE THIS IS A 2012 VIDEO BUT YOU JUST HELPED ME SO FREAKING MUCH THANKYOUTHANKYOUTHANKYOU
you was dying and logarithm saved you😂😂
the video format is perfect, looking forward to see ur other vids
Nice Explanation
Thanks and welcome
Thank you so much sir because of you I understood this concept keep the good work up all support from us.
The very first problem the solution should be 0
Trang Nguyen Exactly what I was thinking.
Shouldn’t it be 1
Nvm I figured it out xD
I was thinking that too
Yes is between 0 and 81
@4:33 if we are going to solve the 4th example in simpler method...it will be 2x+3 > x-2
Simplify:
2x-x > -2-3
= x > -5
And for me,that the final answer...
Watch the domain, though. set each inner part >0 so 2x+3>0 and x - 2>0, so x>-3/2 AND x>2. The final solution to this problem is x>2, NOT x >-5.
@@shawnpavlik1293 oohhh I forgot this lesson though heheheh..but I'll try to understand this again...Thank you also!!
Thank you very, very, very, and very much!!! I have Test tommorow and I didn't study for it. You made it looks much easier to understand.🙋🙋
How was ur exam?
your handwriting is really satisfying
Oh thanks! You are too kind :D
Superb calmly said!!
Glad to hear that yay!!!
excuse me sir, isn't the answer of number (1:28) suppose to be 0
number 1 i meant
when do you use the solution set? and when do you have to have constraints?
You always have constraints, its just that in some of the beginning ones, the solution was over 0 already. You can use solution sets anytime, they are just another way of expressing a solution!
this really helped, thank you so much!
Hello #1 should be 0
why do you enlarge the base, make log as the exponent and then cancel out both?
Oh just to illustrate the inverse cancellation relationship between exponents and logs
we need advanced level problem and solutions
can anyone tell me what's that program in which the man was writing? Thx ;)
thanks, was good lesson for me
Thank you so much
You are very welcome
thank you, very helpful
You are welcome!!!
Glad to hear that
I wish this could be unam lecturers
awesome damn Good it really helped me a lot thank you all of my doubt suddenly vanished away by watching this video
You are welcome from cali!
Thank you sooooooooooooo much that really helped!
You are very welcome
Thanks
Thanx alot sir......so easily explained....
Very nice.
THANK U SOOOOO MUCHHHH
You are welcome!
haha never mind :)
this is a really good video i was really confused before i watched it
thank you so much you explained it better this little video sir
10:20 why did you changed it to less than?
Great questions! whenever you are solving inequalities, you have to switch the sign whenever you divide by -1.
okay, its also just like changing the inequality sign to make the variable positive, right? BTW, thanks for the reply!
NYC explaination 👏👏👏
Thank you 🙂
You are welcome
if only my math teacher taught as good as you :(
couldnt hear very well but good expalining
Nice
YUNG TEACHER MONG SINABIHAN KA NA SA MAG UA-cam NALANG SA LOGARITHMIC INEQUALITIES NAYZZZZ
Raizen Zoldyck HAHAHAHAHA
Thanksss
No problem
X>1/4 supposedly
Thanks man. you realy helped me understand Logs.
Fire video
Can you add a video of solving a logarithmic inequality where the variable is in a base of a logarithm?
awesome damn Good...it..really helped me..a lot...thank..you...all of my doubt suddenly vanished away...by..watching..this..video...
Thanks
Great video, thanks!
Muaaz Khan You are very welcome we are glad that we could be of support to you
Thank you so much sir ,you help me from my report in school
awesome damn Good...it..really helped me..a lot...thank..you...😘😘all of my doubt suddenly vanished away...by..watching..this..video...
thank you
You are very welcome
I didn't understand why the 16 became a square root. Can anyone help?
+The Lone Hunt what number are you speaking of?
+The Lone Hunt The 16 became a zero because anything with the exponent 1/2 is the equivalent of a square root of a number, therefore 16 to the power of 3/2 is equal to the square root of 16 to the power of 3. : )
thanks for the video. it really helped
+Flutterscout1110 loves derpy muffins You are super welcome
Thx
Wrong! Argument of logarithm must be postitive number
The solution in #1 must be (0, 81).
You are welcome!
thanks sir u helped me a lot....
You are very welcome
Showed ur method to my teacher it doesn't work with every equation
Improve ur writing
Utkarsh Srivastava better than ur dad's handwriting...
sir do not mistake me. 4 cube is 256 not 64
Nope...4 cubed is 64. 4 to the 4th power is 256.
:) Problem solved
Thanx alot sir......so easily explained....
awesome damn Good...it..really helped me..a lot...thank..you...😘😘all of my doubt suddenly vanished away...by..watching..this..video...
awesome damn Good it really helped me a lot thank you all of my doubt suddenly vanished away by watching this video