Quantum Numbers | How to determine the quantum numbers of any element.

[@NsambaFred-wd6gp]

Good teacher may God bless you

[@jonahemmanuelofficial]

🙏🏻🙏🏻🙏🏻

[@UmarAbdulRadi-c4v]

Good job

[@jonahemmanuelofficial]

Thank you

[@DailySchool1]

Phosphorus (K)
Electron configuration : 1s2, 2s2, 2p6, 3s2, 3p6, 4s1
n= 4
For s, l= 0
When l= 0... m= 0
s= + 1/2
Therefore, we have that...
Ans= 4, 0, 0, +1/2

[@splendidforum4353]

Thank you so much prof.

[@jonahemmanuelofficial]

Always welcomed 👍

[@JehoshaphatMathias-uv1vd]

Thank you sir❤❤

[@jonahemmanuelofficial]

Always 11

[@NzubechiBlessing-ql4ng]

Thank you so much sir i always learn from your lessons 😊😊 . please sir what is the quantum number hydrogen?

[@jonahemmanuelofficial]

Great...!!!
Glad to hear

[@AliyuHassan-z3g]

Nice work Prof 👏

[@jonahemmanuelofficial]

Thank you

[@imaobongjimmy]

N= 4
L= 0
M= 0
S= +½
My answer.
Thank you so much for the knowledge you have impacted on us😊 I'm grateful.
May you continue to soar higher.

[@jonahemmanuelofficial]

Beautiful. Welldone 👍

[@PaulYakubu22]

Sir well done 👍.
But this particular video looks blurred, I don't know why??

[@jonahemmanuelofficial]

Increase the video quality from your setting

[@jonathanagele2209]

Wow, thanks so much for this lecture... And my Answer of the CONCLUDING QUESTION for the QUANTUM NUMBERS of POTASSIUM [Ar]4s¹ is (P=4, A=3, M=-3, S=½)
Please, am I correct, cuz I've never been taught this before... Just learnt it from you.
Thanks in anticipation of your response.
You have no idea how much you're helping me and how many am telling about your channel.

[@jonahemmanuelofficial]

For potassium, check again.

[@jonahemmanuelofficial]

Thank you for spreading the word.

[@NYIFEISIDORENJEH-f5t]

Greatings sir please it is very difficult for me to access the combined organic chemistry turtorail please can u help me access it

[@jonahemmanuelofficial]

@@NYIFEISIDORENJEH-f5t ?

[@NYIFEISIDORENJEH-f5t]

@@jonahemmanuelofficial please l cannot access your video on caboxyllic acid ,phenol,and many more please help me on how to access it

[@Lawrentta-i5u]

n=4, l=0,m=0,s=-1/2
Please sir is it correct
Thank you so much for imparting knowledge

[@jonahemmanuelofficial]

Welldone

[@UredoJames]

🙏

[@jonahemmanuelofficial]

👍

[@DailySchool1]

17:06 😂

[@jonahemmanuelofficial]

😂😂😂😂
Some Behind the scenes Huh?

[@UmarAbdulRadi-c4v]

Good job

[@jonahemmanuelofficial]

Thank you

[@AnthonyAyebaiduate-yk2zq]

Thank you sir ❤❤❤❤

[@jonahemmanuelofficial]

Always welcomed 👍👍

[@AnthonyAyebaiduate-yk2zq]

@@jonahemmanuelofficial
Something I was struggling with ➿
Just within a few minutes
U made me understand it
I say it again thank u sir ❤️
With this explanation I think I can tackle all questions under quantum number 😊