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Somehow weird that a « looking positive » thing turns to be negative to the power of 3
Think about (1+2i)*i and (1+2i)*i*i. Rotation is happening each time you mulply a complex number with none-zero imaginary part.
Or if you prefer...5sqrt(5)e^(3i atan2)
this is pretty complex. Pun intended.
Sir please make a video on how to find intersection coordinates of two circles.
I think i am first viewer to watch you video
Can you evaluate (1+sqrt(2)i)^3
我仅缺实力但不缺真力。面对我的挑战即成就公義！找出你们的意见相同者们来跟我对垒吧！别欺负我缺实力而无法向你们收不義而真欠公義的账。阿们！😎
x = 1+2i = √5e^(i*arctan(2))x³ = 5^(3/2) * e^(3i*arctan(2))certainly not as clean
You can expand the exponential form out and then simplify. Cos(arctan x) and sin(arctan x) should give you some closed form expressions that can then be evaluated further
@@itsphoenixingtimetrue
What?
Now solve it using radians.
Somehow weird that a « looking positive » thing turns to be negative to the power of 3
Think about (1+2i)*i and (1+2i)*i*i. Rotation is happening each time you mulply a complex number with none-zero imaginary part.
Or if you prefer...
5sqrt(5)e^(3i atan2)
this is pretty complex. Pun intended.
Sir please make a video on how to find intersection coordinates of two circles.
I think i am first viewer to watch you video
Can you evaluate (1+sqrt(2)i)^3
我仅缺实力但不缺真力。面对我的挑战即成就公義！找出你们的意见相同者们来跟我对垒吧！别欺负我缺实力而无法向你们收不義而真欠公義的账。阿们！😎
x = 1+2i = √5e^(i*arctan(2))
x³ = 5^(3/2) * e^(3i*arctan(2))
certainly not as clean
You can expand the exponential form out and then simplify. Cos(arctan x) and sin(arctan x) should give you some closed form expressions that can then be evaluated further
@@itsphoenixingtimetrue
What?
Now solve it using radians.