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How can b^(4+0) = b^4 + b^0?If you replace b^4 with a variable (say, X), then isn't that equation X = X + 1?
CORRECT SOLUTION: ua-cam.com/video/XWZYXXcIF34/v-deo.htmlThanks
Sir b^(x+y)=b^x.b^y not plus in between
That's not what the equation in the video says, but that would make more sense.
How can b^(4+0) = b^4 + b^0?
If you replace b^4 with a variable (say, X), then isn't that equation X = X + 1?
CORRECT SOLUTION: ua-cam.com/video/XWZYXXcIF34/v-deo.html
Thanks
Sir b^(x+y)=b^x.b^y not plus in between
That's not what the equation in the video says, but that would make more sense.