In the first round, Adam scooped my solution. But there is another similar way of getting 311 with those numbers: 100 x 75 = 7500 50 x 7 = 350 7500 + 350 = 7850 7850 / 25 = 314 314 - 3 = 311 And I also had these solutions: 75 x 3 = 225 225 + 100 = 325 50 / 25 = 2 7 x 2 = 14 325 - 14 = 311 100 x 7 = 700 700 - 75 - 3 = 622 50 / 25 = 2 622 / 2 = 311 You can also go into the tens of thousands by multiplying by 25 before dividing by 50, but there's no real point to it. In the second round, I saw both contestants' solutions, but also had these: 25 x 6 = 150 150 + 100 + 4 = 254 100 + 25 + 2 = 127 6 - 4 = 2 127 x 2 = 254 25 - 4 = 21 21 x 6 = 126 126 + 1 = 127 127 x 2 = 254 In the third round, I saw Rachel's solution because 100 x 25 / 3, 100 x 50 / 6, and 100 x 75 / 9 are all ways of getting to solutions in the vicinity of 833. However, there are no other solutions. In the fourth round, I saw both contestants' solutions and also had these alternatives: 100 + 25 + 5 = 130 130 - 8 = 122 122 x 5 = 610 610 + 7 = 617 100 - 25 = 75 75 x 8 = 600 600 + 7 + 5 + 5 = 617
For the first round, it looks tricky and I found one way by making 11 without 3 and 100, which is possible since 11 = 2 x 7 - 3: 50 x 7 = 350 350 - 75 = 275 275 / 25 = 11 3 x 100 = 300 300 + 11 = 311 Actually, Adam's solution is just (100 + 3) x 3 + 2 = 311. For the second round, I got the solution 254 = 127 x 2 immediately: 100 + 25 + 2 = 127 6 - 4 = 2 127 x 2 = 254 Besides, there is another simple solution: 25 x 6 = 150 150 + 100 + 4 = 254 For the third round, I think Rachel's solution is the only possible one. The last round is easy. I got the same solution as Adam's once the target was announced.
After seeing Adam's solution for the first round, I thought he could get the 821 as well, but it seems that he's just a specialist of the four-large. Here's my solution, found in time unlike Rachel ;) 50 x 100 = 5000 25 x 3 = 75 5000 - 75 = 4925 4925 + 1 = 4926 *4926 / 6 = 821*
Colin loves Countdown so much. I'm so glad he's presenting now.
Such an exciting ending. Thanks for keeping in the conundrum and contestants reflections.
75*3=225, +100=325, 50/25=2, *7=14, 325-14=311
Exactly the way I saw it.
1. 3x75+100-(7x50/25)=311
2. 6x25+100+4=254
3. (100+50)x6-(25+1)x3=822
4. 25x5x5-8=617
3:25 - Oh Rachel lol. Love this reaction.
5:58
((50x100)-(3x25)+1)/6 = 821
In the first round, Adam scooped my solution. But there is another similar way of getting 311 with those numbers:
100 x 75 = 7500
50 x 7 = 350
7500 + 350 = 7850
7850 / 25 = 314
314 - 3 = 311
And I also had these solutions:
75 x 3 = 225
225 + 100 = 325
50 / 25 = 2
7 x 2 = 14
325 - 14 = 311
100 x 7 = 700
700 - 75 - 3 = 622
50 / 25 = 2
622 / 2 = 311
You can also go into the tens of thousands by multiplying by 25 before dividing by 50, but there's no real point to it.
In the second round, I saw both contestants' solutions, but also had these:
25 x 6 = 150
150 + 100 + 4 = 254
100 + 25 + 2 = 127
6 - 4 = 2
127 x 2 = 254
25 - 4 = 21
21 x 6 = 126
126 + 1 = 127
127 x 2 = 254
In the third round, I saw Rachel's solution because 100 x 25 / 3, 100 x 50 / 6, and 100 x 75 / 9 are all ways of getting to solutions in the vicinity of 833. However, there are no other solutions.
In the fourth round, I saw both contestants' solutions and also had these alternatives:
100 + 25 + 5 = 130
130 - 8 = 122
122 x 5 = 610
610 + 7 = 617
100 - 25 = 75
75 x 8 = 600
600 + 7 + 5 + 5 = 617
For the first round, it looks tricky and I found one way by making 11 without 3 and 100, which is possible since 11 = 2 x 7 - 3:
50 x 7 = 350
350 - 75 = 275
275 / 25 = 11
3 x 100 = 300
300 + 11 = 311
Actually, Adam's solution is just (100 + 3) x 3 + 2 = 311.
For the second round, I got the solution 254 = 127 x 2 immediately:
100 + 25 + 2 = 127
6 - 4 = 2
127 x 2 = 254
Besides, there is another simple solution:
25 x 6 = 150
150 + 100 + 4 = 254
For the third round, I think Rachel's solution is the only possible one.
The last round is easy. I got the same solution as Adam's once the target was announced.
for the final round:
5/5=1
7-1=6
6*100=600
600+25-8=617
617:
100 - 25 = 75
75 * 8 = 600
5 + 5 + 7 = 17
600 + 17 = 617
5 / 5 = 1
7 - 1 = 6
6 * 100 = 600
25 - 8 = 17
600 + 17 = 617
100 + 25 = 125
8 - 5 = 3
125 - 3 = 122
122 * 5 = 610
610 + 7 = 617
254:
100 / 2 = 50 (or 25 * 2 = 50)
6 - 1 = 5
50 * 5 = 250
250 + 4 = 254
25 * 6 = 150
150 + 100 = 250
250 + 4 = 254
6 + 1 = 7
7 * 2 = 14
25 * 14 = 350
350 - 100 = 250
250 + 4 = 254
100 + 25 + 2 = 127
6 - 4 = 2
127 * 2 = 254
100 + 1 = 101
101 * 4 = 404
25 * 6 = 150
404 - 150 = 254
Shame that Richard didn't host at least 1 round of the numbers round.
Would love Richard to take over. Way better than Colin.
617
100 x 5 = 500
25 x 5 = 125
500 + 125 = 625
625 - 8 = 617
[(100 × 7) - 75 - 3] / (50 / 25) = 311
254
100 + 25 = 125
125 x 2 = 250
250 + 4 = 254
254=100+25×6+4=(100+25+2)×(6-4)
After seeing Adam's solution for the first round, I thought he could get the 821 as well, but it seems that he's just a specialist of the four-large. Here's my solution, found in time unlike Rachel ;)
50 x 100 = 5000
25 x 3 = 75
5000 - 75 = 4925
4925 + 1 = 4926
*4926 / 6 = 821*
311:
100 * 3 = 300
50 / 25 = 2
75 + 2 = 77
77 / 7 = 11
300 + 11 = 311
100 * 3 = 300
7 * 50 = 350
350 - 75 = 275
275 / 25 = 11
300 + 11 = 311
75 * 3 = 225
225 + 100 = 325
50 / 25 = 2
7 * 2 = 14
325 - 14 = 311
75 * 7 = 525
525 + 100 = 625
625 - 3 = 622
50 / 25 = 2
622 / 2 = 311
Oh no! Tom has lost!
:(