The Distributive Property with Variables in Algebra & Simplifying Expressions - [7-2-1]
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- Опубліковано 8 лис 2021
- More Lessons: www.MathAndScience.com
Twitter: / jasongibsonmath
In this lesson, you will learn how to use the distributive property and apply it to situations where variables are present in an algebraic expression. We first review the distributive property, using it to multiply the outside term into the parenthesis. After this, we learn how to identify the like terms and simplify the result. We use this very often when solving equations in Algebra.
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you explained the distributive property very well bro, great job
Appreciate it!
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I think distributive property works because the expression inside the parentheses has lower priority than outside term i.e multiplication over addition or subtraction.
Multiplication of two binomials by FOIL method infact uses distributive property.
(a+b)(a-b)=a(a-b)+b(a-b)
=a^2-ab+ab-b^2=a^2-b^2.
Interesting
Talking about 1/2, I know that 1/2 is the sin of 30 deg. said it 25 thousand times, till I know.
Sin of 30 is 1/2.
😊
8c+48
You are so smart😮you had to make math
3w-3d
(3w)-(3d)
(8c)+(48)
30-5h
3b-9
variable
(3.b)-(3.3)
10
(30)-(5h)
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cd-cf
(3.w)-(3.d)
(2.x)+(2.3)
3(b-3)
(2.2)+(2.3)
4h+28
(28)+(4h)
5(6-h)
(3b)-(9)
2x+6
(8.c)+(8.6)
-5h+30
x(y+2)
2(2+3)
2(x+3)
(2x)+(6)
(2j)+(2k)
(12)-(6)
6
(4)+(6)
3(w-d)
6(2-1)
(xy)+(2x)
(6.2)-(6.1)
8(c+6)
(x.y)+(x.2)
(cd)-(cf)
(2.j)+(2.k)
(4.7)+(4.h)
c(d-f)
28+4h
(c.d)-(c.f)
(5.6)-(5.h)
4(7+h)
z(4-j)
(z.4)-(z.j)
(4z)-(zj)
2x+xy
2(j+k)
xy+2x
2j+2k
No more clear now than in high school. It seems to presume certain prior knowledge.
Well that is definitely true. Every concept in math assumes prior knowledge. Even adding numbers together assumes prior knowledge of knowing what the number is. And I’m not trying to be snarky and being completely serious. In this case I’ve already covered the distributive property many times before using only numbers with no variables at all. I recommend watching that and then coming back to this lesson if you wish. Thanks and have a great day, jason
Seems to have no relationship to previous math@@MathAndScience I made solid grades in math until Algebra. Full stop. After day one I was lost and stayed there for three years---failing to graduate because I could not pass Algebra. None of the terms they used were familiar and seemed to have no relationship to any previous math I learned. Today it is no different. None of this makes any sense and seems to require previous knowledge from somewhere. What I do get is that what I was told is addition--is actually distribution.
How about thinking this way?
If you have some apples and you can give them all to five people evenly so that each of the five gets three apples, how many apples do you have? Well, 3×5=15.
So you have fifteen apples.
But what five? Well, the five are three boys and two girls. 3(3+2)=3×3+3×2=9+6=15
But what boys and girls?
They're Jason, Jane, John, Julia, and Jack. So, 3(Jason+Jane+John+Julia
+Jack)=Jason×3+Jane×3+John×3+
Julia×3+Jack×3=3+3+3+3+3=15 where each person represents the whole number 1.
@@soap3044 That is a good explanation, but.
It is actually 5x3
5 groups of 3
5 people with 3 apples each = 5x3=15
@@simpleman283
Thank you for the nice words.
And 3×5=5×3, of course.
This is the commutative property.
4z-zj