The optimal basis of primal consists of variables x_{1} and x_{2} The cost of these are 3 and 0 and the corresponding columns all (3, 2) ^ T and (0, - 1) ^ T then the optimal solution (y_{1}, y_{2}) of dual is: (b) (1, 0) (a) (3, 0) (c) (1, 2) (d) (0, 0)
Big thanks to you I really needed this!!!
Thank you ma'am
such a wonderful explanation.. Thank you!!!
Respected Ma'am, from where can we get these slides or notes...for revision purpose.
You can see it on my website.
@@MathPod Ma'am can you please share the link for it ..as soon as possible
@@RajveerSingh-mo7kb sites.google.com/thapar.edu/meenakshirana/home
@@MathPod Thanks a lot to you ma'am ..for your support.
very fast speed of teaching, seems just reading pages from a book.....
The optimal basis of primal consists of variables x_{1} and x_{2} The cost of these are 3 and 0 and the corresponding columns all (3, 2) ^ T and (0, - 1) ^ T then the optimal solution (y_{1}, y_{2}) of dual is: (b) (1, 0)
(a) (3, 0)
(c) (1, 2)
(d) (0, 0)
..