Ina's stream turns into a math class
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- Опубліковано 20 січ 2025
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Source : 【FFXVI】 I'll Have Uhhhhhhhhhhhhhh AN ANIME FINISH 【#7】
• 【FFXVI】 I'll Have Uhhh...
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ED Animation : • Ninomae Ina'nis Birthd...
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I can think in a fastest way to solve this problem...bring me Ollie.
Ollie would've set up a system of equations lickety split and reached the end result even faster than that.
@@DinnerForkTongue Ollie probably will solve this from gauss equation. Would you want it?
I think the implication was more that he can solve the problem visually by moving around individually detachable zombie limbs 😅
@@graywolf6441using gaussian elimination for this is like using a precision laser cut to cut your bread 😂😂😂
@@ワースト002 Solving this with Gauss was about as quick and hassle-free as using the insertion method
Student: "Why do I need to learn this?"
Teacher: "Imagine you are an idol..."
I lost it 😂😂😂😂😂
Although she got confused and did the less efficient substitution, it was otherwise a textbook solution :)
Nice rhyme
Made it about a million times harder when it had to be when simple multiplication would have gotten her to the same answer...
But her determination to take it seriously and do the damn algebra.. that's why she's our oshi.
she doing it by the book to remember the "know how", in case it's not x + y = 5 but x+ y = 343 and 2x+ 4y = 1928 then you aren't gonna spend all day to replace x and y one by one.@@alanepithet2931
Right? I first got it to x=8-2y and just plugged the rest in from there
Ina and Hololive as a whole are making me realize something: introducing a math side puzzle is a player trap. When the player (or at least a streamer) sees it, terror and brain-frying will ensue even if the puzzle is not mandatory for progress.
I love this way too much. 😂
I watch Kidnap streams for this only.
even Ollie lol
@@irkanorphyn Ollie skips the panic phase and goes straight into brain frying mode.
Somehow the older gen’s VTubers shriek in agony when I saw more simple math questions.
She could have just kept going at 2x + 20 - 4x = 16, at 4:30 mark, which will become -2x = -4, which is same as 2x = 4, or x = 2. It would've been done there, but the negative confused her for a moment and she went a roundabout way of solving for y instead... lol.
To avoid the negatives you could go:
2x + 20 -4x = 16
20 - 2x = 16
16 + 2x = 20
2x = 4
X = 2
what I thought she got x=10 at that point, and was also wondering what went wrong...
I feel Like the question is wrong. Need simpler words.
Nr. of Chocobos
5 14 18 22 26 30
4 *_12_* 16 20 24 28
3 10 *_14_* 18 22 26
2 8 12 *_16_* 20 24
1 6 10 14 *_18_* 22
1 2 3 4 5 Nr. of Antelopes
here's also a table showcasing the correlation between the Nr. of certain stock and their respective number of legs, incase anyone wanted to have a visual repesentation
(the bold & cursive numbers are all those, who's total count of stock adds up to 5)
You can either use the x or the Y to substitute into the original equation and utll work out anyway. The thing about math is one method can form muktiple ways to find an answer.
I could just hear the *Truly immense sizzling of Tako brains* as Ina relentlessly tried to figure out the math problem without giving up.
Proud of my Ina for getting the answer. 😂❤
In her defense, Tako's brain sizzling is just an everyday occurrence.
They are, after all, Ina's emergency ration. Especially when she runs out of cookies...
My God, when she suddenly began taking it so seriously because it's a book of sums I was reminded for the billionth time why she's my oshi, she's so damn cute...
> "You can solve this without algebra"
> Proceed to do algebra, but with words and not variable
lmao
your ability to use spreadsheets would put some of my students to shame, amazing work
I can smell the smoke coming out from her brain, lol. props to you, Vaan, for going the extra mile on the edits by following each of her steps, great work! thanks for the clip!
Ina derailing a stream to do a math problem is one of my favourite parts about her streams. Reminds me of the 30 min long Zelda physics question
I always got into trouble in early math classes with word problems like this because I'd just get the answer in my head without using the formulas the teachers wanted me to.
Issue is, that works for simple problems like this, but when things get harder, especially when the solutions aren’t whole numbers, you’re gonna wish you had those formulas.
Once you discount the antelope with 1 remaining leg you have 12 legs in 4 animals. And the only way to split that between 2 and 4 legs is 2 each.
Thus, 2 Chocobos.
That was how I did it.
yup that's absolutly correct no fancy pants equasions required here
Brains diff 😂
Like in games we say caryy diff and stuff. But its ina its ok
You don't even need to discount the ampulope, the only way it can work even with 16 legs is 2 chocobos and 3 antelope.
@@Elzzaw -Yeah, but 2&2 is easier to find at a glance.-
4:30 she just needed to keep going. The negatives would have cancelled out. 😿
She tried her best
I didn't watch until the end because I wanted to try out the problem myself.
So Basically you just need to hit 13, right? If we use the book's logic you can assume that aside from the one antelope that got mangled, the farmer has more than two of them as Chocobos only have 2 legs so they'll never exceed a minimum total of 6 legs.
So that would mean you need a minimum of two antelopes to reach 8 legs and 2 Chocobos to make it to 12 then add in the last antelope with the single leg to reach 13 legs.
The answer is 2 Chocobos.
EDIT: Ina got the same answer! Though, my 5th Grade Math Teacher would probably shoot me if she knew my solution lmao
Yeah you can just use logic lmao
No need to hit 13, you only care about 12. And that's between 4 animals. So, if all 4 are chocobos, then they could only reach 8 legs max. So we go from biggest fractions, i.e. antelopes. 1 is not enough, but 2 fit perfectly. Counting the one-legged antelope we ignored, that makes 3 of them. And 2 chocobos. I only spend ~1min solving this problem while watching the vod, including the time it took to verify my solution. Celes in chat figured it out pretty quickly, too.
I mean, the logical way of finding the solution is basically the same as working it out algebraically like Ina did
@@falsefingolfin yet it's way faster, as you can see. And it works via fractions, not finding two unknown variables algebraically.
@@AntonYadrov777 They are basically the same thing. Just expressed differently.
Let chocobos = x, antelopes = y.
Given total legs (ignoring the 1-legged atenlope) = 12 and x+y = 4.
If x = 4 and y = 0, total legs = 2x4 + 4x0 = 8
If x = 3 and y = 1, total legs = 2x3 + 4x1 = 10
If x = 2 and y = 2, total legs = 2x2 + 4x2 = 12
The way you did it (and described) is just brute forcing and substituting x and y with number, instead of solving the equations. It's only faster because the numbers are small and the question is easy.
Maybe unconventional, but setting up the system of equations as an augmented matrix and row-reducing also works and is pretty fast to do on paper (does the same thing as elimination, which is just more efficient than substitution in this case).
So, the system 2x + 4y = 16, x + y = 5, gives the augmented matrix,
[2 4 | 16]
[1 1 | 5]
and doing Gaussian elimination,
R_1 = R_1 / 2
[1 2 | 8]
[1 1 | 5]
R_2 = R_1 - R_2
[1 2 | 8]
[0 1 | 3]
R_1 = R_1 - R_2
[1 0 | 2]
[0 1 | 3]
Which finally just gives x=2 and y=3 from the row-reduced matrix.
I also like this method since we can know for sure that our system only has one unique solution; we can see that the non-augmented matrix is just the identity matrix, which means it is invertible and our the vectors should be linearly independent.
Love me some linear algebra ❤
How to use matrix? I don't understand.(I don't learn it yet at school)
Matrices has always been a fast way to solve equations of multiple variables
It's not unconventional either, since you will be frequently using it when dealing with large datasets or modern AI stuff
@@diniza Me neither. I am very curious to know how they work
@@Tyler-bp4md
2x + 4y = 13 legs (+ 3 eaten legs) = 16 legs originally
x + y = 5 animals
x = 5 - y
2(5 - y) + 4y = 16
10 - 2y + 4y = 16
10 + 2y = 16
2y = 6
y = 3 antelopes
X = 5 - y = 5 - 3 = 2 chocobos
That's basically what the matrix is saying
The length of this clip already fills me with dread...
Props to Ina... I think the majority of the people I know wouldn't even recognise that technique let alone be able to perform it.
If there's any criticism it is that she should have solved for what she wanted (x) rather than solving for y and then use that to work out x but that is a nitpick and she got the right result in the end so it's all good.
10 years ago,I don't understand algebra,substitution or whatever it's called.
Now,with a bachelors degree,I still don't understand.
I lost ina when she finished writing 2x+4y =16
Maybe if she'd chosen *a* and *c* for variables, it'd make more sense. It's what I did to not lose perspective.
x 2 legged chocobos plus y 4 legged antlope equals 16 legs before leg eater sustraction of 3.
Bruh, how can u get bachelors degree without basic algebra? Did your study didn't have statistics?
She's having to construct a 2x2 system of equations. Given that she can't resolve the number of each animal simply based on legs, she makes a connected equation based solely on animals: x+y=5. She must then find the solution to each variable that satisfies BOTH equations at once. There are several ways of doing this including substitution method, and elimination method.
@@TwinklesTheChinchilla Pretty much. Point being, you need at least as many equations as there are variables. Any less, and the most you can do is consider one variable a constant.
I only started watching to escape the confines of reality, not be reminded of it
As an asian, good job Ina, you've done the first question, only 39 more. Oh, rememeber, it's a 60-minute test
Ina stop my braincell hurts
At 6:45 Ina is correct that the equation is -2y+4y=6 however I am just the one being weird😔
Who knew Cloove was such a math wiz.
Either 2x+4y=16 and x+y=5 and we are searching for x
or 2x+4y=12 and x+y=4 and we are again looking for x
You can also change around the x and y so that it is 4x+2y=16 with x+y=5 and 4x+2y=12 with x+y=4 and we are looking for y.
Tako's come to Ina specifically to not use their brain.
What is this betrayal.
Since Jim from accounting died, everyone's felt the squeeze.
Wait. Jim is still dead? I thought AO-chan brought him back last week.
@@ellskilltaker1267 She did? I swear the paperwork for that did not reach the Resurrection Department's inbox.
@@DinnerForkTongue Did you eat the papers for that?
@@jordanholloman5907 No. Just the Department of Departments' cookie invoice.
Don't look at me like that, it was a hungry day!
4 marks in the bag 👏👏👏👏 We're on our way to A+ takos
I love how comment sections turn into discussions about the formulas in Math on each member
She made the incredible world of mathematics sound boring for a while there.
*_I love the kind of woman that will actually just outsmart me_*
props to editor🎉
She must be really bad at math. I'm not the best at math, but I had this figured out just after reading the sentence.
top notch editing
My first thought was just "turn one of the into the other and you're done with the calculation"...then Ina hits me that math ain't suppose to be easy most of the time lol
I just woke up my mind is not ready for this
Two minutes in i’ll do it myself for fun
Y = 4
X= 2
Y= 2X
So
13 = x+ 2x +1
So
12= 3x
3=x
Maximum there are three antelopes with one missing 3 legs and minimum there are two with one missing 3 legs
8+1 +x2= 13
X2= 4
Two chocobos and three antelopes
13=4+1+2x
8=2x
So 4 chocobos and two antelopes
Re read the question, there are five animals in total in the barn so there is two chocobos and three antelopes in the barn
Man's translated a clip into a spreadsheet, the heck.
please stop! we only have one total braincell!
when asian make a game 👍
the instant number/math show up my brain already start dead-ing
I remembered when I gotten A+ in Math in the finals before.
I don't think I'm confident in doing that again now :v
Man, I so like how you use sheets to illustrate
Thanks for the clip
can solve it via linear algebra by inverse the matrix [[2,4], [1,1]] to get [[ -0.5, 2], [0.5, 1]] then multiply by transpose of [16, 5] to get [x, y]. Since the original matrix is 2 by 2 square matrix, thus invertible. [[ -0.5, 2], [0.5, 1]] * [16, 5] get you x = 2, y = 3. plug back in original formula to check, you get 2(2) + 4(3) = 16 and (2) + (3) = 5. It's more scalable way of solving the problem as number of variable increases, it become way harder to separate the variable than just inverting the matrix. Although occasionally if the matrix is not fully rank, you might get negative number as a result. Which doesnt always make sense, since you can't really have negative number of limb in the context of this problem.
Two Chocobos in the barn.
Did it by trial and error.
FF got a nice BGM, and conbined with Ina's relaxing voice is such a chill time
I immediately thought if the right solution, but I feel she simply wanted to practice algebra classically after a while. It’s like when those Veritasium videos pop up in my recommended
I like how you pulled out an excel for this. Also to quote a chatter "what is that burnt smell"
I'm so proud of her. I'm not sure how many others would even try to solve it.
So happy to see someone else use spreadsheets as math notebook, she is so proficient in that she uses the ' automatically
She is one of my people, she has to attempt any math problem she sees, like a vampire counting salt grains.
One way to solve it is to acknowledge that 13 legs means there can be no more than 4 antelopes counting the one with one leg. Plugging in 0-3 for y and solving for x gives you cases for 4, 5, 6, and 7 animals. The 5 animal case is 3 antelopes, 2 chocobos, so the answer is 2.
The brain neurons alone could have powered her channel. So many takos brains were on overdrive helping her figure out the problem
A lot of math for a really simple solution.
There are five animals. They can either be antelopes or chocobos. Has to have 16 legs in total. 4x4 is 16, that's not five so that's not going to work. 4x3 is 12; 2x2 is 4; 4+12 is 16=16 what we're looking for. There has to be 3 antelopes and 2 chocobos in order for this to work. It mentions that the legs were cut but that doesn't matter in this math problem, that's a diversion created to stump people as the real question was "How many chocobos are in the barn" which is 2.
Another idea is to actually use the bottom piece and just get rid of the antelope all together so that you're left with 4. Then it becomes 12 legs. 3x4 is 12, we need 4 so that's not it. 2x4=8; 2x2 is 4; 4+8=12. This, again, leaves you with 2 chocobos.
>devoured three of the limbs on one of his antelopes
So we can assume there's at least 2 antelopes, who have a combined 5 legs after the leg eater had a nibble. That leaves 8 legs that can be divided over either 4 chocobos, or 1 additional antelope and 2 chocobos.
Wait, there's a HoloEN member who's actually good at math? Impossible.
my dude you gotta give us some lessons on those sexy excel skills.
I'm so proud of her man, not all en members can do that
Im glad im not the only one that is so slow at doing word problems... I guesss this is a sign to do my college algebra homework...
I still didn't knew how I passed my Algebra and Calculus class with B+ score despite having no understanding of it before and after and only during the classes that my brain somehow managed to work math
🧑: Andy, your math grade's getting better this week! Mind sharing with the class how did you manage it?
🧒: Thanks, Mr. Smith. A certain VTuber gets me interested.
Now do 2x2.
@@teilzeitberndua-cam.com/video/pjYTC2Djijw/v-deo.htmlsi=-XL3AuFt6YI8x2C2
I always thoughts in my head that is what ancient people problem, using number and letter
Ahh, this is a simultaneous equation. Classic high school level algebra.
Better call Ollie!
TIL you can put an apostrophe before some number-y text in Excel to avoid the program from treating it as an expression.
Recreational spreadsheets! Matt Parker would be so so proud.
I just started counting up from the number of antelopes.
1 antelope is 1 leg, 12 chocobo legs left. 2 antelope is 5 legs, 8 chocobo legs left. 3 antelopes is 9 legs, 4 chocobo legs left... which is 2 chocobos.
Even cavemen like me can count.
the gears in ina´s brain are turning, not fast but they turn
You could do this intuitively, which is better for people who might screw up the algebra somewhere along the way. Only go with algebra if you're used to doing flawless math, because then you can do it on auto-pilot mode and get the answer without thinking about what each step represents.
The intuitive way is to reduce possible combinations you have to try at every step. At the end of the story, there are 13 legs. There are 5 animals. One of the 5 animals is an antelope with 1 leg, because we've been told to assume this. This also means the remaining 4 animals have 12 legs in total.
So there's 4 animals with 12 legs. That means on average each animal has 3 legs, as 3x4=12. That means there's 2 animals with 2 legs and 2 animals with 4 legs in order to get an average of 3.
I'm sure this is actually designed to be one of the intended ways to think through the puzzle, because the puzzle writers chose convenient numbers for this, and probably didn't want everyone to break out their pencils to do algebra. Kids can do it without learning algebra.
my brain already starting to hurt
5 Ill animals.
13 remaining limbs.
x + y = 5
2x + (4y-3) = 13
y < 5, and unless there are zero chocobos, y < 4
That leaves 3 possible solutions that can be quickly plugged in and tested. Further algebra will also give the solution, but once you have that few testable solutions with such a simple equation, it can make just as much sense to just plug them in and test if your algebra is rusty.
Gahdamn it I opened UA-cam to escape from my maths homework and _you bring me this?!_
This does seem more complicated than it needed to be. 5 animals went in to the barn, and one of them, an antelope, had three legs eaten. The total number of remaining legs was then 13. 1 leg on the very injured antelope, and 12 for the rest of the animals. Chocobo have 2 legs, and Antelope have 4. So, 4x4 (therefor 0 chocobo) gets 16 legs (too many), 4x3+2 (1 chocobo) gets you 14 (still too many), so 4x2+4 (2 chocobo) gets you 12 and the right number of legs. So, the number of Chocobo in the barn is 2.
That's sum book you got there Priestess, if that's the power of her single brain cell, I can just imagine how her full power would be.
2 chocobo and 3 antelopes one of which lost 3 of its legs.
The numbers are small enough that the problem can be solved using logic, but I wanted to try expressing the solution mathematically so here's my attempt at doing that. I also want to account for the injured antelope all throughout the equation because I'm pretending that the variables can't be simplified using logic.
First, let's represent some variables like so:
x = total number of chocobos
y = number of antelopes (uninjured)
1 = number of antelopes (injured)
x + y + 1 = 5 = total number of animals
To find the total number of chocobos, we need to solve for the two missing variables x and y. To do that, we need to come up with two equations that include them both. The first can simply come from the total number of animals:
x + y + 1 = 5
x + y = 4
Pain tako. I guess it's been too long since the priestess has done any algebra 😂
I found a shortcut different from anything I've read in the comments so far (though not necessarily better)
The leg counts being 2 and 4 makes things really easy, since you can always just replace one antelope with two chocobo and have the same number of legs.
Start by assuming they're all antelope. 16 legs total requires four of them (with one missing three of its legs to hit 13).
Four is the wrong number of total animals, so replace one of them with two chocobos.
Now you have 3 antelopes and 2 chocobos and still 13 legs.
Five is the right number, so you're done. But if you'd needed more, you could just keep replacing one by one until you got there.
All told the whole process took me about a minute, and I needed no paper or anything.
Exact same thing I did except I started with 12 legs and substituting upwards until I hit 5 animals.
Ina was nice enough not to use her brain so as to keep the poor takos from inadvertently activating theirs. I appreciate trying to do this formally (even if she got confused at the end), but "5 animals with 16 legs between them" gives you five options (two of which you can already ignore because there has to be at least one of each) and I'm quite sure thinking about those in order takes two seconds xD
Way I did was 16 total limbs divided by number of animals (5)
So 16/5 = 3.2 which is closer to 4 than 2, which means there were more antilopes than chocobos.
We know there is at least one chocobo, but the minimum amount of antilopes you can fit in 16 limbs without overshooting is 3 (12), as 4 antilopes and 1 chocobo would overshoot, knowing that then 16-12 = 4 which divided by number of chocobo limbs is 2, so 2 chocobos and 3 antilopes.
I wish I knew what she is doing, but my two-cell brain can't handle this.
the number is small enough to compute by mentally image. 16 leg means it can't be 5 or 4 antelope, 3 antelope mean 4 leg remaining for 2 chocobo.
as a math tuition teacher, i understand the pain the write down all the steps with pc
That kinda hurt at 4:35 - she was right there and second-guessed herself.
There's only 5 animals, so just trial-and-error the 5 combinations is way faster.
Bonus points if you start with the middle combination then binary-search in the direction you want to go.
I was hovering over a hxh clip on another tap and thought the audio was on when I heard the music
She found the answer almost immediately and then kept going for some bizarre reason
she so cute, and smart :3
she passed the math
I love their add this kind side read 😂😂
Holy shit the journey.
Our lovely priestess being a massive nerd is something I didn’t expect.
A different (arguably easier) solution is to do something like a probability table. Combos of animals that equal 5. So 5 and 0 of each, 1 and 4 of each, 2 and 3 of each. Then just do arithmetic to find the one solution there must be that add up to 16 legs and has at least 1 antelope. Always fun to see how people approach solving these kinds of simple problems.
I basically got it once she did 2x+4y=16.
2 chocobos with 2 legs each plus 3 antelopes with 4 legs each.
Not the first math stream funnily enough.
Just substract the x + y = 5 from the other equation after multiplying with 4. 2x + 4y - 4(x + y) = 16 - 4*5 which is -2x = -4, so x = 2.
I remembered when she tried to calculate it, fsr I already knew the answer, cuz my teacher made it an example...
There is an efficient way to go about this kind of problem if it only has two kinds of animal:
1. Subtract the one-legged one. So the remaining are 4 animals with 12 legs.
2. Assume that all are 2 legged. This gives you 4x2=8
3. We are missing 4 legs. Replacing a Choco with a Gazelle adds 2 legs, so we have to replace 2 of them.
4. Check: 2 Chocos and 2 Gazelles = 4+8 legs = 12 legs. Plus the gnawed on Gazelle, this makes 5 animals with 13 legs. Done!
Boom, great work fellow tako
Precisely what I meant in other comments. Basic fraction-based solution, finger arithmetic.
I get what it's asking me to do. I hate how much inferring I had to do to get to that point though. It fails as a paragraph, I think.
I think everyone is failing to notice that farmer Otto counted all legs in the barn, so unless he himself is also mangled, he counted 3 chocobo's legs (6), one normal antelope's legs (4) one human's legs (2) and the poor mangled antelope leg, for a total of 6+4+2+1=13. So the true answer is 3
Thing I hate about math is not finding the answer, it’s explaining how the hell I got there.
She had everything out and over thought it.
2x+4y=16
x+y=5
(2x+4y)-(2x+2y) = 16-10
2y=6
hence
y=3
x=5-3
x=2