Championing the Rational Equation Challenge | Math Olympiad

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  • Опубліковано 18 чер 2024
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    Championing the Rational Equation Challenge | Math Olympiad
    Join us as we dive deep into the world of Olympiad mathematics, tackling the formidable challenge of rational equations head-on! In this exciting video, we'll explore winning strategies, problem-solving techniques, and expert tips to conquer Olympiad rational equation problems like a true champion. Whether you're a seasoned competitor or just starting your Olympiad journey, this is the ultimate guide to mastering rational equations and rising to the top of the leaderboard. Don't miss out on this exhilarating adventure in mathematical excellence!
    👉 Don't forget to like, subscribe, and share your thoughts in the comments below. Challenge your friends to join the equation-solving excitement!
    📚 Key Highlights:
    Step-by-step breakdown of the solution process
    Insights into the unique aspects of the rational equation
    Tips and tricks for mastering equation through exponent laws
    Application of algebraic identities and manipulations
    Timestamps:
    0:00 Introduction
    0:40 Domain
    2:20 Algebraic identities
    3:15 Exponent laws
    4:00 Substitution
    8:36 Solutions
    #matholympiad #rationalequations #problemsolving #math #mathematics #algebra #mathenthusiast #problemsolving
    We'd love to hear from you! Did you manage to solve the equation? What other math problems would you like us to cover? Let us know in the comments below!
    🎓 Happy learning, and see you in the next video! 🎉
    Thanks for Watching !!
    ‪@infyGyan‬

КОМЕНТАРІ • 4

  • @mohammedsaysrashid3587
    @mohammedsaysrashid3587 Місяць тому

    Extremely wonderful explanation....thanks sir 🙏 for sharing

  • @abcekkdo3749
    @abcekkdo3749 Місяць тому +3

    X=2i,-2i,

  • @StaR-uw3dc
    @StaR-uw3dc Місяць тому +1

    No real roots. Complex roots: x=±2i.
    Solution:
    The domain: x≠±2.
    After getting common denominator: (x-2)⁶+(x+2)⁶ = 8(x²+4)³
    (x²-4x+4)³+(x²+4x+4)³= (2x²+8)³
    We have the equation of the type: a³+b³=(a+b)³ with the solution a=0 or b=0 or a+b=0.
    The first two give the roots x=±2 which are out of domain, the third one gives the roots x = ±2i.

  • @user-kp2rd5qv8g
    @user-kp2rd5qv8g Місяць тому +2

    x cannot be +/-2. The given equation simplifies to x^6-4x^4-16x^2+64=0 > x^2=-4 > x= +/- 2i. Thus, only imaginary roots are allowed.